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#1
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![]() "Richard Fry" wrote ... On Sep 21, 12:23 pm, Szczepan Białek wrote: You only do not realize that EM waves can start from the ELECRIC field. The electric field is radiated from the ends where is high voltage and no current. No, Szczepan, it is you that does not realize that voltage, alone, cannot produce an Let us assume that electromagnetic field is a proposition by Maxwell. The electric field is more realistic. Only the change in current and charge flowing along a conductor, over time, produces far-field EM radiation. That radiation includes both the magnetic and electric fields, at right angles to each other and to the direction of travel. It is untrue that one part of a conductor or antenna radiates the magnetic field, and another part radiates the electric field, no matter the claims of the proponents of the E-H antenna (which have not been demonstrated). But it is experimentally proved. Stationary charge - electric field, Moving charge - magnetic field. Probably the both fields are the same. Only instruments are different. The fact that the ends of a dipole, and the top of a monopole have very little net current flowing means that those locations cannot contribute very much to the EM radiation from those antennas. But there are the doubled voltage. Very strong pulses must appear in space. You really should form your opinions from research in modern textbooks on antennas, rather than using Wikipedia and inapplicable analogies to sound waves. At a minimum you could recognize the quotes from them on this subject that already have been posted here. Up to now the acoustic analogy is fully applicable. S* RF |
#2
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On Sep 22, 3:34*am, Szczepan Białek wrote:
Up to now the acoustic analogy is fully applicable. Not if one understands the physics of radiation. But it is experimentally proved. Stationary charge - electric field, Moving charge - magnetic field. Untrue, and I challenge you to cite any credible experimental data that you think proves your belief. Far-field EM radiation is produced only by the current flow on the antenna, and that radiation contains BOTH the electric and the magnetic fields. You may have missed the accurate description posted by Chris, and pasted below. "The acceleration of charge in an antenna results almost entirely from the applied potential difference at its terminals. The radiated fields result from the alternating current effectively passing through the radiation resistance, and all the other, reactive, fields have no direct effect on the radiation resistance, or the component of the current that passes through it in phase with the voltage that is developed across it, which together, of course, represent the radiated power. The reactive fields affect the terminal impedance and a large imaginary part can upset the device trying to send power into the antenna, but that is more of a system issue. The alternating current that passes through the radiation resistance is composed of charge that moves in time with each RF cycle, accelerating and decelerating accordingly. The electrostatic field developed between the ends of a half-wave dipole reaches its maximum value a quarter of a cycle later than the voltage at the drive point so any effect it has on the charge in the antenna elements during each cycle must be reactive, and it doesn't affect the radiation resistance or the radiated wave." RF |
#3
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![]() "Richard Fry" wrote ... On Sep 22, 3:34 am, Szczepan Białek wrote: Up to now the acoustic analogy is fully applicable. Not if one understands the physics of radiation. Physics of radiation is unknown. Antennas are the nice apparatus to analyse it. But it is experimentally proved. Stationary charge - electric field, Moving charge - magnetic field. Untrue, and I challenge you to cite any credible experimental data that you think proves your belief. Far-field EM radiation is produced only by the current flow on the antenna, and that radiation contains BOTH the electric and the magnetic fields. For me the magnetic field is the illusion. You may have missed the accurate description posted by Chris, and pasted below. "The acceleration of charge in an antenna results almost entirely from the applied potential difference at its terminals. The radiated fields result from the alternating current effectively passing through the radiation resistance, and all the other, reactive, fields have no direct effect on the radiation resistance, or the component of the current that passes through it in phase with the voltage that is developed across it, which together, of course, represent the radiated power. The reactive fields affect the terminal impedance and a large imaginary part can upset the device trying to send power into the antenna, but that is more of a system issue. The alternating current that passes through the radiation resistance is composed of charge that moves in time with each RF cycle, accelerating and decelerating accordingly. The electrostatic field developed between the ends of a half-wave dipole reaches its maximum value a quarter of a cycle later than the voltage at the drive point so any effect it has on the charge in the antenna elements during each cycle must be reactive, and it doesn't affect the radiation resistance or the radiated wave." My description is shorter: The supply unit sends the voltage pulses (in opposite phase) in the transmissing line. If such pulses collide the voltage is doubled and the strong radiation take place. In straight radiator the forward pulse collides with the reflected. In folded dipoles with that from the other wire. S* |
#4
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On Sep 23, 5:46*am, Szczepan Białek wrote:
Physics of radiation is unknown. Perhaps to you at this point, but not to many others who read the posts here and elsewhere. RF |
#5
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Szczepan BiaĆek wrote:
Physics of radiation is unknown. Antennas are the nice apparatus to analyse it. The physics has been known for a very long time now. You are a babbling idiot. For me the magnetic field is the illusion. Any semblance to reality of your "thinking" is an illusion. snip My description is shorter: The supply unit sends the voltage pulses (in opposite phase) in the transmissing line. If such pulses collide the voltage is doubled and the strong radiation take place. In straight radiator the forward pulse collides with the reflected. In folded dipoles with that from the other wire. S* Yet more babbling nonsense of an idiot kook. Did you tire of being constantly spanked for being a babbling kook in sci.physics and decide maybe your chances of being accepted are better in an amateur group? Guess what, a lot of amateurs are engineers and actually understand the theory. Hell, even those that are not engineers obviously understand it a hell of a lot better than you do. -- Jim Pennino Remove .spam.sux to reply. |
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