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#1
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On Thu, 25 Nov 2004 20:51:16 -0700, Wes Stewart
wrote: On Thu, 25 Nov 2004 20:20:32 GMT, (Robert Lay W9DMK) wrote: Bob, You might want to look at this paper: http://users.triconet.org/wesandlinda/AIEE_High_Swr.pdf Dear Wes, I have downloaded the pdf file and printed it out. It's tough reading. I hope that MacAlpine agrees with what Dave and Richard are telling me, because their responses seem to be correct and are exactly what I was afraid of - that I've been sucked into another example of the strange terminology used to describe "losses". I have always thought of "loss" as a conversion to another form of energy (typically heat energy) which is lost from the system. Apparently, the kind of "loss" being described in the example that I gave is not a loss at all. It's more like "return loss", which is also not a true "loss" in my thinking. In other words, it seems that the "Additional Losses Due to SWR" are not losses at all, but are simply a measure of the power that "could" have been delivered to the load were it not for the mis-match. Bob, W9DMK, Dahlgren, VA http://www.qsl.net/w9dmk |
#2
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On Fri, 26 Nov 2004 16:12:34 GMT, (Robert Lay
W9DMK) wrote: |On Thu, 25 Nov 2004 20:51:16 -0700, Wes Stewart |wrote: | |On Thu, 25 Nov 2004 20:20:32 GMT, (Robert Lay |W9DMK) wrote: | |Bob, | |You might want to look at this paper: | |http://users.triconet.org/wesandlinda/AIEE_High_Swr.pdf | | |Dear Wes, | |I have downloaded the pdf file and printed it out. It's tough reading. Yes. But the ITT Reference Data For Radio Engineers uses this paper as a reference. If you have Mathcad, a sheet that implements some of the equations was included as a reference in my Balanced Transmission line paper. http://users.triconet.org/wesandlinda/LineCalc.mcd |I hope that MacAlpine agrees with what Dave and Richard are telling |me, because their responses seem to be correct and are exactly what I |was afraid of - that I've been sucked into another example of the |strange terminology used to describe "losses". | |I have always thought of "loss" as a conversion to another form of |energy (typically heat energy) which is lost from the system. |Apparently, the kind of "loss" being described in the example that I |gave is not a loss at all. Yes it is. A simple-minded way of looking at it is if the SWR is greater than unity then increased current is flowing in the line. The line has resistive loss, so the I^2*R loss increases. The current isn't constant (there is a current standing ratio, ISWR, just like a VSWR) so there are peaks and valleys in the current and as you have figured out, the longer the line and the higher its nominal loss, the lower the ISWR is at the line input. So the loss per unit length is non-linear and varies with distance from the mismatch, but it is a real dissipative loss. For those interested in the loss in the shorted or open stub case, maybe this will be of interest: http://users.triconet.org/wesandlind...ching_Loss.pdf |
#3
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On Fri, 26 Nov 2004 10:57:25 -0700, Wes Stewart
wrote: Yes. But the ITT Reference Data For Radio Engineers uses this paper as a reference. If you have Mathcad, a sheet that implements some of the equations was included as a reference in my Balanced Transmission line paper. http://users.triconet.org/wesandlinda/LineCalc.mcd Dear Wes, I was happy to find that the MacAlpine paper is the first part of Chapter 22 of the ITT Handbook, as the latter is much more readable. I did not pick up on the MathCad files, because I do not have MathCd - however, the material from MacAlpine and Ricardi have answered most of my concerns. |I hope that MacAlpine agrees with what Dave and Richard are telling |me, because their responses seem to be correct and are exactly what I |was afraid of - that I've been sucked into another example of the |strange terminology used to describe "losses". | |I have always thought of "loss" as a conversion to another form of |energy (typically heat energy) which is lost from the system. |Apparently, the kind of "loss" being described in the example that I |gave is not a loss at all. I was premature in those two paragraphs, above. I can see now that the Additional Losses Due to SWR really are dissipative and are unrelated to the "Mismatch Losses" and "Transducer Losses" defined on page 22-12 of the ITT Handbook, 5th Ed. Yes it is. A simple-minded way of looking at it is if the SWR is greater than unity then increased current is flowing in the line. The