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Old November 9th 08, 11:49 PM posted to rec.radio.amateur.homebrew
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Default LC calculation

On Nov 9, 8:36*am, Grumpy The Mule wrote:
Howdy,

I'm guessing that it can be solved like this...
Consider the autotransformer action of the tapped inductor.
Then divide the tap capacitor (C2) value by the square of the
turns ratio (N) before adding it to the primary capacitance
of the parallel tuned circuit (C1.)

F=2Pi*sqrt(L(C1+C2/N^2))

I found a rigorous solution in chapter 8 of Alternating
Current Circuits by K.Y. Tang but it's too messy to type.

73,
Grumpy

exray wrote :

Hi,
Can somebody walk me thru the calculation of an LC circuit where the
capacitor is tapped down on the coil? *I see this often done for
bandspreading purposes.


Tnx,
Bill WX4A




One thing to be a bit careful about is including the coupling between
the coil sections. Since I don't know how those particular coils were
designed, I can't say for sure, but in general the coupling between
pieces of the coil isn't as high as you might think.

You can make a good estimate for typical HF single-layer air-core
solenoid coils just using your favorite coil calculation. For
example, consider a coil that's one inch diameter, two inches long, 20
turns per inch, and tapped at the 30th turn (1.5 inches) up from the
bottom. Then the whole coil is about 16.32uH, the 1.5" part is about
11.54uH, and the top 0.5" is about 2.63uH. If the coupling were
perfect between the sections, I believe the inductance of the whole
would be about 11.54uH + 2.63uH + 2*sqrt(11.54*2.63)uH = 25.19uH. At
16.32uH for the whole coil, the implied coupling coefficient between
those two sections is only about 0.20, and you need to be careful to
not think of the tapped coil as simply a transformer with a 3:1 turns
ratio, with implied close coupling between the sections. (This also
illustrates why you can short out turns of a tank coil without totally
killing the net inductance...)

I trust if I've hosed the calculation too badly, someone will point
out the error of my ways. ;-)

Cheers,
Tom
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Old November 10th 08, 01:04 AM posted to rec.radio.amateur.homebrew
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Default LC calculation

Howdy,

That's an excellent point. I expect that the sections
of the coil in question will not have very good coupling.
I hadn't considered it! I calculate the same inductance
values.

Bah! In my previous posts the "(sqrtL*C)" should be "(1/sqrtL*C)"
Heh... with a pencil and paper the formula turned out right.
I noticed this when I calculated the resonance of the two
values 16.32uH and 11.54uH with an arbitrary value of 50pF
just to verify how I thought things should be.

So from this I gather that the extension of the coil
connected to the grid circuit will have even less
effect on the tuning than I expected.

The Easy Teenage NewYork method of solving this would be
to put the problem into SPICE with the estimated coupling
coefficent of 0.2.

I've never liked shorting turns to reduce an inductance.
Seems like an avoidable source of some losses no matter
how you slice it. But for some long coils, like antennas,
it works ok. I guess.



K7ITM wrote in
:

One thing to be a bit careful about is including the coupling between
the coil sections. Since I don't know how those particular coils were
designed, I can't say for sure, but in general the coupling between
pieces of the coil isn't as high as you might think.

You can make a good estimate for typical HF single-layer air-core
solenoid coils just using your favorite coil calculation. For
example, consider a coil that's one inch diameter, two inches long, 20
turns per inch, and tapped at the 30th turn (1.5 inches) up from the
bottom. Then the whole coil is about 16.32uH, the 1.5" part is about
11.54uH, and the top 0.5" is about 2.63uH. If the coupling were
perfect between the sections, I believe the inductance of the whole
would be about 11.54uH + 2.63uH + 2*sqrt(11.54*2.63)uH = 25.19uH. At
16.32uH for the whole coil, the implied coupling coefficient between
those two sections is only about 0.20, and you need to be careful to
not think of the tapped coil as simply a transformer with a 3:1 turns
ratio, with implied close coupling between the sections. (This also
illustrates why you can short out turns of a tank coil without totally
killing the net inductance...)

I trust if I've hosed the calculation too badly, someone will point
out the error of my ways. ;-)

Cheers,
Tom


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Old November 10th 08, 09:30 PM posted to rec.radio.amateur.homebrew
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First recorded activity by RadioBanter: Jul 2006
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Default LC calculation

Hmmm, looks to me like that tapped tank is the oscillator set up for
the super regeneration...

denny ... k8do

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Old November 10th 08, 09:58 PM posted to rec.radio.amateur.homebrew
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Posts: 326
Default LC calculation

On Nov 10, 3:30*pm, Denny wrote:
Hmmm, looks to me like that tapped tank is the oscillator set up for
the super regeneration...

denny ... *k8do


And a second thought is see the same thing on the second stage, where
the top portion of that tank is in series between the tank and the
control grid... Redraw that circuit in your head so that the top
portion of coil is bent over at a right angle to the tank... I wonder
if the grid to cathode capacity is too high for comfort and the
series section of coil is for taming that... We do that for
amplifiers on 10 meters where the plate capacity is too high for
comfortable tuning... A small series coil between the plate and the
tank calms that down...
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