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SparkyGuy wrote:
http://www.n6mrx.com/Antenna/Cubical-Quad1.htm Thanks for the link. The calculator works for me. One remaining Q: how do I take into account the "pigtails" of the driven element? A nice square loop is nice, but I've got to connect it to the (relatively) big diode, and this requires a bit more wire from the loop to the diode (on the + side of the loop) and to the meter connector (on the - side). Do I include these wire lengths in the loop size calculation? Or ignore them? Or does the 1000pF cap effectively terminate the loop (re. size)? Thanks. You MUST take into consideration every single mm of the loops length! Leads (apparently "pigtails") ARE the loop ... But, nothing stops you from being creative. The guy whos' construction(s) we are following did have about optimum parts to work with--you will just have to be "creative" ... good-luck. Warm regards, JS |
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