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![]() "Art Unwin" wrote in message ... On Sep 21, 7:33 pm, "christofire" wrote: "Art Unwin" wrote in message ... On Sep 21, 4:19 pm, "christofire" wrote: "Art Unwin" wrote in message - - snip - - Chris you are being stupid as well as acting as a fool. Acceleration of the particle only occurs while within the electrostatic field. When it exits it has the speed of light because it has emmerged from the intersecting two fields.and thus from the accellerating forces. I remind you of Newtons law of ut + 1/2 ft sqd The first expression is for the speed attained on entering the accelerating field and the other half is for the length of the accelerating electrostatic field. On leaving the two fields it looses the applied accelerating force where it has arrived at a particular speed.Maybe you should look up the workings of a CRT using Newtons laws instead of shooting from the hip. It was at a different time that the speed of light was measured where it was found to equal the sppeed emerging from two intersecting fields. * Actually, I'm well aware of the principle involved in accelerating electrons in an electron gun as used in CRTs, klystrons, TWTs, and so on, by subjecting an electron cloud to a potential difference using an anode with a hole in it (!), but that's different from what happens in an antenna. The acceleration of charge in an antenna results almost entirely from the applied potential difference at its terminals. The radiated fields result from the alternating current effectively passing through the radiation resistance, and all the other, reactive, fields have no direct effect on the radiation resistance, or the component of the current that passes through it in phase with the voltage that is developed across it, which together, of course, represent the radiated power. The reactive fields affect the terminal impedance and a large imaginary part can upset the device trying to send power into the antenna, but that is more of a system issue. The alternating current that passes through the radiation resistance is composed of charge that moves in time with each RF cycle, accelerating and decelerating accordingly. The electrostatic field developed between the ends of a half-wave dipole reaches its maximum value a quarter of a cycle later than the voltage at the drive point so any effect it has on the charge in the antenna elements during each cycle must be reactive, and it doesn't affect the radiation resistance or the radiated wave. But all this can be looked up from any one of the respected books on antennas. Krauss, and others, gives expressions for the different field components and the theory all hangs together quite readily using Maxwell's equations without modification. I don't care if you think me stupid, and I'll continue to try to avoid name calling of individuals, although I may criticise what they write especially if it appears ignorant of proper science yet attempts to re-write established theory, and therefore appears arrogant. Chris No it does not appear in Kraus book. * That is incorrect, and I expect you know that to be the case. All of what I wrote above can be traced to sources such as Kraus, Jordan and Balmain, and Jasik; books you may never have tried to read and understand (on the basis of your comment). He never followed Maxwells laws with respect to equilibrium. * Define 'equilibrium' in trems of normal physics and cite a reference. To do that you must think in terms of wavelength. After all with respect to science all revolve around boundary laws of the Universe and you blindly ignore that fact. * How is there a boundary to the universe? It is unbounded - the universe is known to be expanding into empty space. Now back to radiation which applies spin to a p. * No it doesn't - cite a reference. Nowarticle where as with a crt no spin is applied as it is heat that separates the resting particle * ... separates it from what? Now earlier you refered to a electrostatic field that according to what you stated did not have a border and surely you know that just can't be unless it is in equilibrium which requires a closed circuit. * Fields in unbounded space tend to be unbounded. The fields around a dipole are bounded by the surface of the dipole, which is the boundary condition used by NEC, and usually in practice by the earth. For this to come to fruition you go back to the boundary laws where the arbitrary border is one that is closed i.e. in equilibrium. * Define 'equilibrium' in terms of normal physics and cite a reference. Now cast your mind back to the Gauss extension where radiators and particles lie in a closed static field. Now you should see that equilibrium must reign for a closed static field. Now you blithely mentioned an electrostatic field with nary a mention as to how it is formed and how it fits into the whole picture. * Recent discussion has been about the electric field produced by the voltage that appears between the ends of a dipole - that's what I was writing about, and so were you. How can you state 'with nary a mention as to how it is formed'? Why? Because the books do not provide an unbroken trail that fully describes radiation ( books admit that) as I have done where everything dove tails into the existing laws of the Universe. * Kraus provides a trail that's as unbroken as can be comprehended by most engineers. Physicists may wish to take it further but there's no evidence of physicists in this newsgroup. And then I gave you a bonus with respect to the weak field that Einstein searched for in vain. Einstein looked at the package presented by the Big Bag but omitted to keep that which it was wrapped into. * Is the universe enclosed in a Big Bag? That was the arbitrary boundary around which were forces or vectors that were equal and opposite when a smallest of smallest of particles edged out towards the border. Yes it was of a weak force but for all of that it broke the equilibrium boundary as the forces at that point was not now equal. The breakage was one where the opposing forces were offset to each other thus providing a torque force that provided spin. Now we come to our own Earth encased in a arbitrary border and outside the border we have the same conditions of equilibrium that must equal the forces of the Big Bang which means the outside has two vectors, gravity vector which is straight and a vector denoting spin i.e. rotation of the Earth. On the other side of the border you again have two vectors a straight vector and that curly one you don't like me to call eddy current. * Call it what you wish. Capitalising the word within a sentence, as you did before, is usually reserved for phenomena named after the people who discovered them - but that's an engineer thing. Yup. Everything falls together nicely thank you, when you study radiation from first principles instead of binding yourself to books that readily admit to not understanding the radiation process. * If you believe so fervently in your own version of all this then why don't you submit it to peer review at sci.physics or sci.physics.research? It's rather unfair to expose this only to an amateur radio newsgroup when what you are doing is apparently re-writing physics in such a major way. Those newsgroups would be more appropriate, considering the depth to which you are going (i.e. well beyond amateur radio) - wouldn't you agree. Now this is not being arrogant when one has applied all principles * My dictionary defines 'arrogant' as: 'having or showing an exaggerated opinion of one's own importance , merit, ability, etc.' from the Latin 'arrogare': 'to claim as one's own'. Your re-writing of physics conforms to this definition precisely. but I do think it is arrogant of you and others to asasinate the character of "S" purely because of his english and spelling and not to help one that wants to learn. * He is showing no inclination of wanting to learn - he asks a question, and then when answered responds with non-physical contradiction. His treatement here is a direct consequence of that behaviour, like yours. Just think about it all. I have shown how a particle moves in space in a straight line trajectory such that the particle maintains a straight line without the parabolic force of gravity driving it down to the Earth. Go back to your books and show just how the electrostatic field came about and what was the borders that it was contained in Art via applied spin and where gravity * As I say, you should present your theory to sci.physics and sci.physics.research if you have any interest in checking whether it is correct, and not limit its exposure to this group. Do let us know when you have posted there. Chris |
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