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#1
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Jim Kelley wrote:
Cecil Moore wrote: Here's the example sans the Bird. Between the tuner output and the load, where exactly is the actual SWR = 1:1 and where exactly is the actual SWR = 2.25:1? Answer: nowhere! XMTR--tuner---1 WL 75 ohm coax---50 ohm load And the answer would be different still in this circuit. XMTR---1/4 WL 75 ohm coax---50 ohm load No, it wouldn't. The answer is exactly the same. *NOWHERE* is the SWR 1:1 or 2.25:1. In both examples, the SWR on the coax is 1.5:1. The SWR is *always* set by the relationship of Z0 to the load. In both examples above, that relationship is *identical*. Amazin', what happens when you change the circuit! Z0 didn't change. The load didn't change. Therefore, the SWR didn't change. What exactly do you think changed? -- 73, Cecil http://www.qsl.net/w5dxp |
#2
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![]() "Cecil Moore" wrote in message . .. Jim Kelley wrote: Cecil Moore wrote: Here's the example sans the Bird. Between the tuner output and the load, where exactly is the actual SWR = 1:1 and where exactly is the actual SWR = 2.25:1? Answer: nowhere! XMTR--tuner---1 WL 75 ohm coax---50 ohm load And the answer would be different still in this circuit. XMTR---1/4 WL 75 ohm coax---50 ohm load No, it wouldn't. The answer is exactly the same. *NOWHERE* is the SWR 1:1 or 2.25:1. In both examples, the SWR on the coax is 1.5:1. The SWR is *always* set by the relationship of Z0 to the load. In both examples above, that relationship is *identical*. Amazin', what happens when you change the circuit! Z0 didn't change. The load didn't change. Therefore, the SWR didn't change. What exactly do you think changed? -- 73, Cecil http://www.qsl.net/w5dxp obviously the problem here is that cecil thinks he is the only one that knows better than to try to measure reflected power with a 50 ohm meter in a 75 ohm coax. |
#3
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Dave wrote:
obviously the problem here is that cecil thinks he is the only one that knows better than to try to measure reflected power with a 50 ohm meter in a 75 ohm coax. From your posturing, it wasn't readily apparent to me that you were agreeing with me. -- 73, Cecil http://www.qsl.net/w5dxp |
#4
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![]() "Cecil Moore" wrote in message . .. Dave wrote: obviously the problem here is that cecil thinks he is the only one that knows better than to try to measure reflected power with a 50 ohm meter in a 75 ohm coax. From your posturing, it wasn't readily apparent to me that you were agreeing with me. -- i'm not agreeing with how you assume the 50 ohm impedance of the meter out of the circuit. and i am not agreeing that there should be reflected power measured by the meter in the case of the 50 ohm load on the end of a 1/2 wave 75 ohm line. obviously it will not measure any reflected power which is perfectly correct for the whole circuit as defined and as actually measured. |
#5
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Dave wrote:
i'm not agreeing with how you assume the 50 ohm impedance of the meter out of the circuit. I don't think you understand what I was saying. It takes a certain length of feedline to establish a Z0 environment for the forward and reverse traveling TEM waves, i.e. to force Vfor/Ifor = Vref/Iref = Z0. and i am not agreeing that there should be reflected power measured by the meter in the case of the 50 ohm load on the end of a 1/2 wave 75 ohm line. I never said it "should" measure that reflected power. What I said is if it doesn't measure the reflected power that exists, it is not giving a valid measurement of reflected power. A properly calibrated meter will indeed measure the reflected power that exists. -- 73, Cecil http://www.qsl.net/w5dxp |
#6
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![]() "Cecil Moore" wrote in message om... Dave wrote: i'm not agreeing with how you assume the 50 ohm impedance of the meter out of the circuit. I don't think you understand what I was saying. It takes a certain length of feedline to establish a Z0 environment for the forward and reverse traveling TEM waves, i.e. to force Vfor/Ifor = Vref/Iref = Z0. and what the experiment pointed out was that the length of feedline attached is immaterial, the 50ohm environment is established within the meter itself and it doesn't care what the length of feedline attached is. |
#7
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Dave wrote:
"Cecil Moore" wrote: I don't think you understand what I was saying. It takes a certain length of feedline to establish a Z0 environment for the forward and reverse traveling TEM waves, i.e. to force Vfor/Ifor = Vref/Iref = Z0. and what the experiment pointed out was that the length of feedline attached is immaterial, the 50ohm environment is established within the meter itself and it doesn't care what the length of feedline attached is. The experiment proved that the 50 ohm environment is NOT established because the Bird readings were wrong. The Bird reported 100 watts forward power where the actual forward power was 104.1667 watts. The Bird reported zero reflected power where the reflected power was 4.1667 watts. Thus the experiment proves my point. The Bird does not yield accurate results when embedded in an environment other than 50 ohms. All the Bird does is sample the voltage and current essentially at a point. If the ratio of net voltage to net current happens to be 50 ohms, the Bird will report a matched condition, no matter what the Z0 of the transmission line and no matter how much reflected power actually exists at the measurement point. For instance: XMTR--balun--1/2WL 450 ohm line--x--1/2WL 450 ohm line--50 ohm load The SWR on the line is 9:1. The reflected power is 64% of the forward power. If forward power equals 100 watts, reflected power will be 64 watts at point 'x'. Yet a Bird wattmeter inserted at point 'x' will read zero reflected power. The environment is clearly 450 ohms. The reflected energy doesn't tuck tail and run away when the Bird is inserted. The Bird is simply giving the wrong reading for reflected power because all it is looking at is voltage and current at a point. This is such elementary transmission line stuff that I cannot believe there is any argument about it. The insertion of a Bird wattmeter in the middle of a non-50 ohm environment does NOT eliminate the reflected energy that exists before the insertion. -- 73, Cecil http://www.qsl.net/w5dxp |
#8
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![]() Cecil Moore wrote: Z0 didn't change. The load didn't change. Therefore, the SWR didn't change. What exactly do you think changed? I think the circuit changed. Don't you? I also think that if you change the circuit, it's possible to measure the effect of that change. The meter measures what takes place at its insertion point in the circuit. What you seem to be upset about is that it might not in every case accurately display the conditions at some arbitrary position away from its insertion point. Like within a shorted quarterwave stub for example. Are you still unwilling to accept that the meter itself can present a perturbation? ac6xg |
#9
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Jim Kelley wrote:
Cecil Moore wrote: Z0 didn't change. The load didn't change. Therefore, the SWR didn't change. What exactly do you think changed? I think the circuit changed. Don't you? The circuit changed without changing the forward power, reflected power, and SWR so nothing of interest to the present topic (V/I ratio) changed. Do you know what dictates the SWR in a distributed network? Certainly not the length of the feedline or the removal of a tuner (assuming lossless conditions). -- 73, Cecil http://www.qsl.net/w5dxp |
#10
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![]() Cecil Moore wrote: Jim Kelley wrote: Cecil Moore wrote: Z0 didn't change. The load didn't change. Therefore, the SWR didn't change. What exactly do you think changed? I think the circuit changed. Don't you? The circuit changed without changing the forward power, reflected power, and SWR so nothing of interest to the present topic (V/I ratio) changed. Do you know what dictates the SWR in a distributed network? Certainly not the length of the feedline or the removal of a tuner (assuming lossless conditions). Well, it's certainly true that both circuits are missing the 50 ohm impedance discontinuity in the middle, which is at least one of the "present topics" (and my point). I'll just go ahead and say what you really want me to say: You're good enough, you're smart enough, and doggone it, people like you! :-) ac6xg |
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