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![]() "Jeff Johnson" wrote in message ... "amdx" wrote in message ... "Jeff Johnson" wrote in message ... "amdx" wrote in message ... Several years ago while making inductors for tuning a class E amplifier we end up with a 4-1/2 turn inductor. The inductor used a 3F3 potcore, gapped I think, but it has been awhile. The inductor was driven hard but below saturation. The problem; the 1/2 turn got HOT. Four turns or five turns were ok. My physicist friend had an EE verify the problem 2000 miles away. So, can anyone tell me why 1/2 turn would make such a difference in the heating? Thanks, MikeK Resonance? (I assume by 1/2 you mean the 4.5 inductor?) Yes, a 4 and 1/2 turn inductor had the 1/2 turn overheat. huh? The half turn and the other turns were ok? This is impossible!?!?! One has the same current through the whole coil and if the wire was uniform then it should heat heally well. Not only that copper is a good heat conductor so if the 1/2 turn was heating up then he heat should spread pretty quickly. This assumes everything else is uniform along the coil. Something has to be going on that your not telling us? Ideally the heat should be uniformly distributed along the coil. By "HOT" I assume you mean much much hotter than the other coils? Heat is generated by the current, is it not? and the current should be uniform throughout the wire? The resistance of the wire itself should also be uniform. This suggests that the heat dissipated per unit length is independent of position. Were both ends hot? If not then something else is going on. Because you are saying the .5 end of a 4.5 coil got HOT. Yet which end? the 4.5 coil has two .5 ends and should in theory be symmetric and hence both get equally HOT. If they wern't then something is aloof. I got some confirmation from my collaborator, The 1/2 turn as were describing it was the LAST 1/2 turn wound on the bobbin. MikeK |
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