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Old July 21st 03, 04:43 AM
Tarmo Tammaru
 
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I think the steady state solution would be a lot more palatable if the
analysis started at T=0, when you turn the source on. The extra step of
seeing how you reach steady state makes the latter more "real". One could
almost be convinced that there are no reflections in the steady state;
problem is , there would be no other explanation for standing waves, and I
can measure them with unambiguous instruments.

Tam/WB2TT


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Old July 21st 03, 05:36 AM
W5DXP
 
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Tarmo Tammaru wrote:
I think the steady state solution would be a lot more palatable if the
analysis started at T=0, when you turn the source on. The extra step of
seeing how you reach steady state makes the latter more "real". One could
almost be convinced that there are no reflections in the steady state;
problem is , there would be no other explanation for standing waves, and I
can measure them with unambiguous instruments.


I keep wondering what laws of physics get repealed just as the system
transitions to steady-state. Do photons really start moving from side
to side instead of end to end? Do the standing waves magically sustain
themselves without any reflected waves?
--
73, Cecil http://www.qsl.net/w5dxp



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Old July 21st 03, 06:24 AM
 
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Tarmo Tammaru wrote:
there would be no other explanation for standing waves,


May I suggest that you consider charge.
Consider how static charge can store energy in the capacitance of the
line.
Consider how moving charge can store energy in the inductance of the
line.
Consider how the charge moves to change the energy distribution within
the line.
Do it for a pulse of charge; then for multiple pulses.
Consider what happens when the pulses collide; consider pulses of the
same polarity and different.
Do it for a step of charge; then make the step so long it looks like DC.
Do it for sinusoids.
Do it for opens, shorts and terminated lines.
Do it for matched, unmatched and disconnected sources (disconnect just
after injecting the pulse, step or sinusoid).
Do it for sources at both ends of the lines.

And soon you will have an explanation which does not require waves
travelling up and down the line to explain the observed voltages and
currents of the standing 'wave'.

....Keith
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