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Owen Duffy wrote:
The loss scale is in dB, it is the loss in dB at position x metres from the load. Aha, I see that noted at the bottom now that I scroll down. It didn't make sense to me if the loss scale was in percent. So what do I get if I integrate the area under the curve? Incidentally, I was engaging in fuzzy republican thinking when I came up with eleven current maximum points in 100 meters of feedline. Of course, there are twice that, i.e. 22 current maximum points which can be counted on your graph. You could calculate an average loss per meter figure, but I don't know what you could you use it for? The fact that this line is not straight (as some people seem to assume) means that working with average numbers is inherently inaccurate. Owen, most hams are not rocket scientists like you :-) Quite often, a rule-of-thumb average beats total ignorance. All measurements contain errors and are inherently inaccurate. Some of us live with that reality. Some of us rant and rave about it. Next time you are on your motorcycle, note that your speedometer is "inherently inaccurate" as is your gas gauge as are your reflexes. If you are not inherently inaccurate throwing darts in the local pub, you are a very unusual homo sapien. I, for one, am satisfied with average losses, presumably averaged over one half wavelength. The way I came up with that 25:1 limit on my open-wire SWR is that 600/25 equals 24 ohms and that is an acceptable impedance to my IC-256PRO's autotuner. Noting that the losses in 100 ft. of open-wire line running at an SWR of 25:1 are acceptable was an afterthought. -- 73, Cecil http://www.qsl.net/w5dxp |
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