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![]() Tom Donaly wrote: Cecil Moore wrote: "Reg Edwards" wrote: Sorry Cec, but I havn't the foggiest idea what you are talking about. Let me ask it a little differently. We all know what a plot of the standing wave current magnitude looks like up and down an open-circuit transmission line. But what does a plot of the associated standing wave current *phase* look like up and down that same open-circuited transmission line? -- 73, Cecil, W5DXP By now you should be able to calculate that, Cecil. 73, Tom Donaly, KA6RUH Indeed. And I even gave the answer some time ago -- the phase of the total current (which Cecil seems to like calling the "standing wave" current) is the same all along the line. That's true only for the case of a line that's completely short or open circuited. In any other case, the phase of total voltage and current vary along the line. This can be easily calculated by adding the values of the forward and reverse traveling waves at each point to get the total at each point. Or, if you're lazy, just plug the numbers into the equations you'll find in _Reference Data for Radio Engineers_ or your favorite reference. Or if you're lazier yet you can model a transmission line with EZNEC or the modeling program of your choice and let it tell you what the phase of the current is at each point along the line. Any of the three methods will give the same result if done correctly. As I mentioned before, a plucked guitar string is a good physical analogy. Each point along the string moves in the same direction at the same time, showing that the motions at all points along the string are in phase. That's very basic transmission line theory. If Cecil really doesn't know the answer to the question he asked, it's no wonder he has such conceptual problems with inductors and transmission lines. Roy Lewallen, W7EL |
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