Home |
Search |
Today's Posts |
#131
|
|||
|
|||
what happens to reflected energy ?
On Jun 24, 8:59*pm, Keith Dysart wrote:
But then what explains the reflection at the generator that presents Z0 to the line? Your error is in assuming it is a reflection. It is NOT a reflection which, by definition, involves one wave. It is a redistribution of energy due to superposition which, by definition, involves two or more waves. In a system designed to eliminate reflections at the source, ALL of the redistribution of reflected energy back toward the load is due to superposition accompanied by interference. From the FSU web site: "... when two waves of equal amplitude and wavelength that are 180- degrees ... out of phase with each other meet, they are not actually annihilated, ... All of the ... energy present in these waves must somehow be recovered or redistributed in a new direction, according to the law of energy conservation ..." Nothing said about *reflection* (involving a single wave). It is all about the meeting (superposition) of two waves which can cause the redistribution of energy. It may look somewhat like a reflection but it is technically NOT a reflection. -- 73, Cecil, w5dxp.com |
#132
|
|||
|
|||
what happens to reflected energy ?
On Jun 25, 2:13*am, lu6etj wrote:
In a TL, instead, total destructive interference in one point would mean energy stop flowing from that point forwards (is it OK say "forwards"?) and reverse its flow direction doubling his value, is it OK?. In our ham transmission line systems, the goal is to accomplish total destructive interference toward the source, i.e. zero reflected energy incident upon the source. So let's talk about destructive interference toward the source and constructive interference toward the load. You name it "redistribution" too, not reflection. By definition, reflection is something that happens to a single wave. By definition, superposition involves two or more waves. The redistribution that I am talking about can include both reflection and superposition if both are present. Depending upon the system configuration, both may be present, both may be absent, or one exist without the other. Well, my question was how we can set (devise) an experiment to get such behaviour in a TL? I've presented it before and it is a simple Z0-match involving a 1/4WL matching section. 50w-----50 ohm------+------1/4WL 300 ohm------1800 ohm load On the source side, rho at '+' is 0.7143 Using a TDR, we can verify that there is indeed a reflection from the 50/300 ohm impedance discontinuity. What happens to that reflection during steady-state? What happens to Vfor1(rho) = 50v(0.7143) = 35.7v? What happens to Pfor1(rho^2) = 50w(0.51) = 25.5w? -- 73, Cecil, w5dxp.com |
#133
|
|||
|
|||
what happens to reflected energy ?
"Cecil Moore" wrote ... On Jun 24, 8:59 pm, Keith Dysart wrote: But then what explains the reflection at the generator that presents Z0 to the line? Your error is in assuming it is a reflection. It is NOT a reflection which, by definition, involves one wave. It is a redistribution of energy due to superposition which, by definition, involves two or more waves. In a system designed to eliminate reflections at the source, ALL of the redistribution of reflected energy back toward the load is due to superposition accompanied by interference. From the FSU web site: "... when two waves of equal amplitude and wavelength that are 180- degrees ... out of phase with each other meet, they are not actually annihilated, ... All of the ... energy present in these waves must somehow be recovered or redistributed in a new direction, according to the law of energy conservation ..." Nothing said about *reflection* (involving a single wave). It is all about the meeting (superposition) of two waves which can cause the redistribution of energy. It may look somewhat like a reflection but it is technically NOT a reflection. In the Hertz dipole the reflection take place but in the loop antenna "two waves of equal amplitude and wavelength that are 180-degrees ... out of phase with each other meet," But the both cases are the same. At the meeting the energy is radiated and the electrons emitted because in the meeting place the voltage is doubled. The electronic circuit theory do not use EM. S*. |
#134
|
|||
|
|||
what happens to reflected energy ?
