RadioBanter

RadioBanter (https://www.radiobanter.com/)
-   Antenna (https://www.radiobanter.com/antenna/)
-   -   Additional Line Losses Due to SWR (https://www.radiobanter.com/antenna/2639-additional-line-losses-due-swr.html)

Robert Lay W9DMK December 5th 04 10:51 PM

On Sat, 04 Dec 2004 18:40:20 GMT, Richard Clark
wrote:

On Sat, 04 Dec 2004 05:24:33 GMT, (Robert Lay
W9DMK) wrote:

Just today, I made a careful measurement on an RG-8/U line of 5.33
meters length at 30 MHz and terminated with a 4700 + j 0 load. The
Matched Line Loss of that line at 30 MHz is 0.9 dB per 100 feet, and
its Velocity Factor is between 0.75 and 0.80 The input impedance was
actually measured at 2.45 -j15 ohms for an SWR at the input of 22.25.
The SWR at the load end was 94. Those two SWR's establish a total loss
on the line of 0.15 dB. If one were to blindly apply the formula in
The Antenna Book on page 24-9, the result obtained would be 4.323 dB.

Surprisingly, it was not until today that I finally made a computation
of the input power to the line for the configuration above.
Specifically, I was able to compute the voltage and current at the
input to the line that would produce a 100 volt reference voltage
across the 4700 ohm line. That is the obvious thing that had to be
done in order to establish a reference power for purposes of computing
losses. That calculation resulted in an applied voltage at the line
input of 29.2 volts at angle -171.5 degrees and a current of 1.917
amps at -90.78 degrees. Computing power into the line as E*Icos(theta)
= 9.024 watts. The power delivered to the load is 100 volts squared
divided by 4700 ohms, which is 2.127 watts.

Therefore the efficiency is 23.6% and the losses in the line are 6.275
dB. In all fairness, I did have to change one assumption in the data
above. I had to revise my attenuation value of 0.9 dB per 100 ft.
upwards to a value of 1.72 dB per 100 ft. in order to get my measured
impedance at the line input to be consistent with that line impedance,
length, load value and velocity factor.


Hi Bob,

I notice that true to form, all the response in this thread were not
to your bench results. I trust you will appreciate hard
correspondence rather than the fluff.

The one thing (actually there are several) I noted was your having to
double the presumed line loss to make the numbers come out. Given
this injection (or removal) of 100% (or %50) of error, it stands to
reason that your bench, method or instruments need a attention.

The details as I've sifted from the postings:
Cable type = Columbia's number 1198 - not 9913.
Open circuit stub length = 5.334 meters
Frequency = 10.6 MHz,
Input Z = 0.57 + j 0.3 ohms.

The above details appear to have shifted in mid-stream to:
Cable type = RG-8/U line
stub length = 5.334 meters
Frequency = 30.0 MHz,
Open end termination = 4700 + j 0
Input Z = 2.45 -j15

I will skip the determinations of loss and SWR as being problematic as
you indicate and simply go with your observations noted above, and
summarized he
Open end Vtermination = 100V @ 0°
Open end Itermination = 0.0213A @ 0°
Fed end Vinput = 29.2V @ -171.5°
Fed end Iinput = 1.917A @ -90.78°

I was puzzled to see what was initially a resonant stub now measured
with an extremely high Reactance until I re-scanned the material to
note the tripling of frequency.

What caught my eye was this load and certainly your leap of faith that
it was wholly resistive, especially at HF for its size. This would be
extremely unlikely even in a standards lab.

To make a measurement, the rule of thumb is to have instrumentation
whose precision and accuracy exceeds the goal of measuring an unknown
by 5 to 10 times. For really difficult tests (and RF is classic in
that regard) 3 times is often the best you can achieve.

Let's look at that 4700 Ohm resistance. It demands that any
instrumentation support a paralleling load of no less than 23.5K Ohms
to 47K Ohms, or worst case, 14K Ohms. Let's simply ask about the
family lineage of that 4700 Ohm resistance. It sounds suspiciously
like a common (hopefully) carbon composition resistor.

If so, such beasties are rare if it is of the commercial variety, to
not exhibit reactances due to spiral cut value trimming, or an
end-to-end capacitance. Let's just say that you obtained a remarkable
resistor, but it cannot escape this common parasitic capacitance which
for the garden variety resistor amounts to 1.5pF.

At 30 MHz, this 1.5pF capacitance represents a reactance of 3.5K Ohm.
This rather sweeps aside your specification for the load and replaces
it with 4700 -j3537 Ohms. This is a big time source of error and does
not even come close to the 3X requirement for the lowest accuracy.
Worse yet, you haven't even added the bridging impedance of your
measuring device which is certain to be on par, if not worse (you
haven't identified your instrumentation).

Hope you are still looking forward to more fun. ;-)

73's
Richard Clark, KB7QHC


Dear Richard,

New Measurements -

I created a terminating load consisting of 4 composition resistors in
parallel. That measured 4.3 + j0.65 AT 20 MHz. I then measured the
input impedance of the 5.33 meter length of RG-8/U Foam coax
terminated with the 4.3 +j0.65 ohm load at 20 MHz, and that was 5 -
j7.1 ohms. The SWR at the load is 11.63 and the SWR at the input is
9.88.

Using a velocity factor of 0.745 and an attenuation value of .77, I
calculated the theoretical input impedance of the coax with the above
terminator. That gave a result of 5.17 - j7.3 ohms (theoretical). The
SWR at the load is 11.63, and the SWR at the input to the line is 9.88
(theoretical).

In setting up the simulation, it is necessary to pick an attenuation
and a velocity factor that are not only within the normal distribution
for that particular coax but also give a reasonably good match with
the measured values. In my opinion, the values that I used in the
simulation are well within the normal distribution of values for this
type of line, which has published values of VF=.8 and attenuation =
74 at 20 MHz.

The simulation also predicts the losses, and I used two different
models for that calculation. Both loss models predict a total loss of
0.723 dB, which is 0.589 above the matched line losses based on the
normal attenuation. The two math models used were as follows:

1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17th Edition, page 24-9.

Based on the limited tests that I have made so far, the two models
seem to give the same results. However, I am hoping to be able to
conduct measurements on configurations that involve much higher SWR
values. The immediate problem to be overcome is the measurement of
such impedance values as will be encountered.
Bob, W9DMK, Dahlgren, VA
http://www.qsl.net/w9dmk

Richard Clark December 6th 04 01:05 AM

On Sun, 05 Dec 2004 22:51:03 GMT, (Robert Lay
W9DMK) wrote:

New Measurements -

I created a terminating load consisting of 4 composition resistors in
parallel. That measured 4.3 + j0.65 AT 20 MHz.


I threw together two Allen Bradley 10 Ohm 5% 1/4 Watt resistors and
came up with 5.1 -j0.5 in a quick test at 20 MHz.

I then measured the
input impedance of the 5.33 meter length of RG-8/U Foam coax
terminated with the 4.3 +j0.65 ohm load at 20 MHz, and that was 5 -
j7.1 ohms. The SWR at the load is 11.63 and the SWR at the input is
9.88.

