On Tue, 25 Sep 2007 05:43:22 -0700, Telspam Electronics
wrote in
.com:

On Sep 24, 2:42 pm, Frank Gilliland
wrote:
So you claim it doesn't work because one diode will "hog" the current?
Well, that's the point! D1 "hogs" the current and establishes a fixed
voltage for the base of TR1!!!

As usual Frank you are missing the important point here. That point
being that you can't simply parallel two diodes... and have them share
currents. This would have to be done in order for any tracking between
the two. The problem is that one diode will always turn on before the
other... and take all current. Now I ask you... where is the sharing/
tracking in that scenario? The answer is: there is no sharing/
tracking... because one diode with the lowest drop will hog the entire
current... and the other diode will be off.


Amazing. Two major bungles within one month. First you couldn't
recognize a simple voltage multiplier, and now you show that you can't
even understand the basic principle of diode biasing of a transistor.


this is why the gentleman
on the web page link that YOU provided says it that scheme works like
crap. He's absolutely right!


Funny..... he gives a different explanation.

BTW, where's that schematic, Brian?

On Sep 25, 8:42 am, Frank Gilliland
wrote:
Amazing. Two major bungles within one month. First you couldn't
recognize a simple voltage multiplier, and now you show that you can't
even understand the basic principle of diode biasing of a transistor.

Frank, again you resort to degrading statements in an attempt to shift
the focus and avoid the topic.
You have suceeded... end of conversation with you.
www.telstar-electronics.com

On Tue, 25 Sep 2007 07:08:51 -0700, Telstar Electronics
wrote:

|On Sep 25, 8:42 am, Frank Gilliland
|wrote:
| Amazing. Two major bungles within one month. First you couldn't
| recognize a simple voltage multiplier, and now you show that you can't
| even understand the basic principle of diode biasing of a transistor.
|
|Frank, again you resort to degrading statements in an attempt to shift
|the focus and avoid the topic.
|You have suceeded... end of conversation with you.
|www.telstar-electronics.com
|-------------

No Brian

He is quite on topic. You are failing to comprehend a very simple
basic understanding of the biasing of a transistor.

james

On Tue, 25 Sep 2007 07:08:51 -0700, Telspam Electronics
wrote in
om:

On Sep 25, 8:42 am, Frank Gilliland
wrote:
Amazing. Two major bungles within one month. First you couldn't
recognize a simple voltage multiplier, and now you show that you can't
even understand the basic principle of diode biasing of a transistor.

Frank, again you resort to degrading statements in an attempt to shift
the focus and avoid the topic.


The topic is the concept of using a diode to bias a transistor, a
concept understood by any first-year electronics student.

But not you.

The BE junction stays at or above quiescient current BECAUSE the diode
is hogging the current. It even says that in the article (that you
obviously didn't understand).

Two diodes..... sheesh..... I'll bet you've never seen a Vbe curve,
either.


You have suceeded... end of conversation with you.


Well, since that's the closest thing to an admission of ignorance that
you are capable of, I'll take all nine square feet...... ROTFLMMFAO!!!