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#21
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Understanding Parallel to Series conversion
"Richard Clark" wrote in message ... On Thu, 13 Jan 2011 16:18:35 -0600, "amdx" wrote: The article's focus is on matching a crystal radio tank to the antenna, So as a general statement, the tank is a high impedance (mostly R) Hi Mike, There's your first mistake. Tank Z is never, ever "mostly R," or you wouldn't be able to make the Q claim of 1000 (or even 10). Ok, Richard that wasn't clear to me, I think at resonance the tank is all R, but I put mostly R because I figured you would have an objection to all R. So are you saying it is pure R at resonance? ......which, then leads me to ask "What do you really want?" 73's Richard Clark, KB7QHC I want to understand the use of an air variable to match an antenna to the tank of a crystal radio, over the AMBCB frequency range. With that, I found I need to understand the series to parallel conversion, which I now understand, just IS, it's not anything you do. A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. But as long as that R is transformed up, and minimally loads my tank, that's all good. Then, I understand I still have C left that I can use as part of the C for resonating my LC tank. Mikek |
#22
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Understanding Parallel to Series conversion
On 1/13/2011 7:51 PM, amdx wrote:
"Richard wrote in message ... On Thu, 13 Jan 2011 16:18:35 -0600, wrote: The article's focus is on matching a crystal radio tank to the antenna, So as a general statement, the tank is a high impedance (mostly R) Hi Mike, There's your first mistake. Tank Z is never, ever "mostly R," or you wouldn't be able to make the Q claim of 1000 (or even 10). Ok, Richard that wasn't clear to me, I think at resonance the tank is all R, but I put mostly R because I figured you would have an objection to all R. So are you saying it is pure R at resonance? ......which, then leads me to ask "What do you really want?" 73's Richard Clark, KB7QHC I want to understand the use of an air variable to match an antenna to the tank of a crystal radio, over the AMBCB frequency range. With that, I found I need to understand the series to parallel conversion, which I now understand, just IS, it's not anything you do. A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. But as long as that R is transformed up, and minimally loads my tank, that's all good. Then, I understand I still have C left that I can use as part of the C for resonating my LC tank. Mikek You've got it now, Mike. The series/parallel equivalent circuits are just a mathematical tool for putting things in a form you can handle easier. Adding the capacitor does not change the circuit from series to parallel or the other way around. Lets say you have a fixed frequency AC source, a resistor, and a capacitor. The R and C is in a box where you can't see how they are wired. You measure the voltage applied to the box and measure the current (with phase) into the box. You could calculate the value of the R and C, right? Most people would calculate them as an R in series with a C. But, there is a parallel R (of a different value from the series case) and a parallel C (of a different value) which will give the same measurements as the series case. You cannot tell which way they are wired internally and, because of this, you cannot tell the actual values of the components. But, for analysis or synthesis, it won't matter. You can mathematically change a circuit around from series (impedance) to parallel (admittance). This is the conversion that you've been hung up on. Does this make any sense? Cheers, John |
#23
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Understanding Parallel to Series conversion
"John - KD5YI" wrote in message ... On 1/13/2011 7:51 PM, amdx wrote: "Richard wrote in message ... On Thu, 13 Jan 2011 16:18:35 -0600, wrote: The article's focus is on matching a crystal radio tank to the antenna, So as a general statement, the tank is a high impedance (mostly R) Hi Mike, There's your first mistake. Tank Z is never, ever "mostly R," or you wouldn't be able to make the Q claim of 1000 (or even 10). Ok, Richard that wasn't clear to me, I think at resonance the tank is all R, but I put mostly R because I figured you would have an objection to all R. So are you saying it is pure R at resonance? ......which, then leads me to ask "What do you really want?" 73's Richard Clark, KB7QHC I want to understand the use of an air variable to match an antenna to the tank of a crystal radio, over the AMBCB frequency range. With that, I found I need to understand the series to parallel conversion, which I now understand, just IS, it's not anything you do. A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. But as long as that R is transformed up, and minimally loads my tank, that's all good. Then, I understand I still have C left that I can use as part of the C for resonating my LC tank. Mikek You've got it now, Mike. The series/parallel equivalent circuits are just a mathematical tool for putting things in a form you can handle easier. Adding the capacitor does not change the circuit from series to parallel or the other way around. Lets say you have a fixed frequency AC source, a resistor, and a capacitor. The R and C is in a box where you can't see how they are wired. You measure the voltage applied to the box and measure the current (with phase) into the box. You could calculate the value of the R and C, right? Most people would calculate them as an R in series with a C. But, there is a parallel R (of a different value from the series case) and a parallel C (of a different value) which will give the same measurements as the series case. You cannot tell which way they are wired internally and, because of this, you cannot tell the actual values of the components. But, for analysis or synthesis, it won't matter. You can mathematically change a circuit around from series (impedance) to parallel (admittance). This is the conversion that you've been hung up on. Does this make any sense? Cheers, John Ya, I have a better understanding now. I need to run a few cases and see the minimum and maximum capacitor needed for a proposed situation. I wish it would warm up, I'd like to put up an antenna and measure it, to get a real case to work with. Mikek |