Using a velocity factor of 0.745 and an attenuation value of .77, I
calculated the theoretical input impedance of the coax with the above
terminator. That gave a result of 5.17 - j7.3 ohms (theoretical). The
SWR at the load is 11.63, and the SWR at the input to the line is 9.88
(theoretical).

In setting up the simulation, it is necessary to pick an attenuation
and a velocity factor that are not only within the normal distribution
for that particular coax but also give a reasonably good match with
the measured values. In my opinion, the values that I used in the
simulation are well within the normal distribution of values for this
type of line, which has published values of VF=.8 and attenuation =
74 at 20 MHz.


Hi Bob,

I would say that your data shows a very good correlation to the models
and certainly the presumptions you made are well within the production
variables.

The simulation also predicts the losses, and I used two different
models for that calculation. Both loss models predict a total loss of
0.723 dB, which is 0.589 above the matched line losses based on the
normal attenuation. The two math models used were as follows:

1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17th Edition, page 24-9.

Based on the limited tests that I have made so far, the two models
seem to give the same results. However, I am hoping to be able to
conduct measurements on configurations that involve much higher SWR
values. The immediate problem to be overcome is the measurement of
such impedance values as will be encountered.


Measure Q by the BW of the Half Power points.

73's
Richard Clark, KB7QHC

Robert Lay W9DMK December 6th 04 06:03 PM

On Mon, 06 Dec 2004 01:05:54 GMT, Richard Clark
wrote:

On Sun, 05 Dec 2004 22:51:03 GMT, (Robert Lay
W9DMK) wrote:

New Measurements -

I created a terminating load consisting of 4 composition resistors in
parallel. That measured 4.3 + j0.65 AT 20 MHz.


I threw together two Allen Bradley 10 Ohm 5% 1/4 Watt resistors and
came up with 5.1 -j0.5 in a quick test at 20 MHz.

I then measured the
input impedance of the 5.33 meter length of RG-8/U Foam coax
terminated with the 4.3 +j0.65 ohm load at 20 MHz, and that was 5 -
j7.1 ohms. The SWR at the load is 11.63 and the SWR at the input is
9.88.

Using a velocity factor of 0.745 and an attenuation value of .77, I
calculated the theoretical input impedance of the coax with the above
terminator. That gave a result of 5.17 - j7.3 ohms (theoretical). The
SWR at the load is 11.63, and the SWR at the input to the line is 9.88
(theoretical).

In setting up the simulation, it is necessary to pick an attenuation
and a velocity factor that are not only within the normal distribution
for that particular coax but also give a reasonably good match with
the measured values. In my opinion, the values that I used in the
simulation are well within the normal distribution of values for this
type of line, which has published values of VF=.8 and attenuation =
74 at 20 MHz.


Hi Bob,

I would say that your data shows a very good correlation to the models
and certainly the presumptions you made are well within the production
variables.

The simulation also predicts the losses, and I used two different
models for that calculation. Both loss models predict a total loss of
0.723 dB, which is 0.589 above the matched line losses based on the
normal attenuation. The two math models used were as follows:

1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17th Edition, page 24-9.

Based on the limited tests that I have made so far, the two models
seem to give the same results. However, I am hoping to be able to
conduct measurements on configurations that involve much higher SWR
values. The immediate problem to be overcome is the measurement of
such impedance values as will be encountered.


Measure Q by the BW of the Half Power points.

73's
Richard Clark, KB7QHC


Dear Richard,

I finally created a test load that gives me the higher SWR that I
wanted.
It measures 7.0 - j2008 at 1.8 MHz. I placed that test load at the end
of a 150 foot piece of RG-59/U and measured the input impedance as
38.5 + j 151.6 at 1.8 MHz. The load SWR is 7901 and the input SWR is
10.18.

Solution of the transmission line equations for this particular load
and with coax characteristics of 73 ohms, VF = .646 and an attenuation
of 0.57 dB per 100 feet gives an input impedance of 38.67 + j 149,
which is a very good match to the measured value.

Losses are calculated using the same two methods as reported in my
previous posting, as follows:
1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17 th Edition, page 24-9.


Matched line losses = 0.855 dB
Additional losses = 28.087 dB
Total losses = 28.942 dB

I am satisfied that the methods of calculating losses as described in
the two references are in agreement and are valid.

I am also reasonably satisfied that the 1 dB steps that are printed on
Smith Charts as the means of determining matched line losses are
valid, as are the nomograms provided in the ITT Handbook, pages 22-7
and 22-8, above.

73,
Bob, W9DMK, Dahlgren, VA
http://www.qsl.net/w9dmk

Richard Clark December 6th 04 07:57 PM

On Mon, 06 Dec 2004 18:03:47 GMT, (Robert Lay
W9DMK) wrote:

I finally created a test load that gives me the higher SWR that I
wanted.
It measures 7.0 - j2008 at 1.8 MHz. I placed that test load at the end
of a 150 foot piece of RG-59/U and measured the input impedance as
38.5 + j 151.6 at 1.8 MHz. The load SWR is 7901 and the input SWR is
10.18.

Solution of the transmission line equations for this particular load
and with coax characteristics of 73 ohms, VF = .646 and an attenuation
of 0.57 dB per 100 feet gives an input impedance of 38.67 + j 149,
which is a very good match to the measured value.

Losses are calculated using the same two methods as reported in my
previous posting, as follows:
1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17 th Edition, page 24-9.


Matched line losses = 0.855 dB
Additional losses = 28.087 dB
Total losses = 28.942 dB

I am satisfied that the methods of calculating losses as described in
the two references are in agreement and are valid.

I am also reasonably satisfied that the 1 dB steps that are printed on
Smith Charts as the means of determining matched line losses are
valid, as are the nomograms provided in the ITT Handbook, pages 22-7
and 22-8, above.


Hi Bob,

Congratulations are in order for your effort at the bench, regardless
of outcome.

Congratulations are in order for your chain of reasoning, your
attention to detail, and the obvious refinement of technique that is
now agreeing not only with references, but is also consistent from one
test to the next.

I still see some aberration in the data when you have to drive the
cable Z to 73 Ohms to make the formulas work. It shows that the
generality of the references is good, but with the instance of your
data is a forced conclusion. I don't find that particularly upsetting
as the accumulation of error could easily account for some of the
differences.

You might want to revisit some of Bart's offerings in this thread;
especially his discussion of the effect of Low-R loads as a source of
Hi-Z, Hi-SWR.

73's
Richard Clark, KB7QHC

Robert Lay W9DMK December 6th 04 10:25 PM

On Mon, 06 Dec 2004 19:57:34 GMT, Richard Clark
wrote:

On Mon, 06 Dec 2004 18:03:47 GMT, (Robert Lay
W9DMK) wrote:

I finally created a test load that gives me the higher SWR that I
wanted.
It measures 7.0 - j2008 at 1.8 MHz. I placed that test load at the end
of a 150 foot piece of RG-59/U and measured the input impedance as
38.5 + j 151.6 at 1.8 MHz. The load SWR is 7901 and the input SWR is
10.18.