On 25 jun, 08:30, K1TTT wrote:
On Jun 25, 7:46*am, lu6etj wrote: On 24 jun, 17:54, K1TTT wrote: On Jun 24, 3:25*pm, Cecil Moore wrote: On Jun 24, 9:20*am, lu6etj wrote: Oh, I'm so sorry Cecil, I should have written "However I can not visualize a simple PHYSICAL mechanism/example to generate such system in a TL". Anyway, your additional info it is very useful to me. Thanks. The physical mechanism is the Z01==Z02 impedance discontinuity with its associated reflection coefficient, rho. We can see that reflection on a TDR so it is indeed a PHYSICAL mechanism. -- 73, Cecil, w5dxp.com don't forget the OTHER physical mechanism that is necessary, superposition... the ability to add voltages, currents, and fields in linear circuits and media. I mentioned same comment in another post. We use superposition principle in two different contexts. Superposition theorem in circuit theory, and wave superposition. Wave (traveling) superposition deals with f(t,x,y,z) and usually with puntual magnitudes, E, H, D, B, etc) while circuit theory deals with a subset f(t) phenomena and with integrated magnitudes (V, I). Sometimes that becomes a confused issue Miguel NO, superposition is always the same. *it is the linear addition of currents or fields in a linear media. *it works the same for circuits as for em waves. the big problem are the people who confuse the formulas for adding powers with adding fields or currents/voltages and forget the phase terms. the other big problem is keith who seems to want to separate his waves into separate time and space variables and leaves out the requirement that wave functions must be dependent on both space AND time. basically any solution to the wave equations derived from maxwell's laws must be of the form f(t-x/v). *this leads him to the erroneous conclusions he gets from trying to compare his batteries to wave propagation. *this is the same problem people have with standing waves, they have separate dependence on t and x, so they can't travel and can't transport energy.- Ocultar texto de la cita - - Mostrar texto de la cita - NO, superposition is always the same I did not say that things were fundamentally different, I said "context" it is different, as "substraction" in mathematics, you can not subtract a natural number bigger from a smaller one in natural field, but you can do it in integer field, we have to apply (comply?) contextual rules with such operations. Otherwise I agree with what you say. 73 |
#135
|
|||
|
|||
what happens to reflected energy ?
On 25 jun, 10:00, Cecil Moore wrote:
On Jun 25, 2:13*am, lu6etj wrote: In a TL, instead, total destructive interference in one point would mean energy stop flowing from that point forwards (is it OK say "forwards"?) and reverse its flow direction doubling his value, is it OK?. In our ham transmission line systems, the goal is to accomplish total destructive interference toward the source, i.e. zero reflected energy incident upon the source. So let's talk about destructive interference toward the source and constructive interference toward the load. You name it "redistribution" too, not reflection. By definition, reflection is something that happens to a single wave. By definition, superposition involves two or more waves. The redistribution that I am talking about can include both reflection and superposition if both are present. Depending upon the system configuration, both may be present, both may be absent, or one exist without the other. Well, my question was how we can set (devise) an experiment to get such behaviour in a TL? I've presented it before and it is a simple Z0-match involving a 1/4WL matching section. 50w-----50 ohm------+------1/4WL 300 ohm------1800 ohm load On the source side, rho at '+' is 0.7143 Using a TDR, we can verify that there is indeed a reflection from the 50/300 ohm impedance discontinuity. What happens to that reflection during steady-state? What happens to Vfor1(rho) = 50v(0.7143) = 35.7v? What happens to Pfor1(rho^2) = 50w(0.51) = 25.5w? -- 73, Cecil, w5dxp.com Sorry. Cecil, I do not catch you (final numeric example), would you mind give to me a more explanatory/explicit answer? (the rest OK). 73 Miguel |
#136
|
|||
|
|||
what happens to reflected energy ?
On Jun 25, 8:24*am, Cecil Moore wrote:
On Jun 24, 8:58*pm, Keith Dysart wrote: Still does not explain why you choose only the positive root. Of course it does. In the power density equation, choosing the negative root would lead to a violation of the conservation of energy principle. When one of the roots is obviously impossible in reality, a rational person chooses the other root. You might study why the real power folk prefer three phase to single. It all has to do with instantaneous power. I am a "real power folk", Keith. My first EE degree was in power generation and transmission. Three-phase puts less stress on the system by eliminating the hills and valleys in the energy flow common with traveling waves. That's the time domain. Variation in the instantaneous energy flow. Not quite 'as useless as tits on a boar hog, or as Hecht said, putting it mildly: "of limited utility"'. ....Keith |
#137
|
|||
|
|||
what happens to reflected energy ?
