On Sat, 27 Aug 2005 15:26:25 -0500, "hasan schiers"
wrote:

I found the error, I had to fix two conditions that I had changed in the
model:

Copper wire (for loss)
Ground characteristics

Now that both antennas have the same conditions, the T has ever so slightly
better gain at 20 degrees than the Inverted L. Not enough to bother with the
increased complexity, and the input Z is now down around 5 ohms for the T
and 8 ohms for the L.

Now, is it worth matching the 8 ohms up to 50 at the feedpoint, or just
using the tuner in the shack to take care of it? (coax feed, LMR-400, about
50')

If you would go he

http://www.qsl.net/ac6la/tldetails.html

download the program and enter your load Z and 50' of LMR400 @ 3.5
MHz, you would immediately see the answer to your question.

If the 8 ohm is real (j=0) then the total loss is all of 0.4 dB and if
the line is 50' long, the resulting input Z is easily matched with low
loss.

Thanks Wes...done...btw the antenna is for 160 meters, not 80m, so the loss
is even less. It doesn't look to me like it's worth doing anything more than
tuning out the mismatch in the shack. 73

....hasan, N0AN

On Sun, 28 Aug 2005 07:02:03 -0500, "hasan schiers"
wrote:

Thanks Wes...done...btw the antenna is for 160 meters, not 80m,

Sorry, I was just thinking about the subject of the thread, not
reading what you wrote.

so the loss is even less. It doesn't look to me like it's worth doing anything more than
tuning out the mismatch in the shack.

Exactly. As I said earlier, if it makes it easier on the someone's
(not you, you get it) conscience or ego they can think of the
transmission line as a bunch of distributed L and Cs (with a little R
thrown in) that are part of a tuner.

When they get this "tuner" to show 50 +j0, then they can call the
length of line between the "tuner" and the transmitter, the
"transmission line."

In your case, you have a low-loss line, so the "R" part is low and the
system is efficient.