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#1
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Cecil,
Interesting. I am quite familiar with Kirchoff's equation in regard to voltages around a loop and his equation about currents at a node. Did I miss a third equation regarding currents around a loop? Hint: Kirchoff would not be the slightest bit bothered by this problem. Reg, as usual, has it completely correct. 73, Gene W4SZ Cecil Moore wrote: Reg Edwards wrote: The whole business can be mathematically modelled. The point is that it cannot successfully be modeled with the lumped circuit model where the current is constant everywhere in the circuit. What would Kirchhoff have thought about a coil with 0.1 amp at the bottom and 0.7 amps at the top? It certainly doesn't mean that 0.6 amps is flowing sideways. All it means is that the relative phase of the forward current and reflected current changes through the coil and therefore the distributed network model needs to be used. |
#2
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Gene Fuller wrote:
I am quite familiar with Kirchoff's equation in regard to voltages around a loop and his equation about currents at a node. Did I miss a third equation regarding currents around a loop? Nope, you missed an implication of Kirchhoff's current law. Unequal currents into and out of a passive black box implies the existence of a node inside the box. -- 73, Cecil http://www.qsl.net/w5dxp |
#3
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Cecil,
Your response makes no sense at all. Unequal currents into and out of a passive black box implies charge storage, which generally means capacitance. You cannot have it any other way, with or without waves or reflections. Conservation of charge is one of the most fundamental laws in nature. Reg was correct. 73, Gene W4SZ Cecil Moore wrote: Gene Fuller wrote: I am quite familiar with Kirchoff's equation in regard to voltages around a loop and his equation about currents at a node. Did I miss a third equation regarding currents around a loop? Nope, you missed an implication of Kirchhoff's current law. Unequal currents into and out of a passive black box implies the existence of a node inside the box. |
#4
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Gene Fuller wrote:
Your response makes no sense at all. Unequal currents into and out of a passive black box implies charge storage, which generally means capacitance. Boundary condition: There's nothing but wire inside the black box. -- 73, Cecil http://www.qsl.net/w5dxp |
#5
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Cecil,
This is getting more interesting by the moment. Have you now removed some of the well-known physical attributes of wire and transmission lines? Specifically, what happened to the L and C of the wire? I have no issue with the use of network theory, reflection coefficients, standing waves, or any other commonly used descriptions. However, none of these mathematical conveniences change the fundamental physical laws. If current, and therefore charge, appears to be unbalanced, then there must be charge storage somewhere. As Reg pointed out, the charge is stored in the capacitance of the coil. No need to invoke any magic incantations about networks and standing waves. In principle any of these problems can be solved with very basic equations found in any E&M text. In practice it is extremely cumbersome to do so, and that is why all of the network formulations have been developed. Just don't fall into the trap of thinking that any new physical behavior is created by the reflections and standing waves. I believe in previous messages you have referred to that thinking as "seduced by the math models." 73, Gene W4SZ Cecil Moore wrote: Gene Fuller wrote: Your response makes no sense at all. Unequal currents into and out of a passive black box implies charge storage, which generally means capacitance. Boundary condition: There's nothing but wire inside the black box. |
#6
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Gene Fuller wrote:
I have no issue with the use of network theory, reflection coefficients, standing waves, or any other commonly used descriptions. However, none of these mathematical conveniences change the fundamental physical laws. If current, and therefore charge, appears to be unbalanced, then there must be charge storage somewhere. Gene, the flaw is in your misunderstanding of the fundamental physical laws, not in those laws. We measure the net current at one end of a coil at 0.1 amp and we measure net current at the other end of the coil at 0.7 amps (my web page example). The net current *APPEARS* to be unbalanced, but appearances can be deceiving. THERE IS NO STEADY-STATE CHARGE STORAGE ANYWHERE IN THE SYSTEM. Does this violate any fundamental physical laws? Of course not. Here's why (neglecting losses): V*I*cos(theta) equals the same power at both ends of the coil. That proves there