Solution of the transmission line equations for this particular load
and with coax characteristics of 73 ohms, VF = .646 and an attenuation
of 0.57 dB per 100 feet gives an input impedance of 38.67 + j 149,
which is a very good match to the measured value.

Losses are calculated using the same two methods as reported in my
previous posting, as follows:
1) ITT Reference Data for Radio Engineers, 5th Edition, pages 22-8 and
22-9.

2) The ARRL Antenna Book, 17 th Edition, page 24-9.


Matched line losses = 0.855 dB
Additional losses = 28.087 dB
Total losses = 28.942 dB

I am satisfied that the methods of calculating losses as described in
the two references are in agreement and are valid.

I am also reasonably satisfied that the 1 dB steps that are printed on
Smith Charts as the means of determining matched line losses are
valid, as are the nomograms provided in the ITT Handbook, pages 22-7
and 22-8, above.


Hi Bob,

Congratulations are in order for your effort at the bench, regardless
of outcome.

Congratulations are in order for your chain of reasoning, your
attention to detail, and the obvious refinement of technique that is
now agreeing not only with references, but is also consistent from one
test to the next.

I still see some aberration in the data when you have to drive the
cable Z to 73 Ohms to make the formulas work. It shows that the
generality of the references is good, but with the instance of your
data is a forced conclusion. I don't find that particularly upsetting
as the accumulation of error could easily account for some of the
differences.

You might want to revisit some of Bart's offerings in this thread;
especially his discussion of the effect of Low-R loads as a source of
Hi-Z, Hi-SWR.

73's
Richard Clark, KB7QHC


Dear Richard,

No - I didn't. That was a surprise to me, too! The specs on RG-59/U
say 73 ohms. There are 2 other RG-59 types - RG-59 Foam (75 ohms) and
RG-59A, also 73 ohms.

C'est la Guerre!

73,

Bob, W9DMK, Dahlgren, VA
http://www.qsl.net/w9dmk

Richard Clark December 6th 04 11:36 PM

On Mon, 06 Dec 2004 22:25:03 GMT, (Robert Lay
W9DMK) wrote:

No - I didn't. That was a surprise to me, too! The specs on RG-59/U
say 73 ohms. There are 2 other RG-59 types - RG-59 Foam (75 ohms) and
RG-59A, also 73 ohms.


Hi Bob,

You are, in the expression common here in the NW, whipsawing me with
your changes in cable type. I failed to catch that in your post.

Given you are using 73 Ohm line, your results are very remarkable.
I'm glad you've gone the distance. This group, however, exhibits a
very odd ethic that I would call the reverse Little Red Hen story.

Through more than 150 postings they all want to offer advice on how to
cut the grain; they will tell you where to mill it into flour; they
will offer you recipes on what to bake; but none seem to be around to
praise the chef or the cake.

73's
Richard Clark, KB7QHC

Robert Lay W9DMK December 7th 04 12:14 AM

On Mon, 06 Dec 2004 23:36:13 GMT, Richard Clark
wrote:

On Mon, 06 Dec 2004 22:25:03 GMT, (Robert Lay
W9DMK) wrote:

No - I didn't. That was a surprise to me, too! The specs on RG-59/U
say 73 ohms. There are 2 other RG-59 types - RG-59 Foam (75 ohms) and
RG-59A, also 73 ohms.


Hi Bob,

You are, in the expression common here in the NW, whipsawing me with
your changes in cable type. I failed to catch that in your post.

Given you are using 73 Ohm line, your results are very remarkable.
I'm glad you've gone the distance. This group, however, exhibits a
very odd ethic that I would call the reverse Little Red Hen story.

Through more than 150 postings they all want to offer advice on how to
cut the grain; they will tell you where to mill it into flour; they
will offer you recipes on what to bake; but none seem to be around to
praise the chef or the cake.

73's
Richard Clark, KB7QHC


Dear Richard,

Well, I only came here to share, so I'm not the least disappointed -
as some say, the pleasure is in the doing!

You might have asked why I changed coax.

I didn't feel that it would be as dramatic with only 17.5 ft of line.
So, I went to the barn and looked for the biggest, cleanest roll of
coax hanging on the wall, and that was it - Hi!

Bob, W9DMK, Dahlgren, VA
http://www.qsl.net/w9dmk

Richard Clark December 7th 04 12:37 AM

On Tue, 07 Dec 2004 00:14:28 GMT, (Robert Lay
W9DMK) wrote:

You might have asked why I changed coax.

I didn't feel that it would be as dramatic with only 17.5 ft of line.
So, I went to the barn and looked for the biggest, cleanest roll of
coax hanging on the wall, and that was it - Hi!


Hi Bob,

I didn't ask why because it was evident from the drama of results.
May as well force the numbers to expose the theory. I tried that with
my own thread when you started this one - it n'er came out as well as
yours. However, your confirmation of the loss does support my thesis,
even if my thread did not.

73's
Richard Clark, KB7QHC

Roy Lewallen December 7th 04 03:03 AM

I never did quite get clear about your thesis. Would you mind restating it?

Roy Lewallen, W7EL

Richard Clark wrote:

Hi Bob,

I didn't ask why because it was evident from the drama of results.
May as well force the numbers to expose the theory. I tried that with
my own thread when you started this one - it n'er came out as well as
yours. However, your confirmation of the loss does support my thesis,
even if my thread did not.

73's
Richard Clark, KB7QHC


Richard Clark December 7th 04 06:49 AM

On Mon, 06 Dec 2004 19:03:47 -0800, Roy Lewallen
wrote:
I never did quite get clear about your thesis. Would you mind restating it?


Source Z matters.

Frank December 7th 04 01:02 PM

"Richard Clark" wrote in message
...
On Mon, 06 Dec 2004 19:03:47 -0800, Roy Lewallen
wrote:
I never did quite get clear about your thesis. Would you mind restating
it?


Source Z matters.


What is the source Z of a solid state power amplifier, or even a tube
amplifier?

73,

Frank




Roy Lewallen December 7th 04 01:48 PM

Richard Clark wrote:
On Mon, 06 Dec 2004 19:03:47 -0800, Roy Lewallen
wrote:

I never did quite get clear about your thesis. Would you mind restating it?



Source Z matters.


Guess I didn't misunderstand after all -- it actually was so vague as to
be meaningless. Thanks for the elaboration.

Roy Lewallen, W7EL

Cecil Moore December 7th 04 02:46 PM


"Richard Clark" wrote:
Source Z matters.


The *magnitudes* and *phases* of Vfor and Vref are affected by Zs as
described by Chipman. But I don't find anything in Chipman's book to
indicate that the *ratio* of Vmax to Vmin (VSWR) is affected by Zs.

