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#1
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Hi all.
Throwing together a 20m single quad loop (triangular) antenna. In the past I have fed these with a 75r Q section. Nothing strange here.. I use to coil up most of it in a 5" coil to help reduce the line radiation problem - if any... No tuner in use.. This time however I am going to use two pieces of 50 ohm coax in parallel giving a 100r balanced Q section feeder. This more closely matches the loop Z. The shields are joined together at each end of the section and the coax centre conductors become the two antenna connection points. Question; Should I be worried about inbalance in the 50 ohm cable from the radio to the Q section. ie does the Q section reduce any of that problem? If that isnt the case I can make up the usual coil of coax before it meets the Q section.. or can I coil up the Q section instead. I also wonder about Q section shield grounding as I hadnt intended grounding either end. Will this be an issue? Cheers Bob W5/VK2YQA |
#2
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On Mon, 12 Sep 2005 15:39:23 -0500, Bob Bob wrote:
Hi all. Throwing together a 20m single quad loop (triangular) antenna. In the past I have fed these with a 75r Q section. Nothing strange here.. I use to coil up most of it in a 5" coil to help reduce the line radiation problem - if any... No tuner in use.. This time however I am going to use two pieces of 50 ohm coax in parallel giving a 100r balanced Q section feeder. This more closely matches the loop Z. The shields are joined together at each end of the section and the coax centre conductors become the two antenna connection points. I have a question, Why? The loop Z is going to be in the neighborhood of 120 ohm. A 75 ohm Q section is a better deal than 100 ohm. Question; Should I be worried about inbalance in the 50 ohm cable from the radio to the Q section. ie does the Q section reduce any of that problem? If that isnt the case I can make up the usual coil of coax before it meets the Q section.. or can I coil up the Q section instead. I also wonder about Q section shield grounding as I hadnt intended grounding either end. Will this be an issue? Cheers Bob W5/VK2YQA |
#3
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The modelled Z is around 140 ohms. The "top" element of the loop is
about 20% longer than the other two. It is starting to approach a folded dipole. Bob Wes Stewart wrote: I have a question, Why? The loop Z is going to be in the neighborhood of 120 ohm. A 75 ohm Q section is a better deal than 100 ohm. |
#4
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On Mon, 12 Sep 2005 18:38:34 -0500, Bob Bob wrote:
The modelled Z is around 140 ohms. The "top" element of the loop is about 20% longer than the other two. It is starting to approach a folded dipole. Okay. 75 ohm is -still- better than 100. |
#5
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Err why?
50r to 100r = 122r 50r to 75r = 90r Do I have the calcs right? Wes Stewart wrote: Okay. 75 ohm is -still- better than 100. |
#6
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Bob Bob wrote:
Err why? 50r to 100r = 122r SQRT(50*200) = 100 50r to 75r = 90r SQRT(50*100) = 70.7 Do I have the calcs right? Wes Stewart wrote: Okay. 75 ohm is -still- better than 100. SQRT(50*140) = 84 ohms. Z0=75 ohms is closer to 84 ohms than is Z0=100 ohms. If you had a 200 ohm feedpoint, Z0=100 ohms would be perfect. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#7
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On Tue, 13 Sep 2005 10:04:56 -0500, Bob Bob wrote:
Err why? 50r to 100r = 122r 50r to 75r = 90r Cecil already gave you the answer. A 90-degree line is called a "geometric mean" transformer. The required impedance is the square root of the product of the desired R and the load R. Here's a little tutorial: http://www.microwaves101.com/encyclo...uarterwave.cfm |
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