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Roy,
It is amazing how a simple concept such as impedance can be made obscure but most current probes are spec'd this way by the manufacturers and test procedures for DO-160E (FAA aircraft testing) call out probes the same way. By saying that a current probe has a transfer impedance of 0dB-ohm means 0dB relative to 1 ohm, but R = V/I so 0dB-ohm means that for 1A of current thru the primary of the probe produces 1V across a 50 ohm load. Similarly a -20db-ohm transfer means that 1A produces .1V across a 50 ohm load. For most of us, this means a 1 turn primary and a 50 turn secondary which yields a theoretical primary impedance or 0.02 ohms. One of the probes I have says the primary impedance is less than ..1 ohm. Larry Benko, W0QE Roy Lewallen wrote: Larry Benko wrote: Hi Roy, I have a couple of RF current meters with freq. response from 10KHz to 100MHZ that are the types used for FCC part 15, DO-160E testing etc. and have a transfer impedance of 0dB-ohm. They have an opening of about 1.6" dia. and I sqeeze the feedline together (spacing about 1.5") temporarily and clamp over both conductors for measurement #1 and clamp over just 1 of the conductors for measurement #2. I read the output of the current probe with an RF power meter. In my case the current in a single conductor was approximately 15dB above the differential current which seemed to be pretty well balanced. Is there anything wrong with this approach? Larry Benko, W0QE Not that I can see. In my opinion it's the best way to make the measurement. A homebrew version of this is entirely adequate, though, as described in the earlier thread. It's very important to terminate the secondary with a fairly low impedance so the transformer doesn't present a significant impedance to the line. I assume your meter does this internally -- maybe that information is in the transfer impedance you mentioned and which I don't really understand. Roy Lewallen, W7EL |
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