Perusing all the references to VSWR in Chipman's book, you will find
that the source is not mentioned at all. Only the load reflection
coefficient
and the transmission line characteristics are needed to calculate VSWR.
--
73, Cecil http://www.qsl.net/w5dxp



Reg Edwards December 7th 04 05:36 PM


Perusing all the references to VSWR in Chipman's book, you will find
that the source is not mentioned at all. Only the load reflection
coefficient
and the transmission line characteristics are needed to calculate VSWR.


===================================

Cecil, the trouble with 'bibles' is that they are so easily misquoted.
It's always better to rely only on your 'own' knowledge.

Only the MAGNITUDE of the reflection coefficient is needed to calculate SWR.
The phase angle is superfluous.

Nothing else whatever need be known about the line. Not even Zo, the
terminating impedance, and certainly not the generator impedance.

Conversely, the SWR will tell you virtually nothing about what's going on on
the line until you include and add to it what you already know anyway. You
can't even work back to find the reflection coefficint because of the loss
of the angle information.

The reflection coefficient is of no use to anybody without its angle,
except, of course to calculate the SWR.

Abolish SWR meters!
---
Reg.



Richard Clark December 7th 04 05:38 PM

On Tue, 07 Dec 2004 13:02:01 GMT, "Frank"
wrote:
What is the source Z of a solid state power amplifier


HI Frank,

Commonly 1.5 to 3 Ohms resistive transformed to 35 Ohms to 70 Ohms at
the Connector.

or even a tube amplifier?


Much greater variation here, X KOhms resistive transformed to 50 Ohms
at the connector.

Such are ballpark figures, as an average over a full cycle, at rated
power, for Class AB operation in a Push-Pull configuration. This
typically results in an efficiency on the order of 40% to 60%.

The nut of the matter about "Source Z matters" is that if your source
were at either of those untransformed Zs that are native to
transistors or tubes, then almost all their power would be reflected
back into them at the antenna connector's connection to a 50 Ohm
antenna system.

The argument of the matter about "Source Z matters" is that if your
source were at either of those untransformed Zs that are native to
transistors or tubes, then reflections from the load (once you got
some power into line) would encounter this same massive mismatch and
re-reflect. There is a naive argument here (all too common) that this
is "exactly" what happens. My pointed observation to those statements
is "why would anyone need a tuner then?"

The refinement of the matter about "Source Z matters" is that if your
source were at either of those untransformed Zs that are native to
transistors or tubes, then with any mismatch at the load you haven't
got a clue what power is being applied OR reflected. This is called
the Mismatch Uncertainty. It is another indicator of the failure of
the argument mentioned in the previous paragraph.

The relevance of the matter about "Source Z matters" here is that the
references that Bob used to measure and model line loss supports this
thesis. It presents an opportunity to observe how a line would suffer
additional loss through being mismatched at both ends. In this
regard, it would be due to the fictive argument for Source Z being
very much lower or very much higher than 50 Ohms (in other words,
lacking the transform circuitry commonly found in commercial gear).
When the loss is not observed, the fiction is shown.

73's
Richard Clark, KB7QHC

Frank December 7th 04 06:57 PM

Hi Richard,

With solid state power amplifier design; the criteria was always that you
must present an impedance, to the output devices, such that the desired
output power is delivered to the load (while not exceeding device
dissipation). Any attempt to optimally match the load to the source
impedance will result in over-dissipation, and probable destruction of the
source device -- probably by excess collector/drain current. If you
remember, Motorola used to publish Smith charts of the output impedance for
their power amplifier devices. Talking to one of Motorola's design
engineers; I asked "How do you derive these Charts". His answer was; "We
use a matching network and adjust it for the required output power, then
measure the input impedance of the network. The complex conjugate of this
impedance is then defined as the source Z". The fact is these data are not
the actual source Z of the device, but are probably considerable higher. I
don't remember anybody actually trying to measure the large signal S
parameters of solid state devices.

I seem to remember that tube amplifiers were designed based on the source
impedance calculated as 2Vp/Ip, (Where Vp is the plate voltage, and Ip the
plate current), and have no idea how, or if, it relates to the actual source
Z of the device. Anyway, I am not convinced that source Z is important.
Where I think some confusion may have come from is Hewlett Packard's 12 term
error correction analysis derived for vector network analyzers. Here source
Z is important because measurements are made in both directions.

I have some conceptual problems with standing waves, and reflected power,
although I know that the solution to the wave equation shows a forward and
reverse traveling wave. Both with uniform plane waves, and in wire
transmission lines. Transmission lines can also be analyzed as a simple
passive network without regard to "Reflected power".

I am sure you will rip my comments to shreds, that's ok, as I may learn
something.

73,

Frank


"Richard Clark" wrote in message
...
On Tue, 07 Dec 2004 13:02:01 GMT, "Frank"
wrote:
What is the source Z of a solid state power amplifier


HI Frank,

Commonly 1.5 to 3 Ohms resistive transformed to 35 Ohms to 70 Ohms at
the Connector.

or even a tube amplifier?


Much greater variation here, X KOhms resistive transformed to 50 Ohms
at the connector.

Such are ballpark figures, as an average over a full cycle, at rated
power, for Class AB operation in a Push-Pull configuration. This
typically results in an efficiency on the order of 40% to 60%.

The nut of the matter about "Source Z matters" is that if your source
were at either of those untransformed Zs that are native to
transistors or tubes, then almost all their power would be reflected
back into them at the antenna connector's connection to a 50 Ohm
antenna system.

The argument of the matter about "Source Z matters" is that if your
source were at either of those untransformed Zs that are native to
transistors or tubes, then reflections from the load (once you got
some power into line) would encounter this same massive mismatch and
re-reflect. There is a naive argument here (all too common) that this
is "exactly" what happens. My pointed observation to those statements
is "why would anyone need a tuner then?"

The refinement of the matter about "Source Z matters" is that if your
source were at either of those untransformed Zs that are native to
transistors or tubes, then with any mismatch at the load you haven't
got a clue what power is being applied OR reflected. This is called
the Mismatch Uncertainty. It is another indicator of the failure of
the argument mentioned in the previous paragraph.

The relevance of the matter about "Source Z matters" here is that the
references that Bob used to measure and model line loss supports this
thesis. It presents an opportunity to observe how a line would suffer
additional loss through being mismatched at both ends. In this
regard, it would be due to the fictive argument for Source Z being
very much lower or very much higher than 50 Ohms (in other words,
lacking the transform circuitry commonly found in commercial gear).
When the loss is not observed, the fiction is shown.

73's
Richard Clark, KB7QHC




Jim Kelley December 7th 04 08:24 PM



Richard Clark wrote:

This is called
the Mismatch Uncertainty.



The relevance of the matter about "Source Z matters" here is that the
references that Bob used to measure and model line loss supports this
thesis. It presents an opportunity to observe how a line would suffer
additional loss through being mismatched at both ends. In this
regard, it would be due to the fictive argument for Source Z being
very much lower or very much higher than 50 Ohms (in other words,
lacking the transform circuitry commonly found in commercial gear).
When the loss is not observed, the fiction is shown.


