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August 29th 03, 11:34 PM

Mike Silva

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wrote in message . ..
It seems that the formula should be adjusted to account
for the conduction angle, e.g. Rl should be smaller by at
least a factor of 2 to compensate for the conduction
angle. What am I missing?

More current is flowing thru the transistor when conducting than would normally
be used if class-A ? ... this would average out because it's being pulsed rather
than continuous.

And it's reasonable to expect higher current in the pulse than Ohm's
Law would give, because the pulse has a whole bunch of energy in
harmonics, for which the load impedance is lower (the load C reactance
being lower). Since the harmonic content of the pulse goes up as the
conduction angle gets smaller, it makes sense that the average current
through the whole cycle would be somewhat independent of conduction
angle.

Just don't ask me to prove it! ;-)

73,
Mike, KK6GM

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