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#1
September 29th 06, 04:01 PM
posted to rec.radio.cb
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Look at what Griffey thinks his amp will do...
Frank Gilliland wrote:
You claim 516 watts PEP and 55% efficiency. And I'll be super-nice and say that's at 14 volts and you aren't going into saturation. So that means: 516 watts / 14 volts = 36.86 amps 36.86 amps / 55% efficiency = 67 amps 67 amps / 2 transistors = 33.5 amps Ic on each transistor. Amplifier efficiency isn't based on peak power (PEP) you putz... see http://www.rf-amplifiers.com/index.php?topic=dc_input Are you really this stupid?... or are you just putting us on? www.telstar-electronics.com |
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#2
September 29th 06, 04:16 PM
posted to rec.radio.cb
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Look at what Griffey thinks his amp will do...
On 29 Sep 2006 08:01:56 -0700, "Telstar Electronics"
wrote in .com: Frank Gilliland wrote: You claim 516 watts PEP and 55% efficiency. And I'll be super-nice and say that's at 14 volts and you aren't going into saturation. So that means: 516 watts / 14 volts = 36.86 amps 36.86 amps / 55% efficiency = 67 amps 67 amps / 2 transistors = 33.5 amps Ic on each transistor. Amplifier efficiency isn't based on peak power (PEP) you putz... see http://www.rf-amplifiers.com/index.php?topic=dc_input Once again you didn't understand what I wrote. I wasn't calculating amplifier efficiency; I calculated peak collector current -based on- your very own amplifier efficiency claim. Would you rather I use the transistor's collector efficiency of 35%? Are you really this stupid?... or are you just putting us on? I have thought of asking the same question of you, but I haven't because you would ignore it just like all the other tough questions. That, and I already know the answer. |
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#3
September 29th 06, 04:18 PM
posted to rec.radio.cb
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Look at what Griffey thinks his amp will do...
Frank Gilliland wrote:
I have thought of asking the same question of you, but I haven't because you would ignore it just like all the other tough questions. That, and I already know the answer. Great response... you really are a piece of work... LOL www.telstar-electronics.com |
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#4
September 29th 06, 04:30 PM
posted to rec.radio.cb
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Look at what Griffey thinks his amp will do...
On 29 Sep 2006 08:18:43 -0700, "Telstar Electronics"
wrote in . com: Frank Gilliland wrote: I have thought of asking the same question of you, but I haven't because you would ignore it just like all the other tough questions. That, and I already know the answer. Great response... you really are a piece of work... LOL Ok, we'll use the collector efficiency..... 516 watts / 14 volts = 36.86 amps 36.86 amps / 35% efficiency = 105.3 amps 105.3 amps / 2 transistors = 52.65 amps Ic on each transistor. And since 65% is dissipated as heat, 52.65 amps * 65% = 34.22 amps (Scary!) 34.22 amps * 14 volts = 479 watts.... HOLY ****!!! You better have a BIG MF HEAT SINK!!! Are these transistors water-cooled? |
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