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#1
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Wes Stewart wrote:
On 23 Jun 2005 12:29:51 -0700, "Brian Kelly" wrote: Oliver Gebele wrote: Hi, i am using a Collins-Filter with 2 variable capacitors and a switched inductor (Pi). Obviously there are infinitely many possibilities to match an antenna.Are there any preferred possibilities? And how would i adjust my box to do this? (Maybe there are already links on the internet that i did not find.) Inductors are lossy. Capacitors are not. Use the tuner settings which provide a 2:1 VSWR match or better with the least possible amount of inductance. In other words use the least amount of inductance you can get away with. Let's examine this statement. First all should note that this is a pi-network. Suggestions to use an MFJ (tee-network) tuning procedure are wrong. Here is a random example made up on the spur of the moment. Assume the load is 20 +j50 @ 14 MHz. SWR = 5.2 Also assume that the tuning capacitor(s) Q = 500 and the inductor Q = 200, both typical values. A nearly optimum solution, from a match and loss standpoint is: Cin = 140.3 pF, L = .958 uH, Cout = 333.6 pF. The input z = 49.69 +j0.03 or SWR = 1.006 , Loss = 0.09 dB. Now, let's force the inductance to a lower value. Cin = 422 pF, L = 0.67 uH, Cout = 471.3 pF. The input Z = 49.6 -j0.04 or SWR = 1.008 but the loss = 0.18 dB. The loss doubled when the inductance was lowered. All of this is easily calculated using a free tool: XLZIZL.xls. (1) Physics must have changed, I guess I missed the revisions. (2) Doesn't matter because old wives tales trump physics every time. (3) The bloomin' file won't run in my version of Excel. I missed those revisions too. sigh w3rv |
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#2
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On 24 Jun 2005 06:00:55 -0700, "Brian Kelly" wrote in
reply to my comments: [snip] (1) Physics must have changed, I guess I missed the revisions. I don't recall any changes. The pi (and tee and other) network(s), having three reactances, allow(s) the operating Q to be set by the choice of component values. Efficiency is a function of the ratio of operating (loaded) Q and the unload Q of the components. For a single reactor it is: eff = Qu / (Qu + Ql) Clearly, for highest efficiency (lowest loss) you want high unloaded Q(s) and a minimum loaded Q. By reducing the inductance below an optimum value, the unloaded network Q was increased, resulting in lower efficiency. (2) Doesn't matter because old wives tales trump physics every time. Not sure what this means. (3) The bloomin' file won't run in my version of Excel. I missed those revisions too. I thought my software was behind the times. |
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#3
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Wes Stewart wrote:
"Brian Kelly" wrote: (1) Physics must have changed, I guess I missed the revisions. I don't recall any changes. Planck's Constant rendered Maxwell's Equations discontinuous. :-) -- 73, Cecil, http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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#4
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On Fri, 24 Jun 2005 09:46:39 -0500, Cecil Moore wrote:
Wes Stewart wrote: "Brian Kelly" wrote: (1) Physics must have changed, I guess I missed the revisions. I don't recall any changes. Planck's Constant rendered Maxwell's Equations discontinuous. :-) Heisenberg suspected so, but he was uncertain. |
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#5
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"Bob Nielsen" wrote in message news ![]() On Fri, 24 Jun 2005 09:46:39 -0500, Cecil Moore wrote: Wes Stewart wrote: "Brian Kelly" wrote: (1) Physics must have changed, I guess I missed the revisions. I don't recall any changes. Planck's Constant rendered Maxwell's Equations discontinuous. :-) Heisenberg suspected so, but he was uncertain. Schroder said he had to look to be sure. |
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#6
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Bob Nielsen wrote:
SNIPPED Heisenberg suspected so, but he was uncertain. Could Heisenberg be certain that Heisenberg was Heisenberg? Was he certain that the Uncertainty Principle was in itself certain? Damn, Physics and Philosophy getting all mixed up! VSWR is real! Deal with it. VSWR isn't a REAL problem! Deal with it! VSWR is real and ENGINEERS and Ham Radio operators make transmission lines and antennas work; while Physicists wonder if it's real or uncertain. [My 80 meter antenna has a VSWR of 30:1. It works just fine!] |
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#7
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VSWR isn't a REAL problem! Deal with it! VSWR is real and ENGINEERS and Ham Radio operators make transmission lines and antennas work; while Physicists wonder if it's real or uncertain. [My 80 meter antenna has a VSWR of 30:1. It works just fine!] ===================================== Anything will work after a fashion. It's no proof of anything. It is not realised by many amateurs and engineers that the so-called SWR meter does not measure SWR. It merely indicates whether or not the transmitter is loaded with its design resistance. Which, of course, is useful. The meter not located in the right place to measure SWR on the feedline. The feedline on which it is imagined SWR is measured does not exist. To measure SWR on any line a moving voltmeter is required. SWR is simply max volts divided by min volts which occur at a distance apart of 1/4-wavelength if the line is long enough, and requires no knowledge of line impedance or its terminating impedances, or of anything else about the line. In other words, SWR is just something for Old Wives and "clever" people to plagiarise and waffle about, on newsgroups and in the magazines, and so continue to mislead themselves together with the unfortunate learners, CB-ers, and the novices. ---- Reg, G4FGQ |
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#8
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"Reg Edwards" wrote in message ... VSWR isn't a REAL problem! Deal with it! VSWR is real and ENGINEERS and Ham Radio operators make transmission lines and antennas work; while Physicists wonder if it's real or uncertain. [My 80 meter antenna has a VSWR of 30:1. It works just fine!] ===================================== Anything will work after a fashion. It's no proof of anything. It is not realised by many amateurs and engineers that the so-called SWR meter does not measure SWR. It merely indicates whether or not the transmitter is loaded with its design resistance. Which, of course, is useful. The meter not located in the right place to measure SWR on the feedline. The feedline on which it is imagined SWR is measured does not exist. To measure SWR on any line a moving voltmeter is required. SWR is simply max volts divided by min volts which occur at a distance apart of 1/4-wavelength if the line is long enough, and requires no knowledge of line impedance or its terminating impedances, or of anything else about the line. In other words, SWR is just something for Old Wives and "clever" people to plagiarise and waffle about, on newsgroups and in the magazines, and so continue to mislead themselves together with the unfortunate learners, CB-ers, and the novices. ---- Reg, G4FGQ ================================ In other words, ENGINEERS make transmission lines and antennas work by copying what was done last time. Nothing has changed since Oliver Heaviside, 1875 - 1925. If anybody mentions G5RV I shall cry. ---- Reg, G4FGQ |
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