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W. Watson wrote:
I'm guessing that one starts with an open ended transmission line, and looks at how the E and B fields are distributed along it. It's a standing-wave antenna. That means there is a forward wave and a reflected wave. The forward current adds to the reflected current all up and down the dipole. The magnitude of the reflected current arriving back at the feedpoint is approximately 90% of the forward current and are assumed to be approximately equal by Kraus. The forward current and reflected current are very close to being in phase at the feedpoint. The forward and reflected current are equal in magnitude and 180 degrees out of phase at the tip of the dipole. The feedpoint impedance of a 1/2WL dipole is approximately (|Vfor|-|Vref|)/(|Ifor|+|Iref|). The angle of the reflected current is close to equal in magnitude and opposite in sign to the forward current at any point along the dipole so the angle of the net current is very close to zero degrees. The net current pictured on that web page is a standing current wave with the same basic shape as in a 1/4WL open-circuit stub. That current distribution is illustrated in any antenna book, including Kraus and Balanis. It's also in my 15th edition ARRL Antenna Book. -- 73, Cecil http://www.qsl.net/w5dxp |
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