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On 10/6/2015 3:26 AM, Ian Jackson wrote:
In message , rickman writes When you tune for VSWR of 1:1, the impedance of the TX side of the ATU will match the TX. You can't say it is 50 ohms unless the TX is 50 ohms, no? No, no, no. As I keep saying, the reading on the SWR meter has nothing to do with the output impedance of the TX feeding RF into it. It is determined by the reference resistors in the meter's directional coupler circuits and the impedance of the load attached to its output. If the load is 50 ohms, a 50 ohm SWR meter will read 1:1, regardless of the TX output impedance. The purpose of the ATU is not to match the TX output impedance to the outside world. It is to convert the impedance of the outside world to 50 ohms - which is the impedance the TX is designed to work into. So there *can* be reflected power back into the TX by the ATU if the impedances don't match. I guess this is not so much an issue in that the TX is never supposed to drive any other impedance. Rather than talk about power reflected back into the TX, the power delivered into a 50 ohm load is considered the point of reference. But if a resistive load of less than 50 ohms is connected to the output, it would dissipate *more* power than the 50 ohm load would. If the TX output were also 50 ohms, max power would only be delivered into a 50 ohm load. -- Rick |
#172
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On 10/6/2015 6:31 AM, Jeff wrote:
The whole function of the ATU is to provide a 1:1 match for the Tx, when that is the case NO POWER GOES BACK TO THE TX. That is not technically correct. A 1:1 match prevents TX power from being reflected, it does not prevent other power from being sent to the TX. Depends how pedantic you are being, we are only considering the wave that is originated by the Transmitter at one particular frequency. If the ATU is set to provide a 1:1 match at that frequency then NO PART of that forward wave will find its way back to the Tx. Who is being pedantic? It is not about the reflection of the power from the TX at that point. The issue being discussed is how much power reflected from the antenna will find it way back through the ATU to the TX. Just as all power from the TX will cross the 1:1 impedance match (if there *is* a 1:1 impedance match) all the power passing through the ATU from the antenna will find it's way into the receiver. The question at this point is if there is *any* power that is not reflected by the ATU *back* to the antenna to pass through the ATU. That is not to say that ....snip without changing meaning... a signal that originates at the antenna will not pass to the Rx. That is my point. Anyway this discussion has now got to the silly stage so I am off. Ok, enjoy. -- Rick |
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