On Jun 25, 9:00*am, Cecil Moore wrote:
On Jun 25, 2:13*am, lu6etj wrote: In a TL, instead, total destructive interference in one point would mean energy stop flowing from that point forwards (is it OK say "forwards"?) and reverse its flow direction doubling his value, is it OK?. In our ham transmission line systems, the goal is to accomplish total destructive interference toward the source, i.e. zero reflected energy incident upon the source. So let's talk about destructive interference toward the source and constructive interference toward the load. You name it "redistribution" too, not reflection. By definition, reflection is something that happens to a single wave. By definition, superposition involves two or more waves. The redistribution that I am talking about can include both reflection and superposition if both are present. Depending upon the system configuration, both may be present, both may be absent, or one exist without the other. Well, my question was how we can set (devise) an experiment to get such behaviour in a TL? I've presented it before and it is a simple Z0-match involving a 1/4WL matching section. 50w-----50 ohm------+------1/4WL 300 ohm------1800 ohm load On the source side, rho at '+' is 0.7143 Using a TDR, we can verify that there is indeed a reflection from the 50/300 ohm impedance discontinuity. What happens to that reflection during steady-state? What happens to Vfor1(rho) = 50v(0.7143) = 35.7v? Using superposition, when you add Vrev2(tau) to Vfor1(rho) you get zero. With zero voltage comes 0 energy transfer. For further learning, do not just examine steady state, but also examine how it gets to steady state. Using a lattice diagram, examine what happens as the first reflection and then each re-reflection arrives at '+'. Determine how Vrev2(tau) slowly builds to equal Vrev1 and cancels it, using the simple addition of superposition. While this process is occurring, there is a Vrev1 which decreases after each round trip in the second line section. This is all done with simple addition. No need for products and square roots. For further marks, decide whether you should think of Vrev2 as an infinite sum of reverse waves or is it okay to think of it as one sum that slowly accumulates. Which is it really? Same question for Vfor2. What happens to Pfor1(rho^2) = 50w(0.51) = 25.5w? Once you have computed total Vrev1 using simple superposition, it is easy to compute that the "reverse power", Prev1, is 0. Do you really need rho^2 to understand what goes on in a transmission line? ....Keith |
#138
|
|||
|
|||
what happens to reflected energy ?
On Jun 25, 7:30*am, K1TTT wrote:
On Jun 25, 7:46*am, lu6etj wrote: On 24 jun, 17:54, K1TTT wrote: On Jun 24, 3:25*pm, Cecil Moore wrote: On Jun 24, 9:20*am, lu6etj wrote: Oh, I'm so sorry Cecil, I should have written "However I can not visualize a simple PHYSICAL mechanism/example to generate such system in a TL". Anyway, your additional info it is very useful to me. Thanks. The physical mechanism is the Z01==Z02 impedance discontinuity with its associated reflection coefficient, rho. We can see that reflection on a TDR so it is indeed a PHYSICAL mechanism. -- 73, Cecil, w5dxp.com don't forget the OTHER physical mechanism that is necessary, superposition... the ability to add voltages, currents, and fields in linear circuits and media. I mentioned same comment in another post. We use superposition principle in two different contexts. Superposition theorem in circuit theory, and wave superposition. Wave (traveling) superposition deals with f(t,x,y,z) and usually with puntual magnitudes, E, H, D, B, etc) while circuit theory deals with a subset f(t) phenomena and with integrated magnitudes (V, I). Sometimes that becomes a confused issue Miguel NO, superposition is always the same. *it is the linear addition of currents or fields in a linear media. *it works the same for circuits as for em waves. the big problem are the people who confuse the formulas for adding powers with adding fields or currents/voltages and forget the phase terms. the other big problem is keith who seems to want to separate his waves into separate time and space variables and leaves out the requirement that wave functions must be dependent on both space AND time. basically any solution to the wave equations derived from maxwell's laws must be of the form f(t-x/v). *this leads him to the erroneous conclusions he gets from trying to compare his batteries to wave propagation. *this is the same problem people have with standing waves, they have separate dependence on t and x, so they can't travel and can't transport energy.- Hide quoted text - I see that the stress induced by considering DC waves is causing you to misinterpret my writings. May I suggest an alternate exploration for you. Assuming that you accept TDR and know how to use Reflection Coefficients to compute voltage and current reflections, then consider what happens when a rectangular pulse is launched from a matched generator in to a transmission line. For simple reflection coefficients like 0, 1, and -1 compute the reflected pulse. For both the forward and reflected direction compute the voltage and current on the line before the pulse arrives, as it passes and after it has passed. Compute the energy in the pulse, and how long a distance it occupies on the transmission line. Compute the power as the pulse is passing. Be sure you know what happens to the pulse when it re-enters the generator. For simplicity, assume a generator constructed using the Thevenin circuit. Make sure all the results are in agreement; especially, the energy delived by the source and the energy dissipated in the various resistors. Now make the pulse longer and longer... until it looks like a step function. And do the computations again. Determine if the results agree with those I previously presented for the DC example. ....Keith PS: Barring errors, they will. |
#139
|
|||
|
|||
what happens to reflected energy ?
