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Assuming you have edges quite a bit shorter than the period, it's easy
to see what pulse widths you want to avoid to maximize the 5th: don't let 5*pi*width/period be an integer multiple of pi. So avoid width/period = 1/5, 2/5, 3/5 or 4/5. 2/5 and 3/5 (40% and 60%) are not all that far from 50%. There are lots of ways to get 50% (or close to it). One is to slow the edges a bit, and put the result into a Schmitt trigger with adjustable DC level; the DC level will then adjust the period. You can servo the DC level with an integrator tied to the output and referenced to (v(high)+v(low))/2, for high accuracy. Maybe that's too complicated, though, if you want things small. Note that by not causing dissipation of the fundamental or other harmonics, a multiplier can be considerably more efficient than indicated by the percentage available power in the selected harmonic. In other words, don't put a filter on a logic output that shorts out the fundamental, but rather one that looks like an open circuit to the fundamental, etc. Cheers, Tom Paul Burridge wrote in message . .. On Fri, 12 Mar 2004 16:08:15 +0000, John Woodgate wrote: I read in sci.electronics.design that Reg Edwards wrote (in et.com) about 'Extracting the 5th Harmonic', on Fri, 12 Mar 2004: According to Fourier, at some mark-space ratios of a square wave certain harmonics may be missing from the spectrum. For a waveform like this (use Courier font): _____ / \ / _____/ \____________/ with rise-time f, dwell time d, fall time r and period T, the harmonic magnitudes are given by: Cn = 2Aav{sinc(n[pi]f/T)}{sinc(n[pi][f+d]/T)}{sinc(n[pi][r-f]/T)}, where sinc(x)= {sin(x)}/x There seems to be a number of opportunities for a harmonic to 'hide' in a zero of that function. Great. So without a spectrum analyser there's no way to tell? If I examine the output of the multiplier, it's very messy. There's a dominant 3rd harmonic alright (my frequency counter resolves it without difficulty) but the scope trace reveals a number of 'ghost traces' of different frequencies and amplitudes co-incident with the dominant trace. All rather confusing. I suppose the only answer is to build Reg's band pass filter and stick it between the inverter output and the multiplier input? shrug |
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