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#1
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Tom Donaly wrote:
You still got it wrong. It's easy to say someone is wrong - why don't you post the correct equation so we can discuss it? Whether the (kx) term is a sine or cosine is a function of where x=0. Whether the (wt) term is a sine or cosine function is arbitrary. Hecht in "Optics" uses this equation for a pure standing wave: E(x,t) = 2Eo1*sin(kx)*cos(wt) Ramo and Whinnery write it a little differently: E(z,t) = 2E+*sin(kz)*sin(wt) My definition of Eo in my previous equation is Eo = |E+|+|E-| = 2Eo1 = 2E+ E(x,t) = Eo*cos(kx)*cos(wt) I fail to see anything wrong with that equation for a pure standing wave. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
#2
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Cecil Moore wrote:
Tom Donaly wrote: You still got it wrong. It's easy to say someone is wrong - why don't you post the correct equation so we can discuss it? Whether the (kx) term is a sine or cosine is a function of where x=0. Whether the (wt) term is a sine or cosine function is arbitrary. Hecht in "Optics" uses this equation for a pure standing wave: E(x,t) = 2Eo1*sin(kx)*cos(wt) Ramo and Whinnery write it a little differently: E(z,t) = 2E+*sin(kz)*sin(wt) My definition of Eo in my previous equation is Eo = |E+|+|E-| = 2Eo1 = 2E+ E(x,t) = Eo*cos(kx)*cos(wt) I fail to see anything wrong with that equation for a pure standing wave. In the past, Cecil, I've learned that trying to discuss anything with you has been a complete waste of time. There's no discussing anything with someone who makes things up in his head, cherry picks phrases from authorities to justify his fantasies, and then doggedly keeps repeating himself - without understanding, by the way - not in an effort to promote whatever truth that may lie in his assumptions, but to always, and perpetually, and dogmatically crush all doubts about the wisdom of his assertions by other people. If you would spend anywhere near the time studying your subject as you do defending it, you might even have something intelligent to say about it, in which case, your posts might even be worth reading. In the meantime, they are mere cheap red wine: plonk. 73, Tom Donaly, KA6RUH |
#3
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Tom Donaly wrote:
plonk. Aha, one more guru who can't stand to be proved wrong. -- 73, Cecil, IEEE, OOTC, http://www.w5dxp.com |
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