is no steady-state energy storage. V1*(0.7)*cos(theta1) = V2*(0.1)*cos(theta2) This is a distributed network. A lumped circuit analysis fails miserably when you try to use it in a standing- wave environment and you have just proved it. That is also the same mistake that W8JI and W7EL have been making. The forward current at the 0.7 amp point is 0.4 amps at zero deg. The reflected current at the 0.7 amp point is 0.3 amps at zero degrees. The net current is the phasor sum of those two component currents. Inet = (0.4 amps at zero deg) + (0.3 amps at zero deg) Inet = 0.7 amps at zero deg The forward current at the 0.1 amp point is 0.4 amps at 82 degrees. The reflected current at the 0.1 amp point is 0.3 amps at -82 degrees. The coil causes an 82 degree phase shift in both forward and reflected currents and since their phasors are rotating in opposite directions, the sign of their phase shifts are opposite. The net current at this end of the coil is: Inet = Ifor + Iref Inet = (0.4 amp at 82 deg) + (0.3 amp at -82 deg) Inet = 0.057 amps + 0.043 amps = 0.1 amp at zero deg The fundamental physical laws are perfectly valid as has been demonstrated here. It is your understanding of them that seems to be the problem. You seem to have been fooled by appearances and as a result, you chose the wrong model with which to try to solve the problem. The distributed network analysis was developed because the lumped circuit analysis falls apart under certain circumstances. One of those circumstances is the presence of standing waves like the ones that exist in a 75m mobile antenna. -- 73, Cecil http://www.qsl.net/w5dxp |
#7
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Gene Fuller, W4SZ wrote:
"This is getting more interesting by the moment." There are plenty of coils in boxes which have different currents into and out of their two ends. A coil in a box used to be a common way to resonate a too-short 1/4-wave (90-degree) whip. A company I worked for had many Land Rovers, trucks, boats, and ships on and around the Argentine side of the island of Tierra del Fuego.These were equipped with H-F SSB tranceivers. Mobile amntenna was a stainless whip mounted atop a substantial fiberglass box. The box contained the loading coil which was accessible for preselecting the right coil tap to resonate the whip with the vehicle for a particular operating frequency. The box also contained a motor-driven band-switch to automatically change taps on the coil when the frequency was changed on the radio. I am well aware of the ability to resonate a 90-degree whip with no more than the proper coil in series with the short whip on a base insulator. I tuned every one of those coils for each of the frequencies we used in Argentina with my own hands. ON4UN has a graph, Fig 9-22 on page 9-15 of "Low-Band DX-ing" which shows current distribution of a base-loaded whip, In his example, the whip is 45-degrees long.. The loading coil provides the extra 45-degrees required for resonance. Current at the base of ON4UN`s whip is one amp times the cosine of 45-degrees, or 0.707 amp. The loading coil has an input of one amp. With 1 amp into the loading coil and 0.707 amp out of the loading coil, the coil definitely does not have the same current at both ends. Best regards, Richard Harrison, KB5WZI |
#8
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Richard Harrison wrote:
ON4UN has a graph, Fig 9-22 on page 9-15 of "Low-Band DX-ing" which shows current distribution of a base-loaded whip, In his example, the whip is 45-degrees long.. The loading coil provides the extra 45-degrees required for resonance. Current at the base of ON4UN`s whip is one amp times the cosine of 45-degrees, or 0.707 amp. The loading coil has an input of one amp. With 1 amp into the loading coil and 0.707 amp out of the loading coil, the coil definitely does not have the same current at both ends. It's not that perfect in the real world but the basic concept still applies. The actual current at the top of the coil is somewhat higher than 0.707 amp because the current inside the coil is greater than 1 amp. EZNEC says the current about 1/3 of the way up from the bottom of the coil is about 1.15 amp. The inductance of the coil forces the phase between the voltage and current to increase. To maintain the same V*I*cos(theta) power, the current must also increase. The high flux fields developed inside the coil somewhat distort the perfect current cosine wave found in a thin wire dipole so it is not quite as black and white as ON4UN indicates. -- 73, Cecil http://www.qsl.net/w5dxp |
#9
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Richard Harrison wrote:
