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#1
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"Sven Lundbech" wrote in
k: .... As mentioned earlier, most of the stuff is old hat to me - but I really look forward to dig into the chapters concerning tx output impedance. A highly controversial subject for decades. Here is a simple little test for the hypothesis that Zs=50+j0 that uses equipment found in many if not most HF ham shacks. Owen |
#2
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Owen Duffy wrote in news:Xns9D81BC11E3183nonenowhere@
61.9.191.5: "Sven Lundbech" wrote in k: ... As mentioned earlier, most of the stuff is old hat to me - but I really look forward to dig into the chapters concerning tx output impedance. A highly controversial subject for decades. Here is a simple little test for the hypothesis that Zs=50+j0 that uses equipment found in many if not most HF ham shacks. Oh, the URL: http://vk1od.net/blog/?p=1028 . Owen |
#3
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On May 23, 4:31*am, Owen Duffy wrote:
Owen Duffy wrote in news:Xns9D81BC11E3183nonenowhere@ 61.9.191.5: "Sven Lundbech" wrote in . dk: ... As mentioned earlier, most of the stuff is old hat to me - but I really look forward to dig into the chapters concerning tx output impedance. A highly controversial subject for decades. Here is a simple little test for the hypothesis that Zs=50+j0 that uses equipment found in many if not most HF ham shacks. Oh, the URL:http://vk1od.net/blog/?p=1028. Owen While the analysis of transmitter output impedance in Reflections is flawed, experiments (claimed to be repeatable) described in Reflections appear to support the conclusions of the flawed analysis. It would be highly valuable if the results of these experiments could be explained in a manner that aligns with established understandings. Such an explanation might start by describing the circuit conditions that result from following the manufacturer’s tuning procedures. After all, these usually depend on measuring currents and voltages so are only indirectly related to power. Perhaps the resulting conditions are not as they are usually assumed to be. Try as I might, I have not been able to derive a mechanism to explain the observations in Reflections. But the explanations offered in Reflections require large chunks of linear circuit theory to be discarded, so this does not seem to be an appropriate path. ....Keith |
#4
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On May 24, 6:30*am, Keith Dysart wrote:
Such an explanation might start by describing the circuit conditions that result from following the manufacturer’s tuning procedures. On an old tube transmitter, e.g. a Globe Scout, when the manufacturer specifed a particular grid current and a particular plate current, does that imply a particular single resistive load line for the final tube? Why were those particular grid and load currents chosen? Maximum efficiency? Tube life? Minimum distortion? -- TNX & 73, Cecil, w5dxp.com |
#5
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On May 24, 9:23*am, Cecil Moore wrote:
On May 24, 6:30*am, Keith Dysart wrote: Such an explanation might start by describing the circuit conditions that result from following the manufacturer’s tuning procedures. On an old tube transmitter, e.g. a Globe Scout, when the manufacturer specifed a particular grid current and a particular plate current, does that imply a particular single resistive load line for the final tube? Why were those particular grid and load currents chosen? Maximum efficiency? Tube life? Minimum distortion? Excellent questions. I have often wondered if the manufacturer's tuning procedures had anything to do with maximizing output power transfer, or were they, in fact, optimizing some other aspect. ....Keith |
#6
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On Mon, 24 May 2010 07:06:44 -0700 (PDT), Keith Dysart
wrote: I have often wondered if the manufacturer's tuning procedures had anything to do with maximizing output power transfer, or were they, in fact, optimizing some other aspect. This resolves quickly in measurement - no need to wonder unless it offers some secondary benefit of not measuring things. An alternative is to simply examine conventional design considerations. One can add to Plate current by throwing a lot of power into the grid. More plate current yields more output power results, but grid lifetime plumments. One can do innumerable things to force an artificial outcome that strains to prove a distorted logic. Examining a suite of sources, in initial conditions that are average for their application quickly reveals a common design paradigm. ****** The fundamental answer to your question is the manufacturer ultimately designs for market domination, or maximum investment return (the two don't necessarily converge). Thus the marketplace gives us a spectrum of choice and the norm of the distribution reveals cautious design that has its eye on a value exchange expressed in money. THAT is the only optimization you can expect = in an honest barter, you get what you pay for. 73's Richard Clark, KB7QHC |
#7
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On May 24, 6:58*pm, Richard Clark wrote:
On Mon, 24 May 2010 07:06:44 -0700 (PDT), Keith Dysart wrote: I have often wondered if the manufacturer's tuning procedures had anything to do with maximizing output power transfer, or were they, in fact, optimizing some other aspect. This resolves quickly in measurement - no need to wonder unless it offers some secondary benefit of not measuring things. * An alternative is to simply examine conventional design considerations. *One can add to Plate current by throwing a lot of power into the grid. *More plate current yields more output power results, but grid lifetime plumments. One can do innumerable things to force an artificial outcome that strains to prove a distorted logic. *Examining a suite of sources, in initial conditions that are average for their application quickly reveals a common design paradigm. ****** The fundamental answer to your question is the manufacturer ultimately designs for market domination, or maximum investment return (the two don't necessarily converge). *Thus the marketplace gives us a spectrum of choice and the norm of the distribution reveals cautious design that has its eye on a value exchange expressed in money. *THAT is the only optimization you can expect = in an honest barter, you get what you pay for. 73's Richard Clark, KB7QHC You have gone to a bit higher level than I intended with my question and I agree with you conclusions at that level. But my question was more basic. When designing the filter for a PA, among other things, one uses the desired load to be applied to the tube and the disired load impedance to be supported and selects filter components to perform the desired transformation. When operating the radio, the operator has meters that measure some values, some knobs that control some component values and a procedure for adjusting these knobs. It is not at all obvious what exactly the result of performing the procedure is. Does it result in the same load being applied to the tube that was computed by the designer? There are some hints that the procedure will result in the load applied to the tube being real, but beyond that, what exactly are the circuit conditions that result? ....Keith |
#8
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On May 24, 7:30*am, Keith Dysart wrote:
On May 23, 4:31*am, Owen Duffy wrote: Owen Duffy wrote in news:Xns9D81BC11E3183nonenowhere@ 61.9.191.5: "Sven Lundbech" wrote in . dk: ... As mentioned earlier, most of the stuff is old hat to me - but I really look forward to dig into the chapters concerning tx output impedance. A highly controversial subject for decades. Here is a simple little test for the hypothesis that Zs=50+j0 that uses equipment found in many if not most HF ham shacks. Oh, the URL:http://vk1od.net/blog/?p=1028. Owen While the analysis of transmitter output impedance in Reflections is flawed, experiments (claimed to be repeatable) described in Reflections appear to support the conclusions of the flawed analysis. It would be highly valuable if the results of these experiments could be explained in a manner that aligns with established understandings. Such an explanation might start by describing the circuit conditions that result from following the manufacturer’s tuning procedures. After all, these usually depend on measuring currents and voltages so are only indirectly related to power. Perhaps the resulting conditions are not as they are usually assumed to be. Try as I might, I have not been able to derive a mechanism to explain the observations in Reflections. But the explanations offered in Reflections require large chunks of linear circuit theory to be discarded, so this does not seem to be an appropriate path. ...Keith Keith, would you please elaborate on why you believe my analysis of transmitter output impedance is flawed? And what is the basis for your belief that my explanations in Reflections require large chunks of linear circuit theory to be discarded. Could it be because you consider the source resistance in the transmitter to be dissipative, as in the classical generator? If so, you must be made to realize that the source resistance of the transmitter is non-dissipative, which is the reason that its efficiency can exceed 50%. Or are you considering the output characteristic of the transmitter to be non-linear? This is not the case, because the effect of energy storage in the tank circuit isolates the non-linear input from the output circuit, which is linear as evidenced by the almost perfect sine wave appearing at the output of the tank. One last question: Are you basing your dissatisfaction of Reflections from reviewing the 2nd or 3rd edition? Chapter 19 has been expanded in the 3rd edition, in which I presented additional proof of my position on the subject that you should be aware of. If you haven't yet seen the addition that appears in the 3rd ed, please let me know so that I can send you a copy of the addition. Also include your email address so I can send it. Keith, you are the only person I know of who appears to have found flaws in my presentation on this subject. Which is why I'm anxious to know exactly why you believe my presentation is flawed. Walt Maxwell, W2DU |
#9
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On May 24, 10:55*am, walt wrote:
Keith, would you please elaborate on why you believe my analysis of transmitter output impedance is flawed? And what is the basis for your belief that my explanations in Reflections require large chunks of linear circuit theory to be discarded. Could it be because you consider the source resistance in the transmitter to be dissipative, as in the classical generator? If so, you must be made to realize that the source resistance of the transmitter is non-dissipative, which is the reason that its efficiency can exceed 50%. No problems there. There has been much confusion in this area and anything that reduces this confusion is beneficial. Or are you considering the output characteristic of the transmitter to be non-linear? This is not the case, because the effect of energy storage in the tank circuit isolates the non-linear input from the output circuit, which is linear as evidenced by the almost perfect sine wave appearing at the output of the tank. This may be the root of my disagreement. Certainly the output can be an arbitrarily perfect sine wave, but this simply depends on the characteristics of the filter and not on whether the system is linear. But the way the filter transforms the impedances is the crux of the issue. It is my understanding that the input impedance to a filter can be computed by starting with the load impedance applied to the filter and then, using the rules for series and parallel connected components, compute the way through