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Uh.. I'm gonna do this anyway...
"Cecil Moore" wrote in message ... Henry Kolesnik wrote: ...shorted 1/4 wave stub... for the 2nd harmonic it's a 1/2 wave stub and exhibits a very low impedance or a short. There are claims that this can be used to filter the even harmonics. Shorts can't diisipate power and must reflect, so how does a stub work? Consider the following configuration: Source----ideal 1 WL feedline-----------+-----matched load | |Stub | | open Oops! Time to wipe the CRT clean... Henry wants to discuss a SHORTED stub...reset. end. stop. My original comments hold. Harmonics are "reflected" or however you want to look at the fact that they don't make it to the "matched load". ....... Unfortunately, I continue... Assuming Cecil's comments will be valid if I swap the 1xF (1/4W) and the 2xF (1/2W) comments, I proceed... If the stub is 1/4WL, [... RESPONDIND as though this was the 1/2W remark...] At the mouth of the stub, they are 180 degrees out of phase and superpose to zero volts which obeys Ohm's law and delivers zero power to the load. Yea, ok, so a little sneaks by since it ain't lossless. Double the frequency. That makes the stub 1/2WL. [...RESPONDING as though this was the 1/4W remark...] The forward voltage and reflected voltage are essentially the same ... they are in phase and superpose to a maximum value which obeys Ohm's law and delivers maximum power to the load. In my mental model, a hi Z across the line. Absolutely nothing except superposition and interference happens at the mouth of a stub. All the reflected action happens at the physical open circuit. Virtual impedances are only a V/I ratio and CANNOT cause reflections. Absolutely no reflections are happening at the mouth of the stub (unless a physical impedance discontinuity exists there). \\ Nit alarm on\\ (Though I consider this a clarification in an attempt to simplify the explanation and remove the extra complexity added by the double terms) I consider superposition and interference to be the same thing. Superposition is the addition of two quantities (voltages ot currents). They can be of similar sign or different. If they are closer to 'in-phase', then they add to a greater value and if they are closer to 180 degree phase difference, then they add to a smaller value. You can call that "algebraiclly add" if it makes you feel better. That is, a +1 and +1 _add_ to +2. A -1 and a +1 _add_ to 0.0 \\ end nit alarm \\ This IS a correct way to look at it. Think of the "main" line" (the one going to the "matched load" above) as being the thing which is "added to" the shorted system. Since it is added to a low Z point (on this high VSWR line), little goes down that path to the desired load. Any 50 ohm "thing" put in parallel at the point of the lowest voltage of the standing wave, sees a low/zero voltage, therefopre nothing goes there. Consider this. If a stub really presented an infinite impedance, you could simply remove it and nothing would change. At the fundamental (_OPEN_ 1/4W stub, remember) this IS TRUE. Are you saying that the 1/4W _shorted_ stub addition or removal makes a BIG difference at the fundamental -I think not, or you still talking about the 1/4W _open_ stub which kills the system at the fundamental when added. |
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