"It" should be called Grammatical Uncertainty.

73, AC6XG


Richard Clark December 7th 04 11:39 PM

On Tue, 07 Dec 2004 18:57:25 GMT, "Frank"
wrote:

"We
use a matching network and adjust it for the required output power, then
measure the input impedance of the network. The complex conjugate of this
impedance is then defined as the source Z". The fact is these data are not
the actual source Z of the device, but are probably considerable higher. I
don't remember anybody actually trying to measure the large signal S
parameters of solid state devices.


Hi Frank,

I've heard variations of this before, and other's admonitions that
Motorola admitted to a huge specification mistake in the early 90s and
had since mended their ways. When I asked for these updated
references, I ended up quoting verbatim from those mended teachings,
that, yes, Source Z has always been what was specified before
(...1990s), it was the same then (1990s), and it is the same now
(1990s...).

I've just returned from a nanotech seminar this afternoon whose
subject was organic thin film transistors. Dr. Daniel Frisbie -
Depts. of Chemical Engineering and Mat. Science - University of
Minnesota, offered that this new generation of research confirmed that
the Resistance of the transistor channel (similar to a MOSFET) easily
dominated all other sources of impedance. They also tested for
junction offsets (valence band - conduction band potentials) and found
they were negligible. The electron mobility wasn't the hottest thing
going (semiconducting carbon nanotubes easily dominate), but there
were no surprises. One of the EEs in the crowd easily allowed the
OTFTs showed no chemical/physical/electrical departures from
expectations (except for his concern for Schottky bias).

The technique you describe above is called a transfer standard.
Unless there is some mysterious shift in the space-time continuum to
account for this operation being invalid, it fully and accurately
describes the unit under test. Most arguments that lean on this
indirect measure being suspect would have us counting electrons
instead of using an Ammeter. Then we would argue about the counter
and its incapability of being a direct measure, but simply another
abstraction. Inevitably the arguments spiral down to the retort "you
are not going to change my mind."

I am already in the middle of the science that does real electron
counting, literally, where one can find what is called the Coulomb
barrier. For carbon nanotubes, things are so small that one electron
in a "wire" cannot allow another in with it to share the conductor.
Nothing like that is going on in our rigs.

73's
Richard Clark, KB7QHC

Frank December 8th 04 01:25 AM

Hi Richard, thanks for your comments. My contacts with Motorola were in the
late 80s, so does put it in the correct time frame, and does not surprise
me. I know I thought of it as a not very elegant method. The particular
device I was thinking of was a dual push-pull (could have been parallel)
module designed for about 200 - 500 MHz, at about 50 W. As far as I am
concerned Motorola has gone down hill since they used to produce those thick
RF device data books. Not to mention 4DTV. During that same period
everybody was using a technique known as "Load-pull" for power amplifier
design. I was also involved, though not very deeply, in the design of 100 W
to 1 kW HF solid state linear amps, where I was told the same story about
not attempting to actually match the bipolar devices, but simply present an
appropriate impedance to obtain the output power; otherwise the device
parameters will be exceeded. I am far from an expert in the field of power
amplifier design, but it would be interesting to know if high power
transistors are now characterized by large signal S parameters. This may
sound really dumb, but how about feeding 100 W back into a transistor
amplifier, and measuring the return loss. It would at least give you the
large signal magnitude of S22.

You are starting to loose me when it comes to semi-conductor physics, as it
was not a field that I was especially interested in. I think the only
journals that I may have read about "nanotubes" may have been Scientific
American. I have also never had any experience with power FETs.

73,

Frank


"Richard Clark" wrote in message
...
On Tue, 07 Dec 2004 18:57:25 GMT, "Frank"
wrote:

"We
use a matching network and adjust it for the required output power, then
measure the input impedance of the network. The complex conjugate of this
impedance is then defined as the source Z". The fact is these data are
not
the actual source Z of the device, but are probably considerable higher.
I
don't remember anybody actually trying to measure the large signal S
parameters of solid state devices.


Hi Frank,

I've heard variations of this before, and other's admonitions that
Motorola admitted to a huge specification mistake in the early 90s and
had since mended their ways. When I asked for these updated
references, I ended up quoting verbatim from those mended teachings,
that, yes, Source Z has always been what was specified before
(...1990s), it was the same then (1990s), and it is the same now
(1990s...).

I've just returned from a nanotech seminar this afternoon whose
subject was organic thin film transistors. Dr. Daniel Frisbie -
Depts. of Chemical Engineering and Mat. Science - University of
Minnesota, offered that this new generation of research confirmed that
the Resistance of the transistor channel (similar to a MOSFET) easily
dominated all other sources of impedance. They also tested for
junction offsets (valence band - conduction band potentials) and found
they were negligible. The electron mobility wasn't the hottest thing
going (semiconducting carbon nanotubes easily dominate), but there
were no surprises. One of the EEs in the crowd easily allowed the
OTFTs showed no chemical/physical/electrical departures from
expectations (except for his concern for Schottky bias).

The technique you describe above is called a transfer standard.
Unless there is some mysterious shift in the space-time continuum to
account for this operation being invalid, it fully and accurately
describes the unit under test. Most arguments that lean on this
indirect measure being suspect would have us counting electrons
instead of using an Ammeter. Then we would argue about the counter
and its incapability of being a direct measure, but simply another
abstraction. Inevitably the arguments spiral down to the retort "you
are not going to change my mind."

I am already in the middle of the science that does real electron
counting, literally, where one can find what is called the Coulomb
barrier. For carbon nanotubes, things are so small that one electron
in a "wire" cannot allow another in with it to share the conductor.
Nothing like that is going on in our rigs.

73's
Richard Clark, KB7QHC




Richard Clark December 8th 04 01:51 AM

On Wed, 08 Dec 2004 01:25:07 GMT, "Frank"
wrote:

I was told the same story about
not attempting to actually match the bipolar devices, but simply present an
appropriate impedance to obtain the output power; otherwise the device
parameters will be exceeded.


Hi Frank,

There used to be an old, old song: "Yes dear you can go swimming, but
don't go near the water."

Even at DC, you cannot design to the capacity of a transistor, because
the combination of all capacities exceed the "safe operating area."
However, this does nothing to actually change any noted specification.

I've never seen ANY power amplifier for retail trade conjugately
matched to its Source Z. But then I have never seen ANY amplifier for
retail trade designed to be low noise, low distortion, high stability,
or any of the more common qualities that "could be" designed in, if it
weren't for cost and the perception of no particular boon to the
purchaser. Who needed low distortion when you could throw a cheap
filter on the output? Who need low noise when atmospherics dominated
such issues? Who needed stability when the monkey twisting the knob
would correct it as a form of entertainment? Safety margin? Add a
fan to the heatsink - $pecial option.

This may
sound really dumb, but how about feeding 100 W back into a transistor
amplifier, and measuring the return loss. It would at least give you the
large signal magnitude of S22.


