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On Sat, 02 Jul 2005 08:21:07 -0500, Cecil Moore
wrote: The first example was much too easy. How about this one? ---50 ohm feedline---+---300 ohm feedline--- Pfwd1=100w-- Pfwd2 not given-- --Pref1=0w --Pref2 not given Given a Z0-match at point '+': Solve for Vfwd1, Ifwd1, Vref1, Iref1, Pfwd2, Vfwd2, Ifwd2, Pref2, Vref2, Iref2, including magnitudes and phase angles for all voltages and currents. Source is unknown. Load is unknown. Lengths of feedlines are unknown. Without disclosing the answers or the exact procedure for solving the "brain teaser", I would like to draw attention to some of the implicit relationships that "ought" to help. 1) It is assumed that both feelines have purely resistive characteristic impedances (imaginary component, Xo, is zero). 2) Regardless of the length of the 300 ohm line and its termination impedance, the standing wave pattern and the voltages and currents, both incident and reflected as a function of distance x along that line are determined completely by the requirement/condition that there is a Z0 match at point "+". 3) There are an infinite number of lengths of the 300 ohm line and a corresponding infinite number of termination impedances for that line that will produce a Z0 match at point "+". However, because of (2), above, some of those combinations are well known combinations with well understood results (e.g., odd multiple of quarter wavelength or an integer number of half wavelengths). 4) Due to conditions (1) and (2) above, the phase relations between all of the voltages and currents immediately adjacent to either side of point "+" are trivial (i.e., any two quantities chosen will be either exactly in phase or exactly 180 degrees out of phase with one another). Due to (3) and (4) above, it would seem that an arbitrary choice of either a quarter wave line with an 1800 ohm termination or a half wave line with a 50 ohm termination would provide a convenient example with which to begin an analysis. However, that is not necessary and only provides a crutch to get off dead center. If all of the above elements are kept in mind, then it becomes a matter of solving a simple algebraic relationship involving 4 equations with 4 unknowns (the incident and reflected voltages and currents at the right hand side of point "+"). The actual numerical answer to such a problem is irrelevant. The points to be learned from all this are really the implicit relationships (2), (3) and (4) above. Without an understanding of those points, it is virtually impossible to even know where to start. I think that is the real point that Cecil is trying to make. Bob, W9DMK, Dahlgren, VA Replace "nobody" with my callsign for e-mail http://www.qsl.net/w9dmk http://zaffora/f2o.org/W9DMK/W9dmk.html |
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