"Brian" wrote in message
om...
"Keyboard In The Wilderness" wrote in message
news:JhiKb.46924$m83.10369@fed1read01...
Someone wrote;
That and wondering what a CW signal Bandwidth was in the first
place.
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From the ARRL License Manual 1976:

CW Bandwidth = wpm X 4
"With proper shaping, the necessary keying bandwidth is equal to 4
times the speed in words per minute for International Morse Code;
e.g. at 25 words per minute, the bandwidth is approximately 100 cycles.
e.g., 40 WPM = approximately 160 Hz"

Does the ARRL License Manual of 1976 address Farnsworth code and
bandwidth?

The Farnsworth approach isn't even used for faster code speeds like 40wpm so
it is a moot point. However the calculation method would be to use the
character speed as the parameter in the calculation not the "effective word
speed" that is created by increasing the space between characters.

Dee D. Flint, N8UZE