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"Reg Edwards" wrote in message ...
According to Fourier, at some mark-space ratios of a square wave certain harmonics may be missing from the spectrum. Just generate a a train of very short sharp pulses from the oscillator and you will find all the harmonics are present allbeit with reducing amplitudes. A single transistor should do the job. The inverse of the duty cycle. For a square wave 1:1 M/S = 1/2 duty and all harmonics divisble by 2 are absent. For duty 1/5, fifth harmonic (and multiples)are absent. |
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