Home |
Search |
Today's Posts |
#21
![]() |
|||
|
|||
![]()
Szczepan Białek wrote:
You send me to library. Try use his own words. Christofire do it (in "Spherical radiation patern"): God forbid that you should actually do some research! What a terrible thought! tom K0TAR |
#22
![]() |
|||
|
|||
![]()
On Fri, 18 Sep 2009 18:54:25 -0500, tom wrote:
Richard Clark wrote: On Fri, 18 Sep 2009 19:13:17 +0200, Szczepan Bia?ek wrote: All is exactly the same like in the fluids mechanics. "Exactly" makes it very, very easy to show how an analogy fails: Describe the laminar flow in terms of the Reynolds number for Hmm, I think I'd start with a very long K1FO yagi, say 50 elements. Maybe even extend one to 100 elements to getting very fine details. Then we look at the longitoodordinal current along the horizontal element by element. I'll have to work on it a while though. What are you thinking? I am thinking that Stefan by lacking a demonstration of this employment of his own chosen metaphor displays a vacuum in two subject areas. As it stands, he stumbles through the nuances of RF. Instead, he is trying to extrapolate them through a second subject, where, of course, he tumbles over the nuances of fluidics. The best we can expect is for him to haul a book to the nearest Xerox and lean on the copy button to produce a snow job. The deepest impression he will get of that intellectual experience is a paper cut. 73's Richard Clark, KB7QHC |
#23
![]() |
|||
|
|||
![]()
Richard Clark wrote:
What are you thinking? I am thinking that Stefan by lacking a demonstration of this employment of his own chosen metaphor displays a vacuum in two subject areas. As it stands, he stumbles through the nuances of RF. Instead, he is trying to extrapolate them through a second subject, where, of course, he tumbles over the nuances of fluidics. The best we can expect is for him to haul a book to the nearest Xerox and lean on the copy button to produce a snow job. The deepest impression he will get of that intellectual experience is a paper cut. 73's Richard Clark, KB7QHC Very perspective. tom K0TAR |
#24
![]() |
|||
|
|||
![]() "Richard Clark" wrote ... I won't wait for that obvious failure. This is several steps above your pay-grade. So, you should really attempt to work on first principles rather than rummaging in the attic for impressive artifacts of science. And what should do Richard Harrison who wrote: "At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field. " S* |
#25
![]() |
|||
|
|||
![]() "Dave" wrote ... "Szczepan Bialek" wrote in message In the Gas Analogy the monopole antena is exactly like the Kundt's tube. Heaviside did the Hydraulic Analogy. All is exactly the same like in the fluids mechanics. Next the electrons were discovered. Automatically Heaviside is a history and the Gas Analogy is in power. But you, radio people, are very close to waves and should be easy for you to work out the answer for the Question: Which Analogy is right? neither analogy is 'right'. they are useful in limited circumstances to demonstrate some basic pressure wave physics to young students. but neither one properly reproduces electromagnetic waves. "electromagnetic waves" are paper waves. Radio waves are real waves. Now we must not know what the waves are like. Now we should estabilish from which part of the radiator radiate the radio waves. Do you agree with Richard Harisson: "At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field." S* |
#26
![]() |
|||
|
|||
![]() "Cecil Moore" wrote ... Richard Fry wrote: At the top of a monopole, and at the ends of a dipole the net current is almost zero -- so those locations generate very little of the total EM radiation from these antennas. Since the forward current and reflected current are equal in magnitude and opposite in phase at the ends, they act like transmission line currents and the magnetic fields cancel at the ends. They are in phase at the feedpoint - hence the maximum radiation at that point. EM means elecro- magnetic. Radiation can start from any of them, See what Richard Harrison wrote: "At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field." S* |
#27
![]() |
|||
|
|||
![]() "tom" . net... Szczepan Białek wrote: God forbid that you should actually do some research! What a terrible thought! All necessary resarch are done by radio people. You all know how antennas work. Monopole and dipole means the electric pole because no magnetic poles. You only do not realize that EM waves can start from the ELECRIC field. The electric field is radiated from the ends where is high voltage and no current. S* |
#28
![]() |
|||
|
|||
![]()
On Sep 21, 12:23*pm, Szczepan Białek wrote:
