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#1
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By way of agreeing with what Reg posted about capacitance indirectly
adding to the loss, consider that for any TEM line (twin-lead and coax being two examples), the impedance, Zo, is sqrt(L/C), and the propagation delay, tau, is sqrt(LC) [neglecting the very small contribution of R and G for practical lines at HF and above]. From these two, you can see that C=tau/Zo. If the velocity factor is unity, then tau for a foot of line is one foot divided by the speed of light, about 1.017 nanoseconds. If Zo is 50 ohms, then C for that line would be 20.33pF/foot. If you have line which you know to be 50 ohms and 31.0pF/foot, then you know the v.f. is 20.33/31.0 = 0.656, and by my other recent posting in this thread, you know that its attenuation will be about 1/0.656 = 1.52 times as many dB/unit length as the same line with air dielectric (which would be 50 ohms times 1.52 = 76 ohms). (The interrelation of tau, Z, C, L, line physical length and velocity factor suggests that you can determine Z, for example, by measuring C and v.f. accurately. Some line configurations let you accurately measure conductor diameters as well. You end up with lots of ways to determine a set of line parameters.) But note that a 50 ohm air dielectric coax using the same outer conductor diameter would have a larger inner conductor, but MORE loss than the 76 ohm air dielectric line because of the higher capacitance. Quantitatively, it will have about 1.1 times the dB/unit length loss compared with the 76 ohm line...so the difference in loss between air inslated 50 ohm line and solid polyethylene dielectric 50 ohm line (same OD) will be a ratio of 1.1:1.52, or 1:1.38. Going from 50 ohm line insulated with solid pe to 50 ohm line of the same OD with air insulation will cut the dB loss by about 27%. Going from solid to foamed pe will get you about half that much. There's a bigger effect going from a solid pe 75 ohm line to an air dielectric 75 ohm line, cutting the dB loss by over 42% (assuming I didn't screw up the calcs too badly). Cheers, Tom |
#2
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"Hal Rosser" bravely wrote to "All" (04 Apr 05 20:48:04)
--- on the heady topic of "VF, low-loss line, high-impedence line - = relationship" HR Reply-To: "Hal Rosser" HR Xref: aeinews rec.radio.amateur.antenna:27947 HR I've noticed, (but have not studied), some loose relationships in HR transmission line characteristics (and I guess waveguides fit in HR here). From an observer's point of view, it seems that a high HR characteristic impedence line (like 400-ohm or 600-ohm ladder line) HR also is usually a lower-loss line, and has a higher velocity factor. HR It also seems that some coax may have a low VF and high loss. HR Is there a real cause for the relationship of these 3 characteristics HR of transmission lines ? Is it something we can generalize ? HR It makes some sense to say that the faster a signal gets through the HR line, the less loss it will have - and that gives some credence to the HR relationship in VF and loss being inversely associated. You are right there is a connection between wire diameter and spacing. It has to do with the self inductance and resistive losses of two conductors in proximity. By contrast a balanced line has a wider spacing and also allows part of the energy to travel unhindered, so to speak. It helps if the balanced line is designed to be close to the theoretical impedance of free space. The price to pay is that it is more susceptible to the environment. The loss in coax is a trade off to achieve stability. A*s*i*m*o*v .... "Beware of all enterprises that require new clothes." -- THOREAU |
#3
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Asimov wrote:
You are right there is a connection between wire diameter and spacing. It has to do with the self inductance and resistive losses of two conductors in proximity. By contrast a balanced line has a wider spacing and also allows part of the energy to travel unhindered, so to speak. Conductors don't "hinder" the traveling of energy. Energy travels just as well along close spaced conductors as it does along wide spaced ones. In fact, loss due to radiation is greater with wider spacing than narrow (although it's still negligible with the lines typically used). It helps if the balanced line is designed to be close to the theoretical impedance of free space. Please explain in what way it "helps". No equation, formula or theoretical treatment I'm aware of shows any advantage, change, or anomaly in tranmission line behavior at a value equal to or near the characteristic impedance of free space. (As has been pointed out many times before in this newsgroup, the impedance of free space is the ratio of E/H fields in a plane wave; the impedance of a transmission line is the ratio of voltage to current of a traveling wave. Although they have the same unit of measure, they're different things -- like foot-pounds of work and foot-pounds of torque.) The price to pay is that it is more susceptible to the environment. Do you mean that lines of approximately 377 ohms impedance are more susceptible to the environment than 200 or 600 ohm lines? In what ways? Why? The loss in coax is a trade off to achieve stability. Coax is more stable than open wire line? Does open wire line drift in some way? A*s*i*m*o*v ... "Beware of all enterprises that require new clothes." -- THOREAU Roy Lewallen, W7EL |
#4
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"Roy Lewallen" wrote
Energy travels just as well along close spaced conductors as it does along wide spaced ones. In fact, loss due to radiation is greater with wider spacing than narrow ====================================== In fact, the field radiated from correctly balanced twin or open-wire lines is directly proportional to wire spacing. Radiation resistance is the same as a monopole of the same length as the wire spacing in terms of wavelength. Rr even at VHF is quite small. Radiation is off the ends - i.e., in the same direction as the line. Polarisation is in the same direction as the wires are spaced. And, believe it or not, all is independent of the length of the line. ---- Reg, G4FGQ |
#5
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Reg Edwards wrote:
And, believe it or not, all is independent of the length of the line. How much does an infinitessimally short line radiate? :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#6
