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#1
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![]() Owen Duffy wrote: Look up the Friis Transmission equation on Google. Here is a little application for solving the Friis Transmission equation: http://www.vk1od.net/software/fsc/ . Andy asks: The Friis equation at the above website states that the distance exponent may be a number different than "2". Can anyone here explain why a number other than "2" could be used, and under what conditions ?? Thanks, Andy W4OAH |
#2
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AndyS wrote:
Andy asks: The Friis equation at the above website states that the distance exponent may be a number different than "2". Can anyone here explain why a number other than "2" could be used, and under what conditions ?? Thanks, Andy W4OAH The exponent of 2 assumes no dissipative path loss. That is, the reduction in field strength is due solely to the power being spread out over an area which increases with distance from the source, and not to any reduction in the total power at any distance. A larger exponent would be appropriate when the path is lossy, for example when ground wave attenuation is present. A path through air could also get lossy at microwave frequencies due to water in the air in liquid or gas form, and at extremely high frequencies due to absorption by various atmospheric gases. Roy Lewallen, W7EL |
#3
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AndyS wrote in
: Owen Duffy wrote: Look up the Friis Transmission equation on Google. Here is a little application for solving the Friis Transmission equation: http://www.vk1od.net/software/fsc/ . Andy asks: The Friis equation at the above website states that the distance exponent may be a number different than "2". I don't think I say that, Friis uses an exponent of 2, but the calculator can also solve the equation with an exponent other than 2. Can anyone here explain why a number other than "2" could be used, and under what conditions ?? An example is that the FCC stipulates exponents of other than 2 for some field strength interpolation / extrapolation, up to 4 IIRC, and this is for application in real situations at closer distances than radiation far field conditions. The use of the exponent is to account for some other effects. In some cases the value of the exponent has been challenged. If I understand the case correctly, the ARRL has challenged some instances used for BPL and the court has required the FCC to scientifically substantiate its exponent, or use another which it can scientifically substantiate. The ability to specify the exponent is principally provided for peforming those interpolation / extrapolations. Owen Thanks, Andy W4OAH |
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