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On Nov 21, 8:24*pm, "NoSPAM" wrote:
"exray" wrote in message ... *In terms of old transmitters from the 20s/30s...In a crystal oscillator I understand the concept of setting the oscillator output tank to favor the harmonic from the crystal. *(Stop me if I'm wrong already...) *But in a doubling amplifier stage am I counting on having enough harmonic content at the input or am I creating the harmonic with the non-linearity of the amplifier? *TIA *-Bill *WX4A Hi Bill. Remember that single ended frequency multiplier stages are usually operated in Class-C where the nonlinear operation of the stage produces the harmonics. *In a Class-C stage, the grid (of the tube since we are talking about vintage transmitters) is biased such that the plate current only flows in short pulses. *The narrower the pulse width, the greater the harmonic generation of the stage. *If you look in the old RCA Transmitting Tube Manual, there is a design procedure where the "conduction angle" of the tube is chosen for proper harmonic generation. Frequency doubling is unique in that two Class-B stages may be used in a push-push arrangement. *Here the grids are driven in push-pull while the plates are connected together in parallel. *The resulting waveform will essentially be the equivalent of full-wave rectification of the input signal. *Without going into Fourier series, the resultant waveform only contains even harmonics of the input signal while the fundamental driving frequency is cancelled out. Fortunately I was already a ham operator when my high school math class taught Fourier series *. *I immediately saw the practical value of this mathematical concept and it made good sense to me. *Your question is a good one and reading some of the tutorials on Fourier series (do a Google search) will be very useful to your understanding of harmonic generation and intermodulation distortion. *I hope that my simple explanation will start you in your own exploration. * * 73, *Barry L. Ornitz * WA4VZQ * More years ago that I care to admit! *:-) Wow, there's a name I haven't seen for a while. I must be frequenting the wrong groups. I was just thinking about you a couple days ago. Hi Barry! More about what Barry wrote: in the limit as the conduction angle goes to zero and you generate a very narrow pulse of current, the harmonics end up all the same amplitude. That's for an impulse of zero width. Unfortunately, given limited amplitude of the current in that very narrow pulse, the total energy becomes small. As you widen the pulse, you'll see that the "comb" of harmonics no longer has constant amplitude, but the amplitudes as you go up the "comb" (higher in frequency)drop, and there will be a frequency at which they go to zero, and then increase again (and go to zero again, and increase again). The magnitudes follow a sin(x)/x shape, for perfectly rectangular pulses. This becomes interesting for a the design of frequency multiplier stages: if for example you want to get x4 out of a stage you better NOT run it at a conduction angle that results in nulling of the fourth harmonic! I think I was bit by this a time or two in my youth when I didn't understand this. (I'm working on something right now where I want that comb of harmonics to be all very nearly equal amplitude up to about 100MHz, and that tells me how narrow the pulse must be.) Cheers, Tom |
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