the filter until reaching the input and the result is the input impedance to the filter. Similarly, the output impedance of the filter can be computed by starting with source impedance driving the filter, series and paralleling the components until reaching the output and the result is the output impedance of the filter. The desired impedance for the input to the filter is that impedance which produces the desired load on the tube. And the component values are computed to produce this load on the tube when the correct load is attached to the output. For the output impedance of the filter, the question then becomes: What is the source impedance driving the filter? If the source is constructed as a Class A amplifier, then it depends on the controlling device, and for the simplest of circuits would be Rp of the tube. (Just for clarity, in this discussion Rp is the slope of the plate E/I curve with constant grid voltage. In an ideal tube, these lines are equidistant apart and the slopes are the same. Real tubes, of course, are not so well behaved, but this should not affect the basic discussion.) Since the component values for the filter were chosen to provide the optimum load to the tube, and the optimum load value has no relation to Rp, there is no reason to expect the filter will transform Rp to be the conjugate of the load impedance. For amplifiers where conduction is not for 360 degrees (Class AB, B, C), the controlling device is no longer time-invariant so the rules for linear circuit analysis no longer apply. None-the-less, for example, consider a Class AB amplifier where the tube is only cut off for 1 degree. This short cut-off would not have much affect so the analysis for Class A would apply. As the cut-off period increases the behaviour will diverge more and more from that of the Class A amplifier. Simulations produce some interesting results: Another way of measuring the source impedance is to observe the effect on a reflected wave entering the amplifier from the load. With a Class C amplifier, simulation reveals that the effect on the reflected wave depends on the phase of that wave with respect to the drive signal applied to the tube. As the phase of the reflected wave is changed, the reflection co-efficient experienced by the wave changes. Truly a non-linear behaviour. Intriguingly, when the conduction angle is exactly 180 degrees, this effect largely disappears, and the result is much as if the source impedance of the tube was 2 times Rp, which seems to make some sense since the tube is only conducting one-half of the time. One last question: Are you basing your dissatisfaction of Reflections from reviewing the 2nd or 3rd edition? Chapter 19 has been expanded in the 3rd edition, in which I presented additional proof of my position on the subject that you should be aware of. If you haven't yet seen the addition that appears in the 3rd ed, please let me know so that I can send you a copy of the addition. I have been reading the .pdfs at w2du.com along with correspondence and other writings in QST, QEX and newsgroups. The expanded Chapter 19 at w2du.com offers more experimental evidence that seems to support the hypothesis that the transmitter is conjugate matched to the load after tuning, But given, from circuit analysis, that the output impedance can not be well defined for any but a Class A amplifier, the fascinating question is why is there experimental evidence that agrees with the premise that the output impedance of a tuned transmitter is the conjugate match of the load? One simple example to consider which has similar behaviour is a bench power supply that also has a constant current limiter. Set such a power supply to produce a voltage of 100V (more precisely a maximum voltage) and a current limit of 2A. Apply a variable load. Maximum power will be drawn when the load resistance is 50 ohms. Varying the resistance on either side of 50 ohms will reduce the power which might be misconstrued to suggest that the power supply has an output impedance of 50 ohms, when, in fact, it has a infinite output impedance when the load is below 50 ohms and a zero output impedance when the load is above. I have looked for such a simple explanation in the circuits of the transmitters used in the experiments but was not able to find one. So I am still puzzled by the observations. Also include your email address so I can send it. Keith.dot.dysart.at.gmail.com .dot. = . .at. = @ …Keith |
#10
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On May 24, 6:15*pm, Keith Dysart wrote:
This may be the root of my disagreement. Certainly the output can be an arbitrarily perfect sine wave, but this simply depends on the characteristics of the filter and not on whether the system is linear. Since anything except a class-A amplifier is non-linear and since we are talking about linear analysis, it seems we need to locate a point in the system where V is a sine wave, I is a sine wave, and V/I is the constant impedance at that point. IMO, that is the first point at which we can use a linear math analysis and maybe that point is what Walt is talking about. It's certainly not going to be the plate of a class-C amplifier and it may not even be the load-line of the class-C amplifier. There is probably some point in an otherwise non-linear system where a linear analysis becomes possible. I think that point is what Walt considers to be the linear source point, wherever that point might be located. In fact, here is my personal take on the subject. Given an antenna system that presents 50+j0 ohms looking into 50 ohm coax, the internal impedance of the source doesn't matter. For any voltage source, irrespective of the source impedance, if reflected energy doesn't reach the source, the source impedance doesn't matter (except for efficiency). Seems to me, the highest efficiency would be achieved by a source with zero ohms of source impedance. -- 73, Cecil, w5dxp.com |
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