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On Jun 13, 11:12*am, Richard Clark wrote:
From Mendenhall: ... Would you please respond in your own words directly to my previous statement (repeated below)? If you believe by your understanding of the clips you quoted from Mendenhall that a conventional, single vacuum tube Class C r-f amplifier provides a functional termination of 50+j0 ohms for energy applied to the output connector of the transmitter, THEN PLEASE EXPLAIN WHY THAT TERMINATION ALLOWS SUCH SIGNALS TO REACH THE PLATE OF THE PA TUBE -- whose non-linear characteristics created the _measured_ r-f intermodulation products and other performance data given in the Mendenhall paper I quoted. RF |
#2
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On Sun, 13 Jun 2010 10:14:21 -0700 (PDT), Richard Fry
wrote: Would you please respond in your own words Hi Richard, I conform to Mendenhall to the specific statement I responded to. If you believe What I believe has been succinctly laid out in my subscribing to Mendenhall's explicit statement. THEN PLEASE EXPLAIN WHY I don't see that elaboration is going to improve what has been presented. Yes, it is a difficult concept that many struggle with and few have had experience in making a sufficiently accurate determination of. Consult Walt's 333 line posting and examine how experience comes to bear and through my recitations reveal the dovetail fit to theory. The Only Explanation Possible: Here's a modest proposal, Mendenhall constructed a power amplifier that is within the technical grasp of many here to achieve at a modest workbench. The design is quite spartan. The design is quite understressed (there is nothing "forcing" a conclusion). The design conforms to all engineering standards. Build your own. [It feels strange to have to offer that option to a group of Hams.] Having this amplifier before you, observe all the variables, play with them. Measure their impact on NOhms. Account for the heat with direct measurement and note what does not conform to convention. When that is finished the real work begins. Calibrate your tools and repeat this for accuracy. 73's Richard Clark, KB7QHC |
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