This was done decades ago - it is called an active load. I used to
calibrate them too. Guess what, it was specified and it met spec at
50 Ohms (and at least 100W).

73's
Richard Clark, KB7QHC

Ian White, G3SEK December 8th 04 09:01 AM

Frank wrote:
If you remember, Motorola used to publish Smith charts of the output
impedance for their power amplifier devices. Talking to one of
Motorola's design engineers; I asked "How do you derive these Charts".
His answer was; "We use a matching network and adjust it for the
required output power, then measure the input impedance of the network.
The complex conjugate of this impedance is then defined as the source
Z". The fact is these data are not the actual source Z of the device,


I had heard that also. For a typical VHF/UHF device, the manufacturer's
application engineers use an infinitely adjustable stub tuner to explore
the whole range of possible load impedances presented TO the device.

As well as measuring output power, the application engineer also has to
think about maximum voltage and current ratings, chip and bond wire
temperatures, and also IMD performance if the device is going to be
specified for linear operation.

The application engineer adjusts the load impedance to give the optimum
balance of all these factors, at a series of test frequencies. No
problems whatever about that.

The only technical issue is the *assumption* that the conjugate of the
load impedance is equal to the output impedance of the device. Most
manufacturers now tend to avoid that assumption, because it is a totally
unnecessary distraction for the transmitter designer who has to use the
device.

All the designer has to do is create an output network that presents the
manufacturer's recommended load impedance TO the device. This network
replicates the impedance transformation of the original stub tuner
setup, but uses mostly fixed components for obvious practical reasons.

Apart from a very few special applications where reverse termination is
important to avoid ghosting and similar effects, the transmitter
designer doesn't have to think about the device's output impedance at
all.



--
73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB)
http://www.ifwtech.co.uk/g3sek

Richard Harrison December 8th 04 02:56 PM

Ian White, G3SEK wrote:
"The only technical issue is the "assumption" that the conjugate of the
load impedance is equal to the output impedance of the device."

It`s true if maximum power is being transferred.

King, Mimno, and Wing sat so on page 43 of "Transmission Lines,
Antennas, and Wave Guides":

"If a dissipationless network is inserted betweeen a constant-voltage
generator of internal impedance Zg, and a load of impedance ZR such that
maximum power is delivered to the load, at every pair of terminals the
impedances looking in opposite directions are conjugates of each other."

The authors, Arnie, Larry, and Alex were all teaching at Harvard in 1945
when their book was published.

Walter Maxwell, W2DU has been saying the same thing yet has mistaken
nay-sayerrs.

Best regards, Richard Harrison, KB5WZI


Frank December 8th 04 03:51 PM

"Richard Harrison" wrote in message
...
Ian White, G3SEK wrote:
"The only technical issue is the "assumption" that the conjugate of the
load impedance is equal to the output impedance of the device."

It`s true if maximum power is being transferred.

King, Mimno, and Wing sat so on page 43 of "Transmission Lines,
Antennas, and Wave Guides":

"If a dissipationless network is inserted betweeen a constant-voltage
generator of internal impedance Zg, and a load of impedance ZR such that
maximum power is delivered to the load, at every pair of terminals the
impedances looking in opposite directions are conjugates of each other."

The authors, Arnie, Larry, and Alex were all teaching at Harvard in 1945
when their book was published.

Walter Maxwell, W2DU has been saying the same thing yet has mistaken
nay-sayerrs.

Best regards, Richard Harrison, KB5WZI


Maximum power transfer with conjugate matching is undisputed. The problem
with semi-conductor devices is that you cannot necessarily conjugate match
because the device operating parameters may be exceeded.

73,

Frank



Ian White, G3SEK December 8th 04 04:38 PM

Frank wrote:
"Richard Harrison" wrote in message
...
Ian White, G3SEK wrote:
"The only technical issue is the "assumption" that the conjugate of the
load impedance is equal to the output impedance of the device."

It`s true if maximum power is being transferred.

King, Mimno, and Wing sat so on page 43 of "Transmission Lines,
Antennas, and Wave Guides":

"If a dissipationless network is inserted betweeen a constant-voltage
generator of internal impedance Zg, and a load of impedance ZR such that
maximum power is delivered to the load, at every pair of terminals the
impedances looking in opposite directions are conjugates of each other."

The authors, Arnie, Larry, and Alex were all teaching at Harvard in 1945
when their book was published.

Walter Maxwell, W2DU has been saying the same thing yet has mistaken
nay-sayerrs.

Best regards, Richard Harrison, KB5WZI


Maximum power transfer with conjugate matching is undisputed. The problem
with semi-conductor devices is that you cannot necessarily conjugate match
because the device operating parameters may be exceeded.

Exactly.

Richard's assertion relies on at least three things being true:

1. That maximum power is being transferred - for most states of
transmitter tuning, loading and drive levels, that is obviously *not*
true.

2. That the transmitter can be accurately represented as a
"constant-voltage generator of internal impedance Zg", i.e. as a
Thevenin source.

3. That as part of #2, Zg is a constant.

With all due respect to Richard - and above all, respect to Walt - it is
a tall order to prove that all three of those requirements for conjugate
matching are being met. I believe they can only be exactly met under a
few very special sets of operating conditions.

But it then follows that, for all *other* operating conditions, the
complete end-to-end conjugate matching referred to by King et al does
*not* exist.


--
73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB)
http://www.ifwtech.co.uk/g3sek

Frank December 8th 04 04:46 PM

"Ian White, G3SEK" wrote in message
...
Frank wrote:
If you remember, Motorola used to publish Smith charts of the output
impedance for their power amplifier devices. Talking to one of Motorola's
design engineers; I asked "How do you derive these Charts". His answer
was; "We use a matching network and adjust it for the required output
power, then measure the input impedance of the network. The complex
conjugate of this impedance is then defined as the source Z". The fact is
these data are not the actual source Z of the device,


I had heard that also. For a typical VHF/UHF device, the manufacturer's
application engineers use an infinitely adjustable stub tuner to explore
the whole range of possible load impedances presented TO the device.

As well as measuring output power, the application engineer also has to
think about maximum voltage and current ratings, chip and bond wire
temperatures, and also IMD performance if the device is going to be
specified for linear operation.

The application engineer adjusts the load impedance to give the optimum
balance of all these factors, at a series of test frequencies. No problems
whatever about that.

The only technical issue is the *assumption* that the conjugate of the
load impedance is equal to the output impedance of the device. Most
manufacturers now tend to avoid that assumption, because it is a totally
unnecessary distraction for the transmitter designer who has to use the
device.

All the designer has to do is create an output network that presents the
manufacturer's recommended load impedance TO the device. This network
replicates the impedance transformation of the original stub tuner setup,
but uses mostly fixed components for obvious practical reasons.

Apart from a very few special applications where reverse termination is
important to avoid ghosting and similar effects, the transmitter designer
doesn't have to think about the device's output impedance at all.



