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![]() Cecil Moore wrote: dansawyeror wrote: If it is true it proves that a driving a "bad" load can cause the coax feedline to radiate a significant portion of the feed energy. At this point I am not sure what word to use other then 'bad', but I due intend to perform experiments to measure and verify what is happening and the model. dansawyeror wrote: Below is a link to a site that claims to model coax radiation from a dipole. http://www.smeter.net/feeding/feedpowr.php We are in a position now to say what is wrong with that program. Essentially, it violates the conservation of energy principle. Energy cannot exist as both reflected power and radiated power at the same time. If the SWR is 1400:1, the feedline cannot be radiating much because the reflected power is 99.7% of the forward power and both are based on differential currents which don't radiate. That leaves only 0.3% of the power available for radiating by the feedline. If 99.9% of the power is radiated by the coax braid, then the feedline SWR must be very close to 1.6:1 because the ratio of reflected power to forward power can be no more than 0.1/100. As with cake, you cannot have your reflected power and radiate it too. Reflected power plus radiated power cannot add up to more than the forward power. In fact, Pfor = Pref + Prad If 50% of the power is radiated by the antenna plus feedline, then 50% of the power is reflected and the SWR is 5.83:1. Bear in mind that current flowing in a conductor will always generate a field. Alternating current flowing in a (straight) conductor will always generate a radiating electromagnetic field. That radiating field will convey energy if it is not nulled by another equal and opposite field. You need to demonstrate that all the fields resulting from all the currents are nulled in this scenario. Back into the woodwork. ac6xg |
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