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Cecil Moore wrote:
Ian White GM3SEK wrote: Roy has posed a test problem that is very easy to understand, and can be solved unambiguously by simple arithmetic. Solving it using S-parameters will take time and some depth of understanding, but we can be confident that they WILL give exactly the same result in the end. It's not Roy's results that are flawed. It's his premises. If one has a 100v source with a 50 ohm series impedance feeding a 200 ohm resistor, Roy's results are perfect. But when we add that 1/2WL of 200 ohm line, it changes things from a circuit analysis to a distributed network analysis. Much more energy is stored in the system, using the transmission line, than has reached the load during steady-state. Roy tries to completely ignore the stored energy and alleges that there is no energy in the reflected waves. But there is *exactly* the same amount of energy stored in the feedline as is required for the forward waves and reflected waves to posssess the energy predicted by the classical wave reflection model or an S-parameter analysis or an analysis by Walter Maxwell of "Reflections" fame. . . . Ah, the drift and misattribution has begun. I'll butt in just long enough to steer it back. I made no premises, and have not made any statement about energy in reflected waves. I only reported currents and powers which I believe are correct. Nothing you or anyone has said has indicated otherwise. I do question the notion of bouncing waves of average power, and have specifically shown that H's statement about the source resistor absorbing all the reflected power, when its value is equal to the line impedance, is clearly false. (The "reflected power" is 18 watts; the resistor dissipates 8.) I haven't seen any coherent explanation of the observable currents and power dissipations that's consistent with the notion of bouncing current waves. Perhaps your dodging and hand-waving has convinced someone (the QEX editor?), but certainly not me. It's not a 200 ohm line, it's a 50 ohm line. (I see that I neglected to state this when giving my example, and I apologize. But it can be inferred from the load resistance and SWR I stated.) It baffles me how you think you can calculate the line's stored energy without knowing its time delay. The calculation of stored energy is simple enough, but it requires knowledge of the line's time delay. A half wavelength line at 3.5 MHz will store twice as much energy as a half wavelength line at 7 MHz, all else being equal. Even if you knew the frequency (which I didn't specify), you'd also need to know the velocity factor to determine the time delay and therefore the stored energy. I'm afraid your methods of calculating stored energy are in error. But if you think the stored energy is important and you find (by whatever calculation method you're using) that it's precisely the right value to support your interesting theory, modify the example by doubling the line length to one wavelength. The forward and reverse powers stay the same, power dissipation in source and load resistors stay the same, impedances stay the same -- there's no change at all to my analysis or any of the values I gave. But the energy stored in the line doubles. (Egad, I hope your stored energy calculation method isn't so bizarre that it allows doubling the line length without doubling the stored energy. But I guess I wouldn't be surprised.) So if the stored energy was precisely the right amount before, now it's too much by a factor of two. And if you find you like that amount of stored energy, double the line length again. I can see why you avoid the professional publications. Roy Lewallen, W7EL |
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