--
73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB)
http://www.ifwtech.co.uk/g3sek


It seems everybody is in agreement with the fact that you cannot match a
power source to the load. As Ian states: "nobody cares, what the device
output parameters are, only that it is capable of delivering the required
power to a desired load". This still leaves the question unanswered as to
"What is the actual device S22"? I have read that "With HF linear devices
the large signal S parameters are close enough to the small signal values".
For non-linear devices load-pull techniques are used. I have never seen
high power transistors characterized with S parameters, but have not worked
with such designs for a number of years, so am probably out of touch. A
tentative search of the web did not find any info. It seems TRW and
Motorola are pretty much out of the power semi-conductor industry.

I am tempted to synthesize a transmission line based on the per-unit length
parameters, and see how the load power varies as a function of source Z. It
seems to me the only important factor is the applied voltage. The input
impedance is only a complex number. The transmission line could be
considered a "Singly terminated network", the synthesis of which is trivial,
and performance independent of source Z. I have trouble with the concept of
"Reflection"; how can charges (electrons) flow in both directions
simultaneously. Charge flow results from the E field within the conductor.

73,

Frank




Wes Stewart December 8th 04 05:13 PM

On Tue, 07 Dec 2004 18:57:25 GMT, "Frank"
wrote:

|Hi Richard,
|
|With solid state power amplifier design; the criteria was always that you
|must present an impedance, to the output devices, such that the desired
|output power is delivered to the load (while not exceeding device
|dissipation). Any attempt to optimally match the load to the source
|impedance will result in over-dissipation, and probable destruction of the
|source device -- probably by excess collector/drain current. If you
|remember, Motorola used to publish Smith charts of the output impedance for
|their power amplifier devices. Talking to one of Motorola's design
|engineers; I asked "How do you derive these Charts". His answer was; "We
|use a matching network and adjust it for the required output power, then
|measure the input impedance of the network. The complex conjugate of this
|impedance is then defined as the source Z". The fact is these data are not
|the actual source Z of the device, but are probably considerable higher.

The data were useful as presented. When using a Smith chart for
matching network design, the published data could be used as the
"starting point" for the network and the rotations were made toward
the load; the opposite from the usual case of matching a load to a 50
ohm source.

This method was really an early example of load pull characterization.
Maury Microwave app. note 5C-041 is one reference for this. Another
is "A New Load Pull Measurement Technique Eases GaAs
Characterization", Microwave Journal, Nov, 1980, pp. 63-67.

|I don't remember anybody actually trying to measure the large signal S
|parameters of solid state devices.

|I seem to remember that tube amplifiers were designed based on the source
|impedance calculated as 2Vp/Ip, (Where Vp is the plate voltage, and Ip the
|plate current), and have no idea how, or if, it relates to the actual source
|Z of the device.
|Anyway, I am not convinced that source Z is important.
|Where I think some confusion may have come from is Hewlett Packard's 12 term
|error correction analysis derived for vector network analyzers. Here source
|Z is important because measurements are made in both directions.

It's not the error correction that is confusing. The error correction
simply removes systematic errors from the measurement(s). The
parameters usually measured when 12-term correction is called for are
the small-signal S-parameters. If I understand you correctly, "source
Z" is actually the output reflection coefficient (s22), the signal
exiting port 2 due to an input to port 2.

The amplifier output reflection coefficient can be very important,
even in high power amplifiers, when non-dissipative filters are used
for harmonic or spurious rejection. Such filters are commonly
specified and measured in 50 ohm systems and function by reflecting,
not dissipating, the out-of-band energy. When driven by other than a
50 ohm source the rejection will be other than what is measured in a
matched condition.



Cecil Moore December 8th 04 05:28 PM

Frank wrote:
I have trouble with the concept of
"Reflection"; how can charges (electrons) flow in both directions
simultaneously.


Have you ever stood on a cliff overlooking the ocean and seen
ocean waves rolling in and smaller waves rolling back out? The
smaller waves rolling back out to sea are reflections of the
large waves incident upon the shore. The small outflowing wave
meets a large incoming wave and seems to disappear, only to emerge
on the ocean side of the large wave with its identity still intact.

If ocean waves can flow both directions using the same H2O carriers,
why would anyone have difficulty in accepting EM waves flowing
in both directions using the same electron carriers? The energy in
the ocean waves travels much faster than the water molecules. The
energy in an EM wave travels much faster than the electrons.

Ever played with a long rope fastened at one end? You can send a
wave down the rope and receive a reflected wave. If you time it
just right, you can have a forward wave and a reflected wave
meet in the middle of the rope and be unaffected by each other
as long as things remain linear. A forward EM wave has no effect
on a reflected EM wave and vice versa as long as things remain
linear.
--
73, Cecil http://www.qsl.net/w5dxp

Richard Clark December 8th 04 05:58 PM

On Wed, 08 Dec 2004 15:51:07 GMT, "Frank"
wrote:

Maximum power transfer with conjugate matching is undisputed. The problem
with semi-conductor devices is that you cannot necessarily conjugate match
because the device operating parameters may be exceeded.


Hi Frank,

If we return this from the ethereal landscape of sub meter
wavelengths, back to the point of Bob's measurements at HF, and lately
the MF; then matching and issues of the final are trivial with a
million examples in the market today.

I know you would probably like to get to the nut of this, and it will
return you to Motorola's AN1526. This work contains much of the
language offered by correspondents here (in times past), but through
the rather gauzy filter of their memory. Usually they couch the
disassociation of Source Z to a transistor through poor context (in
other words, not reading the entire subject, but just a phrase).

There is the presumption these posters embrace:
"They consider the best match is achieved by a simultaneous
conjugate match of the input and output. However, power amplifiers
provide higher power gain and better efficiency at the rated
output power if the output is purposely mismatched. An added
benefit of doing this is potentially unstable devices, conjugately
matched, can be operated stably under these more optimum
mismatched conditions."
This is the usual mistake of misattribution between the distinctions
of a Conjugate Match, and a Z Match. However, you will note that
here, and elsewhere in the reference, that no one denies the Source
has a Z, and it is significant (all within values I've offered) and
that it is still closely held to the expected load (later I will show
exactly held).

Another dismissal offered by posters is the supposed invalidity or
inaccuracy of the load-pull method (which I find curious after having
calibrated active loads suited for just this purpose). I will turn
again to this same reference:
"Although the technique has been known for some time, the
widespread availability of desktop computers and automatic tuning
systems is just now making this method more attractive,
particularly for higher power devices. The characterization
process is conceptually quite simple."

Then there is the subject of S parameters, which is introduced early
by Motorola with this admonition:
"Many first time RF power designers, brought up on a diet
of small–signal s–parameters, previously used for solving
small signal text book problems, assume these same
techniques are applicable to bipolar class–C and class–AB
power amplifier design."
This selection actually introduces the presumption above. We have one
poster here that violates this admonition with abandon - but with
regard to transmission lines.

When the poster pines further for a Large Signal S parameters:
"However, the authors are not aware of these parameters
being used successfully above a few watts of output power."

