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#51
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![]() Reg Edwards wrote: A pair of radials behave as a continuous dipole fed at its center via a single wire. And it radiates. If the radials are horizontal and radiating, why is there virtually no horizontally polarized radiation? -- 73, Cecil ====================================== Cec, Your use of the word "virtually" indicates a weakness in your ideas on the subject. The radiation, as small as it may be, is vertically polarised. ---- Reg. |
#52
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#53
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What's the matter with 3, equi-spaced radials?
Be economical. Save a radial! It looks better too. And there are no arguments about directionality. ---- Reg. |
#54
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On Tue, 11 Jul 2006 14:35:34 +0100, "Reg Edwards"
wrote: What's the matter with 3, equi-spaced radials? Be economical. Save a radial! It looks better too. And there are no arguments about directionality. ---- Reg. Modeling such an arrangement gave no real noticeable difference between using three or four radials. Danny, K6MHE |
#55
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Reg Edwards wrote:
Reg Edwards wrote: A pair of radials behave as a continuous dipole fed at its center via a single wire. And it radiates. If the radials are horizontal and radiating, why is there virtually no horizontally polarized radiation? -- 73, Cecil ====================================== Cec, Your use of the word "virtually" indicates a weakness in your ideas on the subject. The radiation, as small as it may be, is vertically polarised. ---- Reg. Put a number on it, Reg. Besides, you said, yourself, that Cecil is always right. 73, Tom Donaly, KA6RUH |
#56
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Cecil Moore wrote:
Tom Donaly wrote: wrote: Cecil Moore wrote: It's pretty easy to understand. Any two radials, 180 degrees apart and high enough, should theoretically cancel each other's radiation in the far field. Not true. How much not true? -45 DB, i.e. negligibly not true. :-) That's what I thought. Sometimes, orders of magnitude are important. Otherwise, people would be worrying about the fact that they're closer to the center of the Earth in the middle of the bottom of a flat bottomed hole than they are at the edges. 73, Tom Donaly, KA6RUH |
#57
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John Popelish wrote:
Tom Donaly wrote: How many photons does it take to make a Watt? 1/(Hz*6.63*10^-34). The lower the frequency the less energy per photon. That's joules per second, is it? 73, Tom Donaly, KA6RUH |
#58
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Cecil Moore wrote:
John Popelish wrote: Remember, it is Cecil, not me, who demands agreement or eternal verbal torture. I don't demand agreement, John, just resolution. Resolution in who's mind? I don't demand anything. I just read, occasionally throw out a thought, and learn what I can. I accept that sometimes I will learn something that is wrong, but I just keep trying to fit the pieces together. |
#60
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Tom Donaly wrote:
John Popelish wrote: Tom Donaly wrote: How many photons does it take to make a Watt? 1/(Hz*6.63*10^-34). The lower the frequency the less energy per photon. That's joules per second, is it? A watt is a joule per second. The formula gives the number of photons per second that carry a watt (or a joule per second) once you provide the Hz (frequency). By the way, I am having second thoughts as to whether or not there should be a 2*pi factor in there, since most physics formulas deal with frequency in radians per second, not cycles per second. But the photon energy formulas usually deal with wavelength, and I have never seen one that assumes a wavelength is a radian of a cycle, rather that a full cycle, so, perhaps Hz is the correct unit. If anyone can clear this up for me, I would appreciate it. |
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