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#1
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Anyone know the velocity factor of JSC #1317 450 ohm line, 18 AWG?
Googling seems to give a variety of answers, and it's not posted at the JSC site. tnx, Bob k5qwg |
#2
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On Sun, 04 Apr 2010 12:13:22 -0500, Bob wrote:
Anyone know the velocity factor of JSC #1317 450 ohm line, 18 AWG? Hi Bob, If you were to find a specification, it stands every chance of being wrong. How much wrong is wholly dependant on your need for accuracy. The answer to your question can only be effectively found at the bench through measurements. Various reports from different reporters will reveal a range of values because test conditions are also very important and their variety give considerable sway. Some variation is simply due to poor measurement technique. Some variation is a function of production variation. Weather will contribute a significant variation - more for ribbon line than open line. At the end of the day, you can take an average of all such reports and simply buy into the proposition that you have to tolerate a certain level of indeterminacy. If you application demands precise accuracy, then you might find you will never achieve it. 73's Richard Clark, KB7QHC |
#3
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Bob Inscribed thus:
Anyone know the velocity factor of JSC #1317 450 ohm line, 18 AWG? Googling seems to give a variety of answers, and it's not posted at the JSC site. tnx, Bob k5qwg You could get a sample and measure it ! -- Best Regards: Baron. |
#4
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On Sun, 04 Apr 2010 20:38:35 +0100, Baron
wrote: Bob Inscribed thus: Anyone know the velocity factor of JSC #1317 450 ohm line, 18 AWG? Googling seems to give a variety of answers, and it's not posted at the JSC site. tnx, Bob k5qwg You could get a sample and measure it ! Well, I discarded that idea because I have no idea how. But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. Bob k5qwg |
#5
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Bob wrote:
On Sun, 04 Apr 2010 20:38:35 +0100, Baron wrote: You could get a sample and measure it ! Well, I discarded that idea because I have no idea how. But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. Bob k5qwg Unfortunately, it's not really simple to make measurements with symmetrical line. You'll be exciting a common mode current which will travel with a different velocity factor and affect the measurement. I suggest making an approximate measurement, then doing final adjustments of the MFJ kept as far as possible from conductive objects including yourself. You'll have to adjust it, let go, back off and read the meter, readjust, etc. And then it'll still be a bit off unless the length of the MFJ meter is quite short relative to a wavelength. You'll also have to keep the line well away from any conductors and avoid coiling it. Of course, the same problems will exist when you install the line in whatever system it'll be used for, unless you can get it very well balanced. It'll be a good exercise in learning some basic measurement techniques. Whether your results are adequately accurate depends on the application you'll be using the line for. I sometimes taught a class on TDR techniques, and I'd start by connecting a foot or so of two-conductor ribbon cable -- just soldered into and to the shell of an SMA connector -- to a high speed TDR. The trace would show the large reflection from the open end, of course, but a smaller reflection seemingly coming from a point about 1/4 of the way from the end. I explained that ribbon cable isn't controlled for impedance, so it obviously had a construction anomaly at that point, and pinched the line, running my fingers along until the reflection from the fingers was at the same point as the anomaly. Then I cut the line well toward the TDR unit, discarding the portion with the anomaly. When the audience saw the *new* reflection about 1/4 of the way from the end of the shorter wire, I had their attention. And thus began a discussion of differential and common mode waves. Roy Lewallen, W7EL |
#6
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Roy Lewallen Inscribed thus:
Bob wrote: On Sun, 04 Apr 2010 20:38:35 +0100, Baron wrote: You could get a sample and measure it ! Well, I discarded that idea because I have no idea how. But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. Bob k5qwg Unfortunately, it's not really simple to make measurements with symmetrical line. You'll be exciting a common mode current which will travel with a different velocity factor and affect the measurement. Roy Lewallen, W7EL Please could you elaborate on how and why a common mode current has a different VF on a balanced line. -- Best Regards: Baron. |
#7
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Baron wrote:
Please could you elaborate on how and why a common mode current has a different VF on a balanced line. Sure. First, a balanced line, whether it's twinlead or coax, doesn't have any common mode current, by definition -- the lack of common mode is what makes it balanced. We're talking about a physically symmetrical line. Whenever you have a two conductor line, you effectively have two transmission lines, differential mode and common mode. Although you actually have only one current on each conductor, by taking advantage of the principle of superposition you can mathematically separate the two currents into two *sets* or components of currents, analyze their effects separately to gain a better understanding, and simply add the results if you want to know the overall solution. The sum of the common mode and differential currents are the actual conductor currents, and the sum of the common mode and differential responses is the actual response. The differential or transmission line mode waves (voltage and current) are the components which are equal and opposite on the two conductors, so the field is strongest between the two conductors, fringing outward in the case of ladder line. The presence of the dielectric material in a major portion of the field slows down the waves, lowering the velocity factor. In the case of coax, the field is entirely within the dielectric so we can easily calculate the velocity