#24
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Understanding Parallel to Series conversion
In article ,
amdx wrote: A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. What I found to be most instructive, in understanding this (that is, series representations vs. parallel representations) was to drop down a level into the underlying mathematics. Start with the fact that you have two impedances (let's call them Z1 and Z2) which are in parallel. Toss in the basic formula for the result: Ztot = (Z1 * Z2) / (Z1 + Z2) Since you have a resistor R and a capacitor C in parallel, Z1 is a real number (it's just R), and Z2 will be an imaginary number (it's -i/2piFC, or 1/jWC if you prefer engineering notations and squint at the "W" so it looks like an omega). Plug these values into the equation above, and simplify according to the rules for complex number mathematics. You'll end up with Ztot being a complex number, equal to the sum of a pure resistance (real) and a pure capacitance (imaginary). These are the impedances of the series network equivalent to your original parallel network. Alternate route to the same solution: take each of the two impedances and invert them, to determine the admittances of the two components. The admittance of R will be purely real, while the admittance of C will be purely imaginary. Add the two together (since they're in parallel) to get the complex admittance of the parallel combination. Now, invert this complex number according to the usual rules, to get the equivalent complex impedance... this will be a complex number, the sum of a pure resistance and a pure capacitance. The numbers you get will be the same as in the previous work-through. -- Dave Platt AE6EO Friends of Jade Warrior home page: http://www.radagast.org/jade-warrior I do _not_ wish to receive unsolicited commercial email, and I will boycott any company which has the gall to send me such ads! |
#25
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Understanding Parallel to Series conversion
On 1/13/2011 8:33 PM, amdx wrote:
Ya, I have a better understanding now. I need to run a few cases and see the minimum and maximum capacitor needed for a proposed situation. I wish it would warm up, I'd like to put up an antenna and measure it, to get a real case to work with. Mikek Mike - Look into getting and learning (free) LTSpice for circuit analysis. Also look into getting and learning EZNEC (free) for antenna analysis. You can't beat putting up an antenna and building a circuit for it and measuring results. But, during adverse weather, you can experiment with simulation software and learn a lot. Then you can try your simulated experiments when the wx is good. Cheers, John |
#26
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Understanding Parallel to Series conversion
On Thu, 13 Jan 2011 20:10:46 -0600, John - KD5YI
wrote: Does this make any sense? Up, up, and away, in my beautiful, my beautiful balun! |
#27
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Understanding Parallel to Series conversion
On Thu, 13 Jan 2011 19:51:21 -0600, "amdx" wrote:
"Richard Clark" wrote in message .. . On Thu, 13 Jan 2011 16:18:35 -0600, "amdx" wrote: The article's focus is on matching a crystal radio tank to the antenna, So as a general statement, the tank is a high impedance (mostly R) Hi Mike, There's your first mistake. Tank Z is never, ever "mostly R," or you wouldn't be able to make the Q claim of 1000 (or even 10). Ok, Richard that wasn't clear to me, I think at resonance the tank is all R, but I put mostly R because I figured you would have an objection to all R. So are you saying it is pure R at resonance? Hi Mike, Let's say there is absolutely no loss in the Tank (superconduction and perfect dissipation values as it were); then we would have to ask ourselves what happens to energy applied to this Tank at resonance? It can never enter it, thus the Tank is, in effect, infinite in resistance. But what about the circulating currents? The Tank is, in effect, infinite in conductance. Infinite Ohms & Zero Ohms simultaneously. Is this the Z of the Tank? Is this the R of the Tank to which you are matching? No, not even close and certainly it has nothing to do with resonance - except the condition is a function of it being at resonance. A low Z Tank or a high Z Tank each evidences the same Infinite Ohms & Zero Ohms simultaneity given my initial condition of absolute losslessness. For the energy being applied to or drawn from the Tank, the Tank is in parallel operation. For energy in the Tank, the Tank is in series operation. Where is the Q in this duality? Q suffers by the nature of what you call R. Q has two different values by this duality. One is called "Loaded Q" and as you might guess, the second is called "Unloaded Q." Consult Terman for the engineering design rationale for optimal Qs as I suggested. When the discussion of "matching" seeks to employ R (pure resistance), then the next step is toward a conjugate match and elaborations of efficiency and maximum transfer of power. There is also an alternative discussion called the Zo Match. This second match seems to invite the same elaborations (many who post here try to force them both into the same salad bowl and cover the illogic with dressing). When you offered the comment about "the tank is a high impedance (mostly R)" it was steering the car off the cliff. Is this a Zo match or a Conjugate match you are seeking? (I can already anticipate this has gone over your head, as well as many readers. This and the questions that follow are rhetorical.) For instance, and returning to antennas (the purpose of this group's discussion focus), you can have very high Z antennas with very