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hi. it's not dB, it's dBm and it's a measure of power. the diode mixer has a finite input resistance (read also impedance). as such a voltage applied to its input causes power to be generated and consumed there. 0 dBm is defined to be 1mW of power into 50 ohms. 7dBm equates to 5mW of power into a load of 50 ohms. this amounts to 500mV RMS, or approximately 1.5 volts PTP across 50 ohms. so you have to produce 5 mW of power to drive a regular DBM . there are also special ones requiring up to 50 mW or more for proper performance. Hope it helps: Saandy 4Z5KS wrote: hello, can someone please explain me, what does it mean that DBM diode ring mixer expects +7dB from BFO? I do understand that from BFO comes out some peak-to-peak voltage (2.2 volts for example). But how does it scale to +7dB? thanks |
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