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#1
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On Jun 29, 11:44*am, "Szczepan Bialek" wrote:
You should decide: EM or electrons. The mixture is fun. That's an interesting idea to which I don't know the answer. Let me rephrase the question: Although it is known that electrons cannot flow through the dielectric of an ideal capacitor, how about photons? Can RF photons flow directly through the dielectric layer of a capacitor? If they can, it would explain a lot of things. -- 73, Cecil, w5dxp.com |
#2
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Cecil Moore wrote:
On Jun 29, 11:44 am, "Szczepan Bialek" wrote: You should decide: EM or electrons. The mixture is fun. That's an interesting idea to which I don't know the answer. Let me rephrase the question: Although it is known that electrons cannot flow through the dielectric of an ideal capacitor, how about photons? Can RF photons flow directly through the dielectric layer of a capacitor? If they can, it would explain a lot of things. -- 73, Cecil, w5dxp.com photons can flow through a dielectric.. isn't that what EM propagation is, after all? |
#3
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On Jun 29, 12:54*pm, Jim Lux wrote:
photons can flow through a dielectric.. isn't that what EM propagation is, after all? Yes, after I posted it, I realized that it was a rhetorical question. -- 73, Cecil, w5dxp.com |
#4
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On 29 jun, 15:08, Cecil Moore wrote:
On Jun 29, 12:54*pm, Jim Lux wrote: photons can flow through a dielectric.. isn't that what EM propagation is, after all? Yes, after I posted it, I realized that it was a rhetorical question. -- 73, Cecil, w5dxp.com Dear friends, I follow with interest your interesting digressions, however in various different posts about differents matters, I notice discussion arises about what is "real" and what is not. IMO that contributes to the solution goes away from us (I remember making this comment in a previous post). In this sense respecto to energy I would like to quote a great physics: "...there is a certain quantity, which we call energy, that does not change in the manifold changes which nature undergoes. That is a most abstract idea, because it is a mathematical principle; it says that there is a numerical quantity which does not change when something happens. It is not a description of a mechanism, or anything concrete; it is just a strange fact that we can calculate some number and when we finish watching nature go through her tricks and calculate the number again, it is the same." "It is important to realize that in physics today, we have no knowledge of what energy is. We do not have a picture that energy comes in little blobs of a definite amount. It is not that way. However, there are formulas for calculating some numerical quantity, and when we add it all together it gives "28"'— always the same number. It is an abstract thing in that it does not tell us the mechanism or the reasons for the various formulas." From: Richard Feynman. "Six easy pieces" Miguel LU6ETJ |
#5
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On 29 jun, 20:57, lu6etj wrote:
On 29 jun, 15:08, Cecil Moore wrote: On Jun 29, 12:54*pm, Jim Lux wrote: photons can flow through a dielectric.. isn't that what EM propagation is, after all? Yes, after I posted it, I realized that it was a rhetorical question. -- 73, Cecil, w5dxp.com Dear friends, I follow with interest your interesting digressions, however in various different posts about differents matters, I notice discussion arises about what is "real" and what is not. IMO that contributes to the solution goes away from us (I remember making this comment in a previous post). In this sense respecto to energy I would like to quote a great physics: "...there is a certain quantity, which we call energy, that does not change in the manifold changes which nature undergoes. That is a most abstract idea, because it is a mathematical principle; it says that there is a numerical quantity which does not change when something happens. It is not a description of a mechanism, or anything concrete; it is just a strange fact that we can calculate some number and when we finish watching nature go through her tricks and calculate the number again, it is the same." "It is important to realize that in physics today, we have no knowledge of what energy is. We do not have a picture that energy comes in little blobs of a definite amount. It is not that way. However, there are formulas for calculating some numerical quantity, and when we add it all together it gives "28"'— always the same number. It is an abstract thing in that it does not tell us the mechanism or the reasons for the various formulas." From: Richard Feynman. "Six easy pieces" Miguel LU6ETJ Sorry, I forget to made clear that my comment not reference Cecil recent post mentioning "real power" in mathematical sense, referencing complex numbers. :) Miguel |
