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#1
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It's important not to confuse the sort of pulses or steps used in TDR
with transient sine wave conditions. It's perfectly valid to derive the sinusoidal steady state conditions on a transmission line by looking at the transient conditions that occur from the time the source is first turned on. And because of the transient nature of the signal, the most practical way to approach this analysis is in the time domain. TDR also (obviously) involves time domain analysis. But it's quite different. Sinusoidal transient analysis assumes a sinusoidal source that stays on once it's turned on. But TDR involves either a pulse type source that's off when the pulse reflection returns, or a step type source that provides a DC step to the transmission line. In this case, the source voltage is a stable DC value from the time of the initial step. In the case of the sinusoidal source, the source voltage continues changing while the transients are propagating. In both cases, the sum of all forward and reflected voltages or currents have to sum to the correct values at all points, and this knowledge can be used to derive various wave components. But the results and some of the methods can be very different for the two cases. For example, when a reactive load or impedance bump is present, a simple reflection coefficient can be calculated for the sine wave, based on the reactance at the sine wave's frequency. The reflected wave will be a simple replica of the incident wave, altered only in phase and amplitude. You can't do this with a pulse or step; a reactive load changes its shape, defying a simply defined reflection coefficient. (Some confusion arises because of the use in TDR of a reflection coefficient, usually denoted rho. It's the same as the magnitude of the sine wave reflection coefficient -- but only if the anomaly or load causing the reflection is purely resistive and a constant value from DC or a low frequency up to the equivalent maximum frequency contained in the TDR pulse and viewable with the TDR system. With some TDR systems having equivalent bandwidths of over 50 GHz, this can be an onerous requirement.) Another important difference is what happens to a returning wave when it reaches the source -- reaction to a source that's off, at a stable DC value, or at some point in the cycle of a sinusoidal waveform is different. TDR is a very valuable technique, providing important information and illuminating insights about transmission line phenomena. But great care has to be taken in extrapolating TDR observations to what happens in a sinusoidal transient or steady state environment. As readers have seen, I'm very wary of explanations of sinusoidal phenomena, either steady state or transient, that depend on drawing parallels to TDR results. You should be, too. Roy Lewallen, W7EL W5DXP wrote: Tdonaly wrote: I would like to know why Cecil, for instance, uses pulses, as in a TDR, in order to argue a steady state point. Do steady-state signals obey one set of laws of physics and pulses obey a different set of laws of physics? You seem to feel so but I just don't have that much faith! The useful steady-state shortcuts have developed into a religion that has no place in science. I am not opposed to steady-state shortcuts. I am opposed to the steady-state religion that has evolved based on faith. "Have faith, there is no such thing as reflected waves." "Have faith, photons can be exchanged between equivalent inductors and capacitors in a transmission line so they move sideways at less than the speed of light instead of lengthways at the speed of light." Particle physicists would really be interested in any proof of that. "Have faith, a V/I ratio is identical to a physical impedance because a source, with an IQ of zero, cannot tell the difference." "Reflections completely disappear the instant that steady-state conditions are reached." There are many more faith-based characteristics of the steady-state model. These are just the ones that come to mind. |
#2
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Roy Lewallen wrote:
It's important not to confuse the sort of pulses or steps used in TDR with transient sine wave conditions. Why? Do they obey different laws of physics? TDR also (obviously) involves time domain analysis. But it's quite different. Why? Does a TDR obey a different set of physics laws? The reflected wave will be a simple replica of the incident wave, altered only in phase and amplitude. Not if it contains random noise and all waves contain random noise. TDR is a very valuable technique, providing important information and illuminating insights about transmission line phenomena. But great care has to be taken in extrapolating TDR observations to what happens in a sinusoidal transient or steady state environment. Why? Does a TDR obey a different set of physics laws than sine waves? -- 73, Cecil http://www.qsl.net/w5dxp "One thing I have learned in a long life: that all our science, measured against reality, is primitive and childlike ..." Albert Einstein -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
#3
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Did you really read what I wrote?
Roy Lewallen, W7EL W5DXP wrote: Roy Lewallen wrote: It's important not to confuse the sort of pulses or steps used in TDR with transient sine wave conditions. Why? Do they obey different laws of physics? TDR also (obviously) involves time domain analysis. But it's quite different. Why? Does a TDR obey a different set of physics laws? The reflected wave will be a simple replica of the incident wave, altered only in phase and amplitude. Not if it contains random noise and all waves contain random noise. TDR is a very valuable technique, providing important information and illuminating insights about transmission line phenomena. But great care has to be taken in extrapolating TDR observations to what happens in a sinusoidal transient or steady state environment. Why? Does a TDR obey a different set of physics laws than sine waves? |
#4
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I think the steady state solution would be a lot more palatable if the
analysis started at T=0, when you turn the source on. The extra step of seeing how you reach steady state makes the latter more "real". One could almost be convinced that there are no reflections in the steady state; problem is , there would be no other explanation for standing waves, and I can measure them with unambiguous instruments. Tam/WB2TT |
#5
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Tarmo Tammaru wrote:
I think the steady state solution would be a lot more palatable if the analysis started at T=0, when you turn the source on. The extra step of seeing how you reach steady state makes the latter more "real". One could almost be convinced that there are no reflections in the steady state; problem is , there would be no other explanation for standing waves, and I can measure them with unambiguous instruments. I keep wondering what laws of physics get repealed just as the system transitions to steady-state. Do photons really start moving from side to side instead of end to end? Do the standing waves magically sustain themselves without any reflected waves? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
#6
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Tarmo Tammaru wrote:
there would be no other explanation for standing waves, May I suggest that you consider charge. Consider how static charge can store energy in the capacitance of the line. Consider how moving charge can store energy in the inductance of the line. Consider how the charge moves to change the energy distribution within the line. Do it for a pulse of charge; then for multiple pulses. Consider what happens when the pulses collide; consider pulses of the same polarity and different. Do it for a step of charge; then make the step so long it looks like DC. Do it for sinusoids. Do it for opens, shorts and terminated lines. Do it for matched, unmatched and disconnected sources (disconnect just after injecting the pulse, step or sinusoid). Do it for sources at both ends of the lines. And soon you will have an explanation which does not require waves travelling up and down the line to explain the observed voltages and currents of the standing 'wave'. ....Keith |
#7
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wrote:
And soon you will have an explanation which does not require waves travelling up and down the line to explain the observed voltages and currents of the standing 'wave'. Yes, soon you will have some mathematical shortcuts. But do mathematical shortcuts really cause photons to flow sideways between an equivalent capacitance and an equivalent inductance? Can you describe a bench experiment where photons are transferred from a capacitor to an inductor and back? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
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