When Motorola actually gets down to design:
"The load line resistance is the optimum load impedance
for the internal collector node of the transistor, neglecting
the junction and parasitic device capacitance."
What a concept! Same as before, Same then, Same now.

The ONLY contretemps revealed by this tempest in a teapot is the
forced conclusion that a conjugate match was required (a common
mistake of not knowing the difference between Conjugate Matching and Z
Matching) which was in turn driven by higher frequency operation (much
of this is couched in the 900 MHz band) and parasitics already noted
above. The final and most compelling admission from Motorola is found
with their statement:
"It is up to the device designer to choose which
impedance gets published. One is just as valid as the other.
However, quite frankly, gain is what sells devices."

And of course this discussion will do nothing with those who utter
"you are not going to change my mind." ;-)

To be continued - no doubt.

73's
Richard Clark, KB7QHC

Richard Harrison December 8th 04 06:09 PM

Frank, WE6CB wrote:
"Maximum power transfer with conjugate matching is undisputed."

Great! W2DU has made progress.

Frank also wrote:
"The problem with semi-conductor devices is that you cannot necessarily
conjugate match because the device operating parameters may be
exceeded."

True for certain voltages, currents, and drive. The maxima may not all
be acheived simultaneously. It`s true for vacuum tube amplifiers too.
The total device dissipation can`t be exceeded without reduced life
expectancy.

Another caution is the difinition of "maximum available power". In an RF
amplifier this is specific to a certain set of operating conditions.
Maxium available power is with fixed B+ (or minus) voltage and drive.
Current, too, is limited to non-destructive values.

Terman says on page 76 of his 1955 edition:
"Alternatively, a load impedance may be matched to a source of power in
such a way as to make the power delivered to the load a maximum. (The
power delivered to the load under these conditions is termed the
avalable power of the power source.)"

Best regards, Richard Harrison, KB5WZI


Richard Harrison December 8th 04 07:09 PM

Frank wrote:
"I have trouble with the concept of "Reflection", how can charges
(electrons) flow in both directions simultaneously."

The wave, or signal flowing in one direction is distinctly different
from that flowing in the opposite direction. Upon reflection, the phase
between current and voiltage prodiuced by the wave is inverted. Only
phase of the volts or amps is inverted by reflection, not both. The
phase relation between volts and amps is the key to the direction the
wave is traveling on the line. It`s the wave which travels. The volts
and amps are generated by the wave traveling on the line. The line is
just guiding the wave.

The traveling forward and reflected waves, traveling in opposite
directions on the same line, produce the familiar standing wave patterns
through superposition of volts and amps. Transmission lines and the
appurtenances used with them have no problem keeping values associated
with the waves straight with proper design. A directional wattmeter can
separate the two directions of travel wery well indeed. It knows one
direction from the other by whether the volts and amps are in-phase or
out-of-phase.

Best regards, Richard Harrison, KB5WZI


Richard Harrison December 8th 04 08:26 PM

I quoted Terman, saying:
"The power delivered to the load under these conditions (a conjugate
match) is termed the AVAILABLE POWER of the power source."

The match between source and load is the best it can be and can`t be
improved when you have a conjugate match. A conjugate match is an
empowerment but does not cause you to put out any particular power.
That`s up to you.

Suppose you have a conjugate output match to a Class-B power amplifier
you are driving with your SSB transmitter. Instantaneously, average
power from the amplifier is following the modulation. A single steady
tone ideally produces a particular output at at one radio frequency.
Want more output? Increase drive to the amplifier. Want less? Reduce
drive to the amplifier. You may have a conjugate match under only one
condition, some conditions, or under all conditions, but given life`s
usuall imperfections, I would place no bets, except against all
conditions.

Best regards, Richard Harrison, KB5WZI


Richard Clark December 8th 04 09:18 PM

On Wed, 8 Dec 2004 20:55:18 +0000 (UTC), "Reg Edwards"
wrote:

and if that isn't enough, to further complicate matters, the
internal impedance of the transmitter changes as the load impedance is
varied


Hi Reggie,

Such arguments are as juvenile as the claim no one can travel a
straight line because the earth is rotating under them. A quadrillion
miles of experience would suggest this too is trivial to accomplish.

Aren't you the one who is so charmed with the legacy of Kelvinator who
chimed that such chimera without calculation are the chatter of chimps
in the forest canopy?

73's
Richard Clark, KB7QHC

Reg Edwards December 8th 04 09:32 PM

Just a comment -

The design, from start to finish, of a linear power amplifier is based
solely on a device's ratings - volts, amps, watts, etc.

Its RF internal impedance plays no part in it. At HF it is never specified
by the manufacturer.

Even ARRL bibles don't mention the subject of Rint. It's superfluous. Does
anybody know what it is? Give us some numbers.

As for conjugate matching - don't make me laugh.
---
Reg.



Reg Edwards December 8th 04 11:33 PM


Richard, you've slipped into one of your incoherent phases. Try again in a
few days time when you are feeling better. ;o)
----
Yours, Punchinello.




Richard Harrison December 9th 04 12:30 AM

Reg, G4FGQ wrote:
"The active device generally behaves as a current source."

As Reg also wrote:
"I can`t imagine why this conversation has continued for so many years
by more or less the same group of experts."

Agreed! Reg seems to have answered his own question.The same people
recite the same arguments in hopes their view of reality will be
accepted. Fat chance! Time has inured them.

Reg has faithfully proposed constant-current behaviour from all vacuum
valves and transistors as I recall. I agree that most of these devices
have extremely high plate ond collector resistances as linear
amplifiers. Current through them is almost constant regardless of anode
voltage.

As most transmitter power amplifiers exceed 50% efficiency by a good
margin, these devices are not operating as Class-A linear amplifiers.
They instead operate as HF switches. These are turned-off most of every
cycle and are only on for short pulses. Harmonics and other noise is
cleaned up by output filters. It`s the only thing which makes the output
linear.

During the output device`s conduction, its saturation volts are very low
and its current is very high, giving the device a very low impedance
while switched-on. You may not infer a low impedance from the d-c volts
and amps feeding the final amplifier. These are the averages, almost, of
the device amps. The device saturation volts sre what counts toward its
dissipation and loss. The transmitter usually has no built-in indicator
of saturation voltage. It wouldn`t read much anyway.Device
impedance depends mostly on its ratio of off to on times. This is a form
of lossless resistance. Dissipation is zero in a sewitched-off device.
The d-c volts and amps are related to the output device(s) internal
impedances used as a switch when the transmitter output is considered. A
high voltage and a low current accompany a high internal impedance but
they won`t be nearly so high as the spec sheet plate or collector
resistances.

We have d-c power input to the amplifier. We can measure HF power
output. The difference is dissipation, but loss resistance does not
represent the total source resistance because we have non-dissipative
resistance in the device off-times.

There have been measurements of transmitter internal output impedances
which indicated that they did indeed match their loads. I have not done
it myself but have no reason to doubt the reports.

Best regards, Richard Harrison, KB5WZI



All times are GMT +1. The time now is 09:06 PM.

Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
RadioBanter.com