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Old December 11th 04, 07:39 PM
Avery Fineman
 
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In article , Paul Burridge
writes:

On 09 Dec 2004 19:12:18 GMT, (Avery Fineman)
wrote:

Of course the resistor lead contribute some inductance. In fact,
most of it. However that inductance is directly calculable based
on old, available data. What remains is the resistor body itself.
A very quick approximation of that body would be to get a scrap
of kitchen aluminum foil and wrap it tightly around the body with
the overlap tight around the leads to make contact. [won't make
much difference because the body, being larger in diameter than
the leads, will have much less inductance than those leads]


Sorry, Len, I stand to be corrected (no doubt) but surely this way of
shorting the ends together is going to make matters much worse? Aren't
you going to end up with a significant amount of capacitance between
your outer foil and the inner spiral of resistive film? Isn't that
going to just throw another complex variable into the mix and probably
completely change the resistors SRF?


Paul, don't kick yourself after reading this, but shorting out the body
with foil will put a conductor in contact with BOTH ends of the
resistor body. :-)

I mentioned that only in passing since it isn't necessary to do in order
to find out anything significant.

Finding a "self resonant frequency" involves doing several
measurements of the total R, C, and L of the device, finding the
complex R and X at each, then plotting that (a Smith Chart will do
it nicely) to see the skew shape of the curve as compared to a
perfect resistor (a single point on a Smith Chart). You will have to
work out the SRF yourself based on that information; that is going
to vary with each specified R value, film type, and the kind of laser
trimming (or whatever) is done to get the DC/low-frequency R value
precise through a film spiral or gouging or whatever. Not needed.

If you just measure the device with a bridge/instrument yielding the
complex impedance or admittance, you just apply that to the
circuit taking the device and be done with it. You will have to allow
for some adjustment in the circuit itself to compensate for the
device characteristics (whatever they come out to be).

An analytical model of the resistor is an R component in series
with an L component (due to any spiral of film, if any, plus the
length/diameter of the resistor body), but that has fringing capacity
between the ends of the leads inserted into the body...that capacity
being in parallel to the series R-L connection. You can estimate
that and do a paper exercise to see the effect for jollies...or just
skip it, use the device measurements to base the overall model as
it applies to the circuit and go on with the project.

The effect, if any, is going to be minimal with 1/4 Watt or smaller
resistors at VHF on up to low UHF bands. Nothing to worry about
provided the leads themselves follow the usual "short as possible"
rule.

One can go nuts on the intellectual paper exercise and about all
it is good for is mumbling-bragging over glasses at the local pub. :-)




 
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