line has resistive loss, so the I^2*R loss increases. The current isn't constant (there is a current standing ratio, ISWR, just like a VSWR) so there are peaks and valleys in the current and as you have figured out, the longer the line and the higher its nominal loss, the lower the ISWR is at the line input. My interpretation of your "Yes it is." is that you mean that the Additional Losses Due to SWR are truly heat losses and are due to the ohmic losses in the hot spots of the line. Then we agree on that point. Your paragraph above is much more succinct than the papers by MacAlpine and Ricardi, but it certainly tells the story. So the loss per unit length is non-linear and varies with distance from the mismatch, but it is a real dissipative loss. I don't know that I would have used the term "non-linear", but I would certainly agree that it varies along the line in accordance with the current loops. For those interested in the loss in the shorted or open stub case, maybe this will be of interest: http://users.triconet.org/wesandlind...ching_Loss.pdf I took that pdf and added it to the collection. There were several things about that paper that filled-in gaps of detail in MacAlpine. However, neither paper gives us much hope for a simple model of these losses. Nonetheless, it makes hash out of the material in The ARRL Antenna Book. In all fairness, the Antenna Book cannot cover all aspects of these topics in detail. Unfortunately, the material in the Antenna Book is, in my opinion, very misleading in several specific areas, as follows: - The Antenna Book gives only one expression for Total Line Loss (combining ML loss and the Additional Loss Due to SWR). If we accept Macalpine's model, there are different relationships for the range of SWR from 0 to 6 and for the range from 6 upwards. - Antenna Book does not explain that the hot spots are very localized and that the additional losses can be quite dependant upon the length of the line in wavelengths. For example, the losses in a segment of line less than 1/3 wavelength might be insignificant in comparison with a segment of line greater than 1/3 wavelength simply because the shorter segment may not contain a hot spot. In other words, one cannot apply the Antenna Book equations, blindly, because of several factors that are not even mentioned, and for short line segments it is quite possible that there would be no signicant losses due to SWR. - The most misleading information in The Antenna Book is on pages 24-11 and 24-12 where it is shown that a 100 foot RG-213 feedline will suffer 25 dB of Additional Loss Due to SWR at 1.83 MHz because of the very short antenna. I believe that when the equations from the ITT Handbook are used instead, that the actual losses will be far, far less. Just today, I made a careful measurement on an RG-8/U line of 5.33 meters length at 30 MHz and terminated with a 4700 + j 0 load. The Matched Line Loss of that line at 30 MHz is 0.9 dB per 100 feet, and its Velocity Factor is between 0.75 and 0.80 The input impedance was actually measured at 2.45 -j15 ohms for an SWR at the input of 22.25. The SWR at the load end was 94. Those two SWR's establish a total loss on the line of 0.15 dB. If one were to blindly apply the formula in The Antenna Book on page 24-9, the result obtained would be 4.323 dB. Bob, W9DMK, Dahlgren, VA http://www.qsl.net/w9dmk |
#4
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Robert Lay W9DMK wrote:
Just today, I made a careful measurement on an RG-8/U line of 5.33 meters length at 30 MHz and terminated with a 4700 + j 0 load. The Matched Line Loss of that line at 30 MHz is 0.9 dB per 100 feet, and its Velocity Factor is between 0.75 and 0.80 The input impedance was actually measured at 2.45 -j15 ohms for an SWR at the input of 22.25. The SWR at the load end was 94. Those two SWR's establish a total loss on the line of 0.15 dB. If one were to blindly apply the formula in The Antenna Book on page 24-9, the result obtained would be 4.323 dB. For your 1/4WL open stub on 10.6 MHz, with a stub impedance of 0.57 ohms, I calculate total losses of about 0.2 dB. -- 73, Cecil http://www.qsl.net/w5dxp |
#7
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Keep in mind that real ohmic and dielectric losses measured in watts depend