#6
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On 29 jun, 15:08, Cecil Moore wrote:
On Jun 29, 12:54*pm, Jim Lux wrote: photons can flow through a dielectric.. isn't that what EM propagation is, after all? Yes, after I posted it, I realized that it was a rhetorical question. -- 73, Cecil, w5dxp.com I learnt displacement current inside a condenser it was = eo* d(phi E)/ dt no EM radiation inside the condenser to made that current possible, in any case EM radiation in physical condenser will come out from condenser to the rest of the universe :). I also learnt photons was necessary to explain certain energy interchange phenomena such as fotoelectric effect or subatomic particle interactions, wave-particle duality for me means "duality", not "wave kaput" :) to account for EM wave well explainable phenomenom. As it was taught to me (I am not physicist), quantum nature of a 80 m wavelenght energy it is useless for calculations and invisible to our instrument resolution because its immensely large quantic number. Is it wrong? Miguel LU6ETJ |
#7
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On Jun 29, 8:41*pm, lu6etj wrote:
I learnt displacement current inside a condenser it was = eo* d(phi E)/ dt no EM radiation inside the condenser to made that current possible, in any case EM radiation in physical condenser will come out from condenser to the rest of the universe :). It depends on your definition of "radiation". In an ideal transmission line, energy is not lost to radiation but photons (EM fields and waves) necessarily exist all up and down the line. In an ideal coaxial transmission line, the photons (EM fields and waves) are confined to the dielectric. Electrons cannot travel at the speed of light. EM waves travel at the speed of light. Therefore EM waves are photons. Given the physical nature of a capacitor, refraction would be the primary mechanism for losing energy to radiation and there's probably very, very little refraction in the capacitor dielectric. If electrons are being acelerated and decelerated in the capacitor, photons will be emitted. It seems obvious now that when electrons are decelerated on one capacitor plate, photons are emitted that propogate across the capacitor dielectric and are absorbed by electrons on the opposite plate. When the concept of displacement current was invented, nobody knew that RF fields were actually made up of particles (photons) but now we do know. Displacement current seems only to be EM radiation from one capacitor plate to the other. As it was taught to me (I am not physicist), quantum nature of a 80 m wavelenght energy it is useless for calculations and invisible to our instrument resolution because its immensely large quantic number. Is it wrong? The quantized nature of a single RF photon is no longer open to argument and the energy in that single photon can be calculated, (h*f), where h is Planck's constant, 6.626 x 10^-34 J*s. Whether there are any instruments sensitive enough to detect a single 80m photon is a moot point that does not change the nature of RF fields and waves. What is important is that it is impossible to radiate a signal level less than (h*f). If anyone asserts that RF fields and waves can violate the laws of physics regarding photons, that person is wrong and delusional. (Light left over from the time when the universe became transparent is today red-shifted down to RF microwave frequencies and called background radiation.) -- 73, Cecil, w5dxp.com |
#8
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On Tue, 29 Jun 2010 18:41:52 -0700 (PDT), lu6etj
wrote: As it was taught to me (I am not physicist), quantum nature of a 80 m wavelenght energy it is useless for calculations and invisible to our instrument resolution because its immensely large quantic number. Is it wrong? Yes. We experience 80M activity every day irrespective of it being Newtonian or Quantum. All it reveals is that something with a very, very, very low energy is still quite measurable. However, you "can" deliberately choose the wrong instrument to measure the energy. That instrument reveals more about the choice-maker than the energy. For instance, a 1KW 80M energy source presents a near 0 degree absolute temperature. A fever thermometer is not going to register that energy. 73's Richard Clark, KB7QHC |
#9
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On 30 jun, 16:00, Richard Clark wrote:
On Tue, 29 Jun 2010 18:41:52 -0700 (PDT), lu6etj wrote: As it was taught to me (I am not physicist), quantum nature of a 80 m wavelenght energy it is useless for calculations and invisible to our instrument resolution because its immensely large quantic number. Is it wrong? Yes. We experience 80M activity every day irrespective of it being Newtonian or Quantum. *All it reveals is that something with a very, very, very low energy is still quite measurable. * However, you "can" deliberately choose the wrong instrument to measure the energy. *That instrument reveals more about the choice-maker than the energy. For instance, a 1KW 80M energy source presents a near 0 degree absolute temperature. *A fever thermometer is not going to register that energy. 73's Richard Clark, KB7QHC Dear Richard: What I said is what my physics book says, I swear there no creation of mine... :) (I have not any authority on this matter). I was thinking in quantic number describing the energy of a typical 100 W 80 m oscillator devolped in one second, representing a quantic number n = 4.3 * 10^28; we know our quanta represents the minimun possible energy of a 80 m radiation AND the minimun "delta" Energy possible for a given oscillator, energy difference between (among?) one quanta an two quanta of 80 m radiation is 2.3 * 10^ -27 J, that difference (my physic book say) it is unmeasurable experimentally (this energy leap (skip?, hop?) it is in the order of 10^-8 smaller that green light leap (in reality my book -Resnick Halliday- give a moving dust particle example with quantic number very much lower than my 80 m example yet = n = 3 * 10^14, they said "we can not distiguish energy difference among n = 3 * 10^14 and n = [3 * 10^14] +1") What it is the ohysical sense of working with magnitudes we can not measure? Nobody (as we know) use (or need) quantum mechanics to deal with (or explain) locomotive movement :) Cecil said "electrons can not travel at light speed, photon yes therefore EM waves are photons", well... EM CAN travel at light speed, then photons are EM waves ![]() ![]() behave as waves and vice versa) have not dead yet (or he died and I found out?). Cecil said: "When the concept of displacement current was invented, nobody knew that RF fields were actually made up of particles (photons) but now we do know". Cecil seem to me as Zarathustra has declared: "ˇWave is dead!" :) Yes, yes, I know some people bring very strange ideas into the forums, but I think it is not necessary argue them with exotic others -even if they are true- because the partner will double the bet and will bring other even more bizarre yet...! :) Well, dont be bothered by my comments, I am joking a little... 73 - Miguel - LU6ETJ |
#10
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On Wed, 30 Jun 2010 14:02:14 -0700 (PDT), lu6etj
wrote: I was thinking in quantic number describing the energy of a typical 100 W 80 m oscillator devolped in one second, Hi Miguel, Power? Energy? One second? Choose one to talk about, and perhaps the mystery of numbers might clear up. one quanta an two quanta Quanta? Two Quanta? We are now up to four intermixed terms. Simplify. Choose one thing. of 80 m radiation is 2.3 * 10^ -27 J, that difference (my physic book say) it is unmeasurable experimentally (this energy leap (skip?, hop?) it is in the order of 10^-8 smaller that green light leap True, but immaterial. You are confusing wavelength and quanta (no surprise given the blearing of topic). Compare Green and IR. Is there a correlation on a scale of two that predicts out to a scale of 10^8? Compare Green and deep IR. Is there a correlation on a scale of ten that predicts out to a scale of 10^8? Compare Green and the Sub-millimeter band. Is there a correlation on a scale of 100 that predicts out to a scale of 10^8? (in reality my book -Resnick Halliday- give a moving dust particle example with quantic number very much lower than my 80 m example yet = n = 3 * 10^14, they said "we can not distiguish energy difference among n = 3 * 10^14 and n = [3 * 10^14] +1") So a quantum of smaller energy of a dust particle is measureable but 80M transmission is not? Common sense is wheezing in this dust. OK, so they are talking about the difference in quantum, not energy. Would it surprise you that you cannot even tell the difference between one quanta of green light and two with conventional detecting technology? What it is the ohysical sense of working with magnitudes we can not measure? Nobody (as we know) use (or need) quantum mechanics to deal with (or explain) locomotive movement :) The limitation is called Quatum Efficiency and the human eye is vastly superior (to all but $1,000,000 components) at rougly QE = 50%. Cecil said Cecil said Yes, yes, I know some people bring very strange ideas into the forums, Indeed. 73's Richard Clark, KB7QHC |
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