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#1
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I'm wondering about calculating antenna efficiency from the Q as
measured at the feedpoint. I know the definition of antenna Q has been hashed out a bit on this group, so let me be specific and say that I'm measuring Q by looking at the half power bandwidth around resonance as I would with an LCR circuit, or maybe I'm looking at the generalization for a different voltage down from the maximum, so I can use the 2:1 SWR bandwidth as per the description he http://lists.contesting.com/_amps/2006-01/msg00179.html Once you know the Q, you need to know the antenna's radiation resistance using some method, so that you can figure out the loss resistance. Is seems reasonable to model the antenna in EZNEC with lossless elements and use the feedpoint resistance at resonance as the radiation resistance and then subtract that off from the R calculated from Q=X/R. Then all the loss elements are empirically determined, ground losses, bolted connections, traps, etc etc. Any comments on this? It seems a good idea to me but I'd welcome some holes poked in it. I know that accurately modeling things like multiband verticals and so forth even in the lossless case might be tricky. 73, Dan N3OX |
#2
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On 15 Jun 2006 11:51:24 -0700, "
wrote: so I can use the 2:1 SWR bandwidth as per the description he http://lists.contesting.com/_amps/2006-01/msg00179.html Once you know the Q, you need to know the antenna's radiation resistance using some method, so that you can figure out the loss resistance. Hi Dan, Conceptually close, but certainly not to the degree of accuracy you might expect. 2:1 SWR points are not half power, as would be the classic determinant for Q bandwidth. As your link provides, it is 88% power points. 73's Richard Clark, KB7QHC |
#3
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Yes, I guess alternatively you could calculate the SWR at the
half-power points from (E/Eo)^2=(1-((1-SWR)/(1+SWR))^2) With E/Eo = 1/sqrt(2) I get that this is about SWR = 5.8, and I understand that the MFJ-259B is less and less accurate as the load moves away from 50 ohms resistive, so it might be better to use the 88% power, 2:1 SWR bandwidth points. - - - - - - I've thought of an additional question regarding this method. The ground has an effect on antenna feedpoint impedance. This effect contains both modification to the radiation resistance and the loss resistance components of the feedpoint resistance. Is the effect on the radiation resistance different for lossy earth and for perfect earth? Obviously the loss increases with proximity to ground, but can the effect of ground reflections on radiation resistance be accurately modeled by putting the antenna over perfect ground? 73, Dan N3OX |
#4
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On 15 Jun 2006 11:51:24 -0700, "
wrote: I'm wondering about calculating antenna efficiency from the Q as measured at the feedpoint. I know the definition of antenna Q has been hashed out a bit on this group, so let me be specific and say that I'm measuring Q by looking at the half power bandwidth around resonance as I would with an LCR circuit, or maybe I'm looking at the generalization for a different voltage down from the maximum, so I can use the 2:1 SWR bandwidth as per the description he http://lists.contesting.com/_amps/2006-01/msg00179.html Once you know the Q, you need to know the antenna's radiation resistance using some method, so that you can figure out the loss resistance. Is seems reasonable to model the antenna in EZNEC with lossless elements and use the feedpoint resistance at resonance as the radiation resistance and then subtract that off from the R calculated from Q=X/R. Then all the loss elements are empirically determined, ground losses, bolted connections, traps, etc etc. Any comments on this? It seems a good idea to me but I'd welcome some holes poked in it. I know that accurately modeling things like multiband verticals and so forth even in the lossless case might be tricky. SWR bandwidth is pretty much meaningless in this effort. If you model the antenna and then use the reactance slope with respect to frequency around the resonant frequency then you can calculate an equivalent L & C for the radiator. With this and the feedpoint resistance you can calculate Q, for whatever it's worth. Close to resonance the reactance slope is very near linear and the real part is nearly constant. I use Excel's solver to find L & C and go from there. With coupled elements (Yagis, etc) I'm not sure this method is particularly useful, but I'm not sure whether knowing the Q is very useful in the first instance. |
#5
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Wes and Richard. I've realized my conceptual mistake here. I have an
antenna analyzer, not just an SWR meter. I can MEASURE the resistive part of the feedpoint impedance. I can calculate the radiation resistance using EZNEC or more simply for simpler antennas. The resitive part of the feedpoint impedance minus the radiation resistance is the loss resistance, and then I can calculate the antenna efficiency. I've complicated things by getting the Q involved, though maybe if all you have is an SWR meter... Thanks for the replies. 73, Dan |
#6
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On 15 Jun 2006 12:37:20 -0700, "
wrote: I've thought of an additional question regarding this method. The ground has an effect on antenna feedpoint impedance. Hi Dan, To say the least. This effect contains both modification to the radiation resistance and the loss resistance components of the feedpoint resistance. Well, it doesn't change radiation resistance, that is a property of the height of the radiator (as in length, not how high above ground). As for feedpoint resistance, the loss of ground is cast into the determination of feedpoint Z (which contains the sum of Rr, Ohmic loss of the structure, and dielectric loss of the soil). Is the effect on the radiation resistance different for lossy earth and for perfect earth? To say the least. Obviously the loss increases with proximity to ground, but can the effect of ground reflections on radiation resistance be accurately modeled by putting the antenna over perfect ground? Ground reflections are post-hoc determinations of what happens to the available power AFTER it has escaped ground loss and left the radiator. Ground serves to influence the radiation pattern, but only ground at a distance. This is basically ray-tracing and trigonometry between the antenna as a point, and the far field earth. Ground also serves to influence the radiation pattern insofar as how much power is divided between heating the ground and radiating out to that ground at a distance which then bounces off and away. Perfect ground has no loss, and is perfectly reflective. Poor ground (very poor ground in fact) has little loss, but little reflectivity. Better ground has more loss, but higher reflectivity. Ground is a two-edged sword and the degrees of variation don't swing very far for the majority of Hams. If you happen to be one of those minority Hams, you possibly have your vertical planted into very low loss sand dune overlooking the ocean. If you happen to reside at the other end of the bell curve, that minority probably lives in a mountain valley swamp. All situations bear upon the drivepoint Z, and the launch characteristics, but bear in mind they are separate characteristics that have different major variables. 73's Richard Clark, KB7QHC |
#7
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Q cannot be measured. It is a dimensionless number. It is merely a
ratio of two quantities which ARE measurable. But it's not so ridiculous as measuring the standing wave ratio on an imaginary transmission line. |
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