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#1
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OK, so all wavelengths shift by the same ratio. In what way does that
change the "waveshape in modulations," other than to simply change the time scale by that same ratio? Or--does Doppler shift (alone) give rise to different propagation velocities at different frequencies? Does Doppler shift change an impulse to a chirp (or the right chirp to an impulse)? |
#2
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On 8 Mar 2006 14:15:20 -0800, "K7ITM" wrote:
OK, so all wavelengths shift by the same ratio. Yes, in fact they do. I mistakenly ascribed a disproportionality to the relation of the doppler sidebands and the doppler carrier. Net answer, no dispersion. |
#3
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Thanks, Richard. I'd have been happy to learn that indeed Doppler
shift does lead to dispersion -- "any day I learn something new is a good day." But coming to agreement was also good. Now, for the next part of the story, Doppler shift _in_combination_with_ multipath indeed does lead to dispersion, I believe. That's why I was careful in my original question to say, "Doppler alone?" See for example http://www.eleceng.adelaide.edu.au/s...grad/Yu05.html. I get the impression that Ms. Yu is a pretty bright young woman. Cheers, Tom |
#4
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On 8 Mar 2006 15:16:05 -0800, "K7ITM" wrote:
I'd have been happy to learn that indeed Doppler shift does lead to dispersion Hi Tom, I'd gotten it in my mind that the higher sideband would have increased more in relation to the carrier than the lower sideband would have (or versa vice) hence dispersion. Scribbling out the math in response to your questions resolved that error. 73's Richard Clark, KB7QHC |
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