In article , "Robert" writes:

"Clint" rattlehead@computronDOTnet wrote

[ transmitting a 6 mega-pixel image]

I never claimed you COULD send that with CW.

Well, actually, you _could_. I don't have all the tech stuff handy
to determine just how large a 6 mega-pixel 24-bit color image would actually
_be_, so let's just call it a 6 megabyte file, making it, what, 48 million
bits? Now, how many bits in a 'word' of Morse, average? A dozen, maybe? So,
sending at, let's say, 20 wpm gives us a hypothetical bit-rate of 240
bits/min or 4 bits/sec, so we come out with a mere 12 million seconds to
transmit the image (I _swear_ I did not intend for that answer to come out
that simple!).
It would only take 138.88 days.....


Ah, but you forget an important step in the analysis!

One picture is worth a thousand words. Therefore, the time required to send a
"Morse picture" at 20 wpm is equal to 1,000/20 = 50 minutes with no
compression.

73 de Jim, N2EY

(N2EY) wrote in message ...
In article , "Robert" writes:

"Clint" rattlehead@computronDOTnet wrote

[ transmitting a 6 mega-pixel image]

I never claimed you COULD send that with CW.

Well, actually, you _could_. I don't have all the tech stuff handy
to determine just how large a 6 mega-pixel 24-bit color image would actually
_be_, so let's just call it a 6 megabyte file, making it, what, 48 million
bits? Now, how many bits in a 'word' of Morse, average? A dozen, maybe? So,
sending at, let's say, 20 wpm gives us a hypothetical bit-rate of 240
bits/min or 4 bits/sec, so we come out with a mere 12 million seconds to
transmit the image (I _swear_ I did not intend for that answer to come out
that simple!).
It would only take 138.88 days.....


Ah, but you forget an important step in the analysis!

One picture is worth a thousand words. Therefore, the time required to send a
"Morse picture" at 20 wpm is equal to 1,000/20 = 50 minutes with no
compression.

73 de Jim, N2EY

So get going with your grossly incomplete picture.

In article ,
(Brian) writes:

Ah, but you forget an important step in the analysis!

One picture is worth a thousand words. Therefore, the time required to send
a
"Morse picture" at 20 wpm is equal to 1,000/20 = 50 minutes with no
compression.

73 de Jim, N2EY

So get going with your grossly incomplete picture.

Brian, give it up. The PCTA electrical engineer can't understand that
picture elements are not included in the International Morse Code
character list. He can't be brought into the new millennium and all
the present-day technology of modern electronics.