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Cecil,
Almost as much as a "full length" line, if you can feed the power to it. For details check your favorite antenna book. 73, Gene W4SZ Cecil Moore wrote: Reg Edwards wrote: And, believe it or not, all is independent of the length of the line. How much does an infinitessimally short line radiate? :-) -- 73, Cecil http://www.qsl.net/w5dxp |
#7
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On Thu, 07 Apr 2005 09:09:51 -0500, Cecil Moore
wrote: Reg Edwards wrote: And, believe it or not, all is independent of the length of the line. How much does an infinitessimally short line radiate? :-) Sterba and Feldman in "Transmission Lines for Short-Wave Radio Systems", Proceedings of the IRE, Volume 20, No 7., July, 1932 give a formula for the radiated power in a balanced line. The line length *is* a factor, however, they give a simplified approximation for the case of a length more than 20 times the line spacing and the line spacing less than 1/10 lambda. P/I^2 = 160 * ( pi * D / lambda)^2 whe P is in watts I is the RMS current in a matched line D / lambda is the wire spacing in wavelengths |
#8
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"Cecil Moore" asks - Reg Edwards wrote: And, believe it or not, all is independent of the length of the line. How much does an infinitessimally short line radiate? :-) ============================ Cec, you took the bait. So just exercise a teeny bit of your imagination. Suppose you have a generator directly connected to a load resistance without any line in between. Let the generator and load terminals both be spaced apart by the same distance as the conductors of the non-existent line. The load carries a current along a length equal to the spacing between its terminals. The load, by virtue of its length, possesses radiation resistance. And so radiation occurs with zero line length. Even a CB-er can understand the obvious. Can you calculate radiating efficiency? ---- Reg, G4FGQ |
#9
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"Roy Lewallen" bravely wrote to "All" (06 Apr 05 22:10:02)
--- on the heady topic of " VF, low-loss line, high-impedence line - = relationship" RL From: Roy Lewallen RL Xref: aeinews rec.radio.amateur.antenna:28064 RL Do you mean that lines of approximately 377 ohms impedance are more RL susceptible to the environment than 200 or 600 ohm lines? In what RL ways? Why? Since a portion of the EM field in open wire line is free to travel outside the conductor into the environment then we may safely assume there is an exchange between the environment and the conductor. If the impedance of each is approximately the same then there is less loss in the interface between the two. It has to do with the reflective coefficient where the energy is returned. You will note 300 ohm open line has less loss than 100 ohm open line. RL The loss in coax is a trade off to achieve stability. RL Coax is more stable than open wire line? Does open wire line drift in RL some way? It is susceptible to ambient humidity and proximity to conductive objects (birds, snow, rfi). That is a source of drift in practical terms. A*s*i*m*o*v .... No individual raindrop ever considers itself responsible for the flood |
#10
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Asimov wrote:
Since a portion of the EM field in open wire line is free to travel outside the conductor into the environment then we may safely assume there is an exchange between the environment and the conductor. If the conductors are perfectly conducting, no part of the field at all exists within the conductor. With good conductors like copper and at HF and above, there's very little penetration of the conductor by the fields, either electric or magnetic. As far as an "exchange" goes, it sounds like you're trying to describe radiation. If not, what's the phenomenon you're referring to? If the impedance of each is approximately the same then there is less loss in the interface between the two. No, that's not true. First of all, a mismatch doesn't cause loss. Secondly, as I explained in my last posting, the characteristic impedance of a transmission line isn't the same thing as the characteristic impedance of free space. If you were to construct a transmission line with 377 ohms characteristic impedance (numerically the same as the characteristic impedance of free space), the ratio of E/H fields between the conductors probably won't be anywhere near 377 ohms, as it is in a plane wave propagating without wires. It has to do with the reflective coefficient where the energy is returned. Well, no. There isn't a bundle of energy trying to escape the line and bouncing off the air, or bouncing off the air as it travels along the line, or bouncing off the conductors into the air. So reflection coefficient isn't applicable here. You will note 300 ohm open line has less loss than 100 ohm open line. Yes, and 600 ohm line has less loss than 377 ohm line. You'll have to find a way to fit this into your theory if you want to pursue it. RL The loss in coax is a trade off to achieve stability. RL Coax is more stable than open wire line? Does open wire line drift in RL some way? It is susceptible to ambient humidity and proximity to conductive objects (birds, snow, rfi). That is a source of drift in practical terms. Thanks for the clarification. Because the differential fields are completely confined within a coaxial cable, they are indeed more immune to external influences. I'm afraid that the conclusions you've reached about loss and characteristic impedance are based on a poor understanding of fundamental transmission line operation. The result is some conclusions that are, and are well known to be, untrue. If you really feel that you have a viable theory, you should be able to provide some equations and formulas to quantify the extra loss you're talking about. The existing theory, formulas and equations, in daily use for over a hundred years, have been shown countless times to accurately predict transmission line loss, and they don't include the phenomena you're describing. So although I think it's highly doubtful that your formulations will prove more accurate, if you post them they can pretty easily be tested by actual cable measurement. Roy Lewallen, W7EL |
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