On Jun 26, 12:22*am, Keith Dysart wrote:
On Jun 25, 7:30*am, K1TTT wrote: On Jun 25, 7:46*am, lu6etj wrote: On 24 jun, 17:54, K1TTT wrote: On Jun 24, 3:25*pm, Cecil Moore wrote: On Jun 24, 9:20*am, lu6etj wrote: Oh, I'm so sorry Cecil, I should have written "However I can not visualize a simple PHYSICAL mechanism/example to generate such system in a TL". Anyway, your additional info it is very useful to me. Thanks. The physical mechanism is the Z01==Z02 impedance discontinuity with its associated reflection coefficient, rho. We can see that reflection on a TDR so it is indeed a PHYSICAL mechanism. -- 73, Cecil, w5dxp.com don't forget the OTHER physical mechanism that is necessary, superposition... the ability to add voltages, currents, and fields in linear circuits and media. I mentioned same comment in another post. We use superposition principle in two different contexts. Superposition theorem in circuit theory, and wave superposition. Wave (traveling) superposition deals with f(t,x,y,z) and usually with puntual magnitudes, E, H, D, B, etc) while circuit theory deals with a subset f(t) phenomena and with integrated magnitudes (V, I). Sometimes that becomes a confused issue Miguel NO, superposition is always the same. *it is the linear addition of currents or fields in a linear media. *it works the same for circuits as for em waves. the big problem are the people who confuse the formulas for adding powers with adding fields or currents/voltages and forget the phase terms. the other big problem is keith who seems to want to separate his waves into separate time and space variables and leaves out the requirement that wave functions must be dependent on both space AND time. basically any solution to the wave equations derived from maxwell's laws must be of the form f(t-x/v). *this leads him to the erroneous conclusions he gets from trying to compare his batteries to wave propagation. *this is the same problem people have with standing waves, they have separate dependence on t and x, so they can't travel and can't transport energy.- Hide quoted text - I see that the stress induced by considering DC waves is causing you to misinterpret my writings. May I suggest an alternate exploration for you. Assuming that you accept TDR and know how to use Reflection Coefficients to compute voltage and current reflections, then consider what happens when a rectangular pulse is launched from a matched generator in to a transmission line. For simple reflection coefficients like 0, 1, and -1 compute the reflected pulse. For both the forward and reflected direction compute the voltage and current on the line before the pulse arrives, as it passes and after it has passed. Compute the energy in the pulse, and how long a distance it occupies on the transmission line. Compute the power as the pulse is passing. Be sure you know what happens to the pulse when it re-enters the generator. For simplicity, assume a generator constructed using the Thevenin circuit. Make sure all the results are in agreement; especially, the energy delived by the source and the energy dissipated in the various resistors. Now make the pulse longer and longer... until it looks like a step function. And do the computations again. Determine if the results agree with those I previously presented for the DC example. ...Keith PS: Barring errors, they will. why would i want to do all that work? there is no way that my answers will agree with your misconceptions. you'll just come up with an even uglier generator to try to make it fit. oh, and by the way, your fancy 2 generator and 2 resistor 'constant power' source isn't what you think it is. go back to basic circuits 101 and you will find that any linear network like that can be reduced to either a simple one source one impedance norton or thevenin equivalent. in your example it is identical to a 50v voltage source in series with a 50ohm resistor... deriving the norton equivalent is left for the student. |
#140
|
|||
|
|||
what happens to reflected energy ?
On Jun 25, 4:00*pm, Keith Dysart wrote:
That's the time domain. Variation in the instantaneous energy flow. What you seem to be missing is that the *energy content* of power (total joules) must be conserved but the instantaneous power (joules/ second) does not have to be conserved as you have argued numerous times in numerous examples. The only question that needs to be answered is: In a system designed to eliminate reflections and interference, does all the reflected energy eventually get dissipated in the source resistor. The answer is yes because there is nowhere else for it to go. There is no conservation of power principle and that includes instantaneous power. So it is irrelevant what/where instantaneous power might do/go during a single cycle. Now I understand that instantaneous power dictates some physical design considerations as in waveguides. But since instantaneous power does not fall under the conservation of energy principle, it is simply irrelevant to the present discussion. What happens over a complete cycle is what is relevant. However, in any and every case, it is energy that is conserved, not power. How many joules are in that dt sliver of time when the instantaneous power is 100 watts? It's those joules that must be conserved, not the instantaneous power. You didn't answer my previous question. If you measure 100 watts of instantaneous power at 100 places within an inch of each other, does that mean there is 10000 watts of instantaneous power in that one inch of wire? That is the only logical conclusion based on your argument and assertions. Any argument based on the conservation of power is doomed to fail. Please get real. Not quite 'as useless as tits on a boar hog, or as Hecht said, putting it mildly: "of limited utility"'. One could argue that tits on a boar hog are not completely useless and, therefore, instantaneous energy is exactly as useless (or exactly as useful) as tits on a boar hog. (Hint: Without the existence of the tit gene in the male, female hogs would probably not have tits.) -- 73, Cecil, w5dxp.com |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
Reflected Energy | Antenna | |||
Reflected power ? | Antenna |