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Antenna design question
"Richard Harrison" wrote in message
... Mike, N3LI wrote: "Why would the velocity be less at increased (antenna element) width?" Let B = the phase velocity on the antenna element, in radians per unit length. 2pi/B = wavelength on the element. Therefore, 2pi/B=velocity of phase propagation. Due to the behavior of of open-circuited transmission lines and open-circuited antennas: B=2pif times sq.rt. of LC radians / unit length. 2 pi f / B = velocity of propagation. It is intuitive that a fat antenna element has more L & C than a thin element and thus a lower velocity of propagation. Best regards, Richard Harrisob, KB5WZI Hmmmm... my straight wire inductance equation from the ARRL handbook indicates smaller wire diameters have larger inductance. ??? 73, John |
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