Reg, G4FGQ wrote:
"He says it is 1 volt and no doubt the bibles agree."

OK. You have an antenna with some radiation resistance and a lossless
conjugate match to a load.

1/2 the antenna voltage which equals the volts per meter field strength
in your 1-meter wire, is dropped across the radiation resistance and the
other 0.5 volt appears across the receiver load. The radiation
resistance of the antenna becomes the Thevenin equivalent source
resistance of the generator feeding the receiver load..

The power lost to reradiation is 0.5 volt times the current in the
radiation resistance. The power delivered to the matched receiver load
is exactly the same.

Best regards, Richard Harrison, KB5WZI