factor if we know the dielectric constant of the material. In the case of ladder line, we don't know what fraction of the field is in the air and what's in the dielectric without a very advanced computer program, so we have to measure the velocity factor. The fraction and therefore velocity factor changes, by the way, with frequency, a phenomenon known as dispersion. The common or antenna mode waves are the components that are equal and in the same direction or polarity on the two conductors. The field is the same as it would be if the two conductors were connected together to make a single conductor. One conductor of the common mode transmission line is the two conductors of the ladder line, and the other is the Earth and/or surrounding conductors. These two common mode transmission line conductors are usually much farther apart than the ladder line conductors, so the common mode characteristic impedance is higher than the differential mode impedance. The velocity factor is usually higher, too, because the field is between the two common mode conductors -- the ladder line and the Earth --, and almost none of it is in the line dielectric. So its velocity factor is nearly 1. In my TDR demonstration, the common mode open end reflection occurred before the larger differential mode reflection because of the higher velocity factor, so it looked like a differential mode reflection from a point short of the end. (And I helped reinforce this mistake in order to get the audience's attention.) Any two conductor line supports both modes and behave the same, but coax is a little easier to understand because the differential and common mode currents are actually physically separate -- so no mathematical hocus-pocus is necessary. The differential currents and waves are entirely inside the cable, and the common mode currents and waves are outside. The velocity factor inside (differential mode) is determined by the dielectric material, and the velocity factor of the outside (common mode) is nearly 1. Roy Lewallen, W7EL |
#8
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Baron wrote:
Roy Lewallen Inscribed thus: Bob wrote: On Sun, 04 Apr 2010 20:38:35 +0100, Baron wrote: You could get a sample and measure it ! Well, I discarded that idea because I have no idea how. But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. Bob k5qwg Unfortunately, it's not really simple to make measurements with symmetrical line. You'll be exciting a common mode current which will travel with a different velocity factor and affect the measurement. Roy Lewallen, W7EL Please could you elaborate on how and why a common mode current has a different VF on a balanced line. I'll take a shot.. The VF, to a first order, depends on the dielectric constant (permittivity) of the medium separating the conductors of the transmission line. (more correctly, the medium containing the electric and magnetic fields) For differential mode, it's the insulation between the wires (for window line, a value somewhere between that of the plastic and that of air)... For common mode, it's more the two wires acting as one conductor against the surroundings (e.g. earth) as the other conductor. The permittivity of that tends to be lower than that of the medium between the wires, so the velocity factor is "faster" for the common mode than the differential mode. It's not quite that simple, of course, because the field surrounds the conductors in all directions, not just conveniently between them. Another way to look at it is think of a balanced pair with distributed L and C suspended above a ground plane. The C (per unit length) between the pair is different than the C to ground, as is the L, for the common mode vs differential mode. |
#9
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Bob wrote in
: .... But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. As Roy has explained, you need to stop common mode current from significantly altering your measurement. I have had sucess with placing a balun of a string of ferrite cores over the line. It is easy to observe the effectiveness using a VNA sweep, a bit tricker with the MFJ269. I have also found that stretching the line out straight causes the worst common mode problems, but if you coil it, you have to keep adjacent turns much further apart than the line's conductor separation. All this has to be done with the line suspended in the air, well clear of other dielectrics or conductors. (Hint: fishing line can be your friend!) Before these analysers, we measured the resonant frequency of a line section using a GDO. By very loosely coupling the GDO, and reading the GDO frequency from a calibrated receiver, good results could be obtained. Owen |
#10
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On Tue, 06 Apr 2010 00:16:56 GMT, Owen Duffy wrote:
Bob wrote in : ... But then, on a hunch, I checked the manual that came with my MFJ-269, and sure enough, on page 34, it tells how to measure Velocity Factor, utilizing the distance to fault mode. It'll take a day or so to recharge the 269's batteries, and then I'll have at it. As Roy has explained, you need to stop common mode current from significantly altering your measurement. I have had sucess with placing a balun of a string of ferrite cores over the line. It is easy to observe the effectiveness using a VNA sweep, a bit tricker with the MFJ269. I do have a W2DU-style balun of ferrite beads on coax, if that is what you mean. I also have an MFJ gizmo, a tiny 1:1 current balun for antenna analyzers, a coax fitting on one side, and balanced line fasteners on the other side -- but I'm guessing then I'd be measuring the velocity factor of the balun, in addition to the balanced line. Bob k5qwg I have also found that stretching the line out straight causes the worst common mode problems, but if you coil it, you have to keep adjacent turns much further apart than the line's conductor separation. All this has to be done with the line suspended in the air, well clear of other dielectrics or conductors. (Hint: fishing line can be your friend!) Before these analysers, we measured the resonant frequency of a line section using a GDO. By very loosely coupling the GDO, and reading the GDO frequency from a calibrated receiver, good results could be obtained. Owen |
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