You only do not realize that EM waves can start from the ELECRIC field. The electric field is radiated from the ends where is high voltage and no current. No, Szczepan, it is you that does not realize that voltage, alone, cannot produce an electromagnetic field. Only the change in current and charge flowing along a conductor, over time, produces far-field EM radiation. That radiation includes both the magnetic and electric fields, at right angles to each other and to the direction of travel. It is untrue that one part of a conductor or antenna radiates the magnetic field, and another part radiates the electric field, no matter the claims of the proponents of the E-H antenna (which have not been demonstrated). The fact that the ends of a dipole, and the top of a monopole have very little net current flowing means that those locations cannot contribute very much to the EM radiation from those antennas. You really should form your opinions from research in modern textbooks on antennas, rather than using Wikipedia and inapplicable analogies to sound waves. At a minimum you could recognize the quotes from them on this subject that already have been posted here. RF |
#29
![]() |
|||
|
|||
![]() "Szczepan Białek" wrote in message ... "Richard Clark" wrote ... I won't wait for that obvious failure. This is several steps above your pay-grade. So, you should really attempt to work on first principles rather than rummaging in the attic for impressive artifacts of science. And what should do Richard Harrison who wrote: "At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field. " S* What Richard wrote is correct, if written in a slightly provocative manner (deliberately?). But he wasn't stating that the electric field 'At the open-circuited ends of a resonant antenna' passes energy into a radiated radio wave. The energy that makes it that far (i.e. isn't radiated on account of current in the element) is stored temporarily in an 'electrostatic' field which is one of several 'reactive' or 'induction' field components that surround a dipole antenna and decay with distance much faster than the radiation field components (i.e. those that make up a radio wave). As I've noted before, the term 'electrostatic' should not be interpreted literally as an unchanging field - it is used to differentiate between the reactive components and the radiation components of electric field - if this offends you, just call it a 'reactive' component of electric field. This stored energy is passed back into the antenna during the following RF quarter cycle. And guess what ... one of the reactive field components is longitudinal! .... but it isn't part of a radio wave - both parts of a radio wave, the magnetic field and the attendant electric field, are directed transverse to the direction of propagation, but now I'm repeating myself from a week or more ago. Power cannot be abstracted from the reactive fields, including the longitudinal one; they affect the imaginary part of the terminal impedance of the antenna. Of course, I expect you will contradict all this but I still recommend that you read a proper account of the fields around a dipole rather than making up your own version. Since you appear to have a phobia of libraries, you could buy a second-hand copy of Kraus, Antennas for only $15 online: http://www.abebooks.com/servlet/Sear...nnas&x=55&y=10 and there are many, many other sources. Failing that, you could always search the web for a bootleg copy, or one of the MIT Radiation Laboratory series of books. I don't condone bootlegging but someone in another newsgroup recently gave a link to a collection of illegal copies and, in the hope of ending these ridiculous arguments, I'll pass on what he wrote: http://cer.ucsd.edu/~james/notes/MIT...diation%20Lab/ Chris |
#30
![]() |
|||
|
|||
![]() "Szczepan Białek" wrote in message ... "Cecil Moore" wrote ... Richard Fry wrote: At the top of a monopole, and at the ends of a dipole the net current is almost zero -- so those locations generate very little of the total EM radiation from these antennas. Since the forward current and reflected current are equal in magnitude and opposite in phase at the ends, they act like transmission line currents and the magnetic fields cancel at the ends. They are in phase at the feedpoint - hence the maximum radiation at that point. EM means elecro- magnetic. Radiation can start from any of them, See what Richard Harrison wrote: "At the open circuited ends of a resonant antenna there is almost double the forward voltage but zero total current due to cancellation of the dorward and reflected currents at the open circuit. At the open circuit in the wire, all the energy in the wave is transferred to the electric field." S* See my post earlier in this thread. You are misinterpreting what Richard Harrison wrote to suit your own, incorrect, made-up version of how antennas work. Please think on this, Szczepan Białek: the likelihood that your personal version of the physics is correct is vanishingly small - when it conflicts with the version everyone else (except perhaps Art Unwin) appears to understand from their education, which is derived from the basis for antennas that have been in use for more than 100 years. Chris |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Poynting Vector in Standing Waves | Antenna | |||
Standing morphing to travelling waves, and other stupid notions | Antenna | |||
Standing Waves (and Impedance) | Antenna | |||
Traveling Waves, Power Waves,..., Any Waves,... | Antenna | |||
Imaginary Standing Waves? | Antenna |