upon sqrt(SWR). Thus, the higher the SWR (load mismatch) the greater the I^2R losses in the conductors and similarly in the dielectric. So, to me, a non-unity SWR connotes real power loss measurable in watts and attributable to well-known loss mechanisms. Of course, any real power lost in the line materials represents power not delivered to the load, so this fits somewhat with the viewpoint that Line Loss is in fact the magnitude of power undelivered to the load due to the mismatch. But, I think that we are looking at real watts of loss here. Another confusing factor is that one is usually interested in the total loss attributable to the use of a mismatched line and not especially in how that loss is distributed along the line from load to source. But there are applications where the loss distribution with line length is of concern. An example is the case of a complex Zo with rho unity in which the majority of the power loss occurs in the section of the line nearest the load and decreases toward the source. In that case of probably limited application, the line nearest the load might be required to handle more power than that further toward the source. A somewhat related example concerns the W2DU balun in which is it observed that the beads nearest the mismatched load endure the largest heat dissipation and are commonly larger that the remainder further toward the source. However, since complex Zo is an issue of magnitude usually only at low r-f and more so at audio frequencies, this is seldom a practical consideration. Thanks for bringing this topic to light, Bob. Like most engineers, I have been guilty of looking at "line loss" as a monolithic phenomenon and not being concerned with the micro-structure of its distribution. -- 73, George W5YR Fairview, TX http://www.w5yr.com "Robert Lay W9DMK" wrote in message ... On Thu, 25 Nov 2004 20:51:16 -0700, Wes Stewart wrote: On Thu, 25 Nov 2004 20:20:32 GMT, (Robert Lay W9DMK) wrote: Bob, You might want to look at this paper: http://users.triconet.org/wesandlinda/AIEE_High_Swr.pdf Dear Wes, I have downloaded the pdf file and printed it out. It's tough reading. I hope that MacAlpine agrees with what Dave and Richard are telling me, because their responses seem to be correct and are exactly what I was afraid of - that I've been sucked into another example of the strange terminology used to describe "losses". I have always thought of "loss" as a conversion to another form of energy (typically heat energy) which is lost from the system. Apparently, the kind of "loss" being described in the example that I gave is not a loss at all. It's more like "return loss", which is also not a true "loss" in my thinking. In other words, it seems that the "Additional Losses Due to SWR" are not losses at all, but are simply a measure of the power that "could" have been delivered to the load were it not for the mis-match. Bob, W9DMK, Dahlgren, VA http://www.qsl.net/w9dmk |
#8
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Modeling a free space dipole made from a lossless conductor, 100 ft in
length, at 1.8 MHz shows an input impedance of 6.694 - j1621 Ohms. As expected the radiation efficiency is 100%. Adding 300 ft of 600 Ohm, 6" spaced, copper open wire transmission line degrades the radiation efficiency to 16.75 %. The result, therefore indicates a transmission line loss of 7.76 dB. The input impedance is calculated as 11 - j619.7 Ohms. The ARRL, DOS based program, "TL" computes, for 300 ft of 600 Ohm line terminated with 6.694 - j1621 Ohms, a loss of 8.19 dB, and an input impedance of 18.35 - j805 Ohms. Realizing that 6" spaced, #14 AWG, is not exactly 600 Ohms, and NEC's computation of parallel wire transmission lines is not 100% accurate; the results do seem to confirm the validity of the ARRL's program. Another interesting experiment with the ARRL's program also seems to verify its accuracy: RG8, 1000 ft, frequency 100 MHz. Matched line loss = 24.82 dB. Load impedance 1 - j1000 Ohms. Total line loss = 61.82 dB. The program computes the input impedance to by: 50.3 - j0.2 Ohms. 73, Frank "George, W5YR" wrote in message ... Keep in mind that real ohmic and dielectric losses measured in watts depend upon sqrt(SWR). Thus, the higher the SWR (load mismatch) the greater the I^2R losses in the conductors and similarly in the dielectric. So, to me, a non-unity SWR connotes real power loss measurable in watts and attributable to well-known loss mechanisms. Of course, any real power lost in the line materials represents power not delivered to the load, so this fits somewhat with the viewpoint that Line Loss is in fact the magnitude of power undelivered to the load due to the mismatch. But, I think that we are looking at real watts of loss here. Another confusing factor is that one is usually interested in the total loss attributable to the use of a mismatched line and not especially in how that loss is distributed along the line from load to source. But there are applications where the loss distribution with line