low resistance characteristics. Do you want a Zo Match, or a Conjugate Match? Let me flip the antenna: you can have very high Z antennas with very high resistance characteristics. Do you want a Zo Match, or a Conjugate Match? Let's do this sideways: you can have very low Z antennas with very low resistance characteristics. Do you want a Zo Match, or a Conjugate Match? I could box the compass here, but the I think I will let the reader off. ......which, then leads me to ask "What do you really want?" 73's Richard Clark, KB7QHC I want to understand the use of an air variable to match an antenna to the tank of a crystal radio, over the AMBCB frequency range. With that, I found I need to understand the series to parallel conversion, which I now understand, just IS, it's not anything you do. A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. But as long as that R is transformed up, and minimally loads my tank, that's all good. Then, I understand I still have C left that I can use as part of the C for resonating my LC tank. Mikek John had some number issues with Tony's explanation, but the gist of Tony's rational treatment should be your lesson as it provides for your requested "why." It also implies (by my comments of the sudden appearance of two new components) that our (Ham) tuners have been designed to introduce the proper amounts of reactances in the proper parallel/series relationships to enable the necessary transform towards optimal Q and loading balance. The most elaborate of tuners can change from Pi to T topologies, or series L parallel C (or series C parallel L), or series LC, or parallel LC, or parallel C series L (or parallel L series C)... and any of the other combinations I have not enumerated (about 9 in all). Each shines for a particular situation - you have named only one. It is not a trivial discussion by any means even when we are talking about the addition of only two new components. So, your obtaining an understanding is not going to be achieved at one sitting in front of the "definitive" posting to a thread. One problem of seeking the "definitive" posting is that it cannot be born from a broken premise that article you were trying to figure out is lame in the extreme. Given everything you have revealed about it, it didn't present a solution to its fantasy antenna. That is why this work of fiction is not understandable. 73's Richard Clark, KB7QHC |
#28
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Understanding Parallel to Series conversion
On Thu, 13 Jan 2011 21:43:55 -0800, GoldIntermetallicEmbrittlement
g wrote: On Thu, 13 Jan 2011 20:10:46 -0600, John - KD5YI wrote: Does this make any sense? Up, up, and away, in my beautiful, my beautiful balun! That's even worse than your favourite. You know, the one that goes "Your mother should be arrested for ......" **** off, you pathetic dullard. |
#29
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Understanding Parallel to Series conversion
On Jan 14, 2:33*am, "amdx" wrote:
"John - KD5YI" wrote in ... On 1/13/2011 7:51 PM, amdx wrote: "Richard *wrote in message . .. On Thu, 13 Jan 2011 16:18:35 -0600, *wrote: The article's focus is on matching a crystal radio tank to the antenna, So as a general statement, the tank is a high impedance (mostly R) Hi Mike, There's your first mistake. *Tank Z is never, ever "mostly R," or you wouldn't be able to make the Q claim of 1000 (or even 10). * Ok, *Richard that wasn't clear to me, I think at resonance the tank is all R, but I put mostly R because I figured you would have an objection to all R. So are you saying it is pure R at resonance? ......which, then leads me to ask "What do you really want?" 73's Richard Clark, KB7QHC * I want to understand the use of an air variable to match an antenna to the tank of a crystal radio, over the AMBCB frequency range. * With that, I found I need to understand the series to parallel conversion, which I now understand, just IS, it's not anything you do. A series RC has a parallel RC equivalent. I'm not sure how it can be both at the same time. But as long as that R is transformed up, and minimally loads my tank, that's all good. Then, I understand I still have C left that I can use as part of the C for resonating my LC tank. * * * * * * * * * * Mikek You've got it now, Mike. The series/parallel equivalent circuits are just a mathematical tool for putting things in a form you can handle easier. Adding the capacitor does not change the circuit from series to parallel or the other way around. Lets say you have a fixed frequency AC source, a resistor, and a capacitor. The R and C is in a box where you can't see how they are wired. You measure the voltage applied to the box and measure the current (with phase) into the box. You could calculate the value of the R and C, right? Most people would calculate them as an R in series with a C. But, there is a parallel R (of a different value from the series case) and a parallel C (of a different value) which will give the same measurements as the series case. You cannot tell which way they are wired internally and, because of this, you cannot tell the actual values of the components. But, for analysis or synthesis, it won't matter. You can mathematically change a circuit around from series (impedance) to parallel (admittance). This is the conversion that you've been hung up on. Does this make any sense? Cheers, John *Ya, I have a better understanding now. I need to run a few cases and see the minimum and maximum capacitor needed for a proposed situation. * I wish it would warm up, I'd like to put up an antenna and measure it, to get a real case to work with. * * * * * * * * * * * * * * * * * *Mikek just throw a wire out the window, plug it in, and see if it works! ANY antenna connected with a hunk of hookup wire will work better than NO antenna with a perfectly designed match! |
#30
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Ahh....1 should have said Series to Parallel Conversion.
Mikek __________________ |
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