ON4UN has a graph, Fig 9-22 on page 9-15 of "Low-Band DX-ing" which shows current distribution of a base-loaded whip, In his example, the whip is 45-degrees long.. The loading coil provides the extra 45-degrees required for resonance. Those diagrams were highly misleading, and have been withdrawn from the current 4th edition. That whole introduction to short verticals has been completely rewritten and revised. The problem was that the current profiles of the full-size and loaded quarter-wave antennas were both drawn against a linear vertical scale of *phase*. This not only misrepresented the physical lengths of the lower and upper sections, it also misrepresented the length and effect of the coil. This presentation is highly misleading, and the first victim was the person who drew it, and then overlaid current profiles on it. (I don't think this was ON4UN. When someone sets out to produce a 500-page book, they have to quote some things on trust from other people; and it may take a few editions to iron out all the kinks. Much more to the point, ON4UN is right at the leading edge of his subject, and each edition contains something new and important.) The replacement diagrams in the 4th edition are much better. They show current profiles against *physical* height, and help bring out what's really happening. Current at the base of ON4UN`s whip is one amp times the cosine of 45-degrees, or 0.707 amp. The loading coil has an input of one amp. With 1 amp into the loading coil and 0.707 amp out of the loading coil, the coil definitely does not have the same current at both ends. You can't quite those figures in evidence, because they were never more than a speculation based on misunderstandings. When ON4UN came to think about it, he quite rightly changed his mind. This brings up another point that hasn't been mentioned so far in this discussion: there is an important difference between purely inductive loading, and the kind of loading you can get from any practical inductOR. Note the difference. An inductOR is a real-life electronic component, a coil of wire. InductANCE is its main electrical property - but it isn't the only one. When a shortened antenna is loaded by pure inductance, you find the following: 1. The magnitude and phase of the current flowing into the loading inductance are both the same as that of the current flowing out (this is a fundamental property of pure inductANCE). This means the current distributions in the sections above and below the loading inductance join up in a sharp kink. 2. What does go through a step change is the *voltage* across the inductance. This changes in both magnitude and phase. For a typical centre-loaded whip, the RF voltage is low in all of the bottom section, but above the loading inductance it's very high indeed. To repeat: this is the situation for loading with pure inductANCE. (Sorry to keep shouting "ANCE!" and "OR!" like that, but I'll bet someone still comes back with a reply that proves they didn't read what I actually wrote.) The diagram in ON4UN's 4th edition (Fig 9-44) shows these effects much better than I can describe them in words. The diagram came from an article by W7XC in QST for March 1990. I strongly recommend everyone to look at these diagrams... but please don't treat them as 'bible text'. Do your own thinking about it. A different viewpoint on loading inductANCE is given in an article by Boyer in 'Ham Radio'. This uses the 'antenna-transmission line analog' theory... and comes to exactly the same conclusions about the effects of loading inductANCE: it is simply there to resonate the capacitive reactance that arises from having physically shortened the antenna. (Ironically, ON4UN's worked examples and computer programs to calculate loading inductance have always been based on this approach; the conceptual error in early editions was only in that one diagram.) With a firm grip on the way that pure inductANCE loads an antenna, you are then in a good position to look at the differences that appear when you use a practical inductOR. With a real-life inductOR, you don't have pure inductANCE any more. It is embedded in a component that is made from some length of wire, wound into a coil that has a physical length and diameter, has capacitance between its own turns, and also has capacitance to the straight sections of antenna above and below it. The effects of the coil's inductANCE will still be there, but you can certainly expect to see a lot of detailed differences. But the practical differences can't possibly be understood without that basic understanding about inductANCE as a foundation. Without it, you're building your house on sand. -- 73 from Ian GM3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
#10
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Gene Fuller weote:
"Conservation of charge is one of the most fundamental laws of nature." Unequal currents into and out of a passive black box are very simple to produce. Suppose the black box contains a simple transformer with a ratio other than one to one? The power can be constant but the voltage and current must be different on input and output. R-F is a-c, not d-c. Best regards, Richard Harrison, KB5WZI |
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