length is of concern. An example is the case of a complex Zo with rho unity in which the majority of the power loss occurs in the section of the line nearest the load and decreases toward the source. In that case of probably limited application, the line nearest the load might be required to handle more power than that further toward the source. A somewhat related example concerns the W2DU balun in which is it observed that the beads nearest the mismatched load endure the largest heat dissipation and are commonly larger that the remainder further toward the source. However, since complex Zo is an issue of magnitude usually only at low r-f and more so at audio frequencies, this is seldom a practical consideration. Thanks for bringing this topic to light, Bob. Like most engineers, I have been guilty of looking at "line loss" as a monolithic phenomenon and not being concerned with the micro-structure of its distribution. -- 73, George W5YR Fairview, TX http://www.w5yr.com "Robert Lay W9DMK" wrote in message ... On Thu, 25 Nov 2004 20:51:16 -0700, Wes Stewart wrote: On Thu, 25 Nov 2004 20:20:32 GMT, (Robert Lay W9DMK) wrote: Bob, You might want to look at this paper: http://users.triconet.org/wesandlinda/AIEE_High_Swr.pdf Dear Wes, I have downloaded the pdf file and printed it out. It's tough reading. I hope that MacAlpine agrees with what Dave and Richard are telling me, because their responses seem to be correct and are exactly what I was afraid of - that I've been sucked into another example of the strange terminology used to describe "losses". I have always thought of "loss" as a conversion to another form of energy (typically heat energy) which is lost from the system. Apparently, the kind of "loss" being described in the example that I gave is not a loss at all. It's more like "return loss", which is also not a true "loss" in my thinking. In other words, it seems that the "Additional Losses Due to SWR" are not losses at all, but are simply a measure of the power that "could" have been delivered to the load were it not for the mis-match. Bob, W9DMK, Dahlgren, VA http://www.qsl.net/w9dmk |
#9
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Reg, G4FGQ wrote:
"The active device generally behaves as a current source." As Reg also wrote: "I can`t imagine why this conversation has continued for so many years by more or less the same group of experts." Agreed! Reg seems to have answered his own question.The same people recite the same arguments in hopes their view of reality will be accepted. Fat chance! Time has inured them. Reg has faithfully proposed constant-current behaviour from all vacuum valves and transistors as I recall. I agree that most of these devices have extremely high plate ond collector resistances as linear amplifiers. Current through them is almost constant regardless of anode voltage. As most transmitter power amplifiers exceed 50% efficiency by a good margin, these devices are not operating as Class-A linear amplifiers. They instead operate as HF switches. These are turned-off most of every cycle and are only on for short pulses. Harmonics and other noise is cleaned up by output filters. It`s the only thing which makes the output linear. During the output device`s conduction, its saturation volts are very low and its current is very high, giving the device a very low impedance while switched-on. You may not infer a low impedance from the d-c volts and amps feeding the final amplifier. These are the averages, almost, of the device amps. The device saturation volts sre what counts toward its dissipation and loss. The transmitter usually has no built-in indicator of saturation voltage. It wouldn`t read much anyway.Device impedance depends mostly on its ratio of off to on times. This is a form of lossless resistance. Dissipation is zero in a sewitched-off device. The d-c volts and amps are related to the output device(s) internal impedances used as a switch when the transmitter output is considered. A high voltage and a low current accompany a high internal impedance but they won`t be nearly so high as the spec sheet plate or collector resistances. We have d-c power input to the amplifier. We can measure HF power output. The difference is dissipation, but loss resistance does not represent the total source resistance because we have non-dissipative resistance in the device off-times. There have been measurements of transmitter internal output impedances which indicated that they did indeed match their loads. I have not done it myself but have no reason to doubt the reports. Best regards, Richard Harrison, KB5WZI |
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