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On Feb 8, 4:40*pm, wrote:
Thanks for that Lamont. The device is a transceiver and the power usage on: Transmit is 850VA and on Receive is 210VA The result you and my other friend get (which is the same) seems enormous. John Plimmer, Montagu, Western Cape Province, South Africa South 33 d 47 m 32 s, East 20 d 07 m 32 s RX Icom IC-756 PRO III with MW mods Drake SW8 & ERGO software Sony 7600D, GE SRIII, Redsun RP2100 BW XCR 30, Sangean 803A. Antenna's RF Systems DX 1 Pro Mk II, Datong AD-270 Kiwa MW Loop, PAORDT Roelof mini-whiphttp://www.dxing.info/about/dxers/plimmer.dx On Feb 9, 12:17*am, "The Shadow" wrote: wrote in message ... I would be grateful for the advice of one of our technically minded members: The new radio I have coming merely states it's power consumption as 210VA, as it is a multivoltage radio. What consumption in watts/amps does this translate to at 240 volts AC mains? Also. if I used an inverter to drive it off a 12 volt DC battery, what would the power consumption in amps then be? POWER CONSUMPTION IS IN WATTS NOT AMPS A friend who helped me wrote: Watts = Volts * Amperes so 210VA = 210 Watts NOT TRUE - WATTS = V*A*COSINE OF THE PHASE ANGLE 210 Watts means 210 / 240 Amps which is .875 Amps. If you want to use a 12V battery, 210 Watts means 210 / 12 Amps or 17.5 Amps. This assumes the AC supply is as efficient as the DC supply. It won't actually be quite as efficient, so you're likely to need fewer Amps, maybe 14 or 15 but that's a guess. Maybe you can ask as the DC current depends on their design which is not known to us yet. Those numbers look very high to me. I suspect they've made a little mistake. I replied: it does seem very high to me for 210VA. at 240 volts AC mains. As just a poor guess I would estimate 0.5 amps at 240 volts AC mains and 8 amps at 12v DC but I cannot calculate it. _______________________________ So what do the experts out there think? Would be grateful for your help. WHAT KIND OF RADIO IS IT -- 210 VA IS TOO HIGH FOR A RECEIVER -- MORE LIKE A TRANSCEIVER Volt-Amperes VA usually refers to AC apparent power - it takes into account reacive components see URL:http://www.allaboutcircuits.com/vol_2/chpt_11/2.html True power in an AC circuit is IxE if there are no reactive components otherwise it is I squared R or ExI x Cos theta So True Power (Watts) does not equal VA unless the circuit is purely resistive. Assuming your device is resisive (or near to it) then see URL:http://www..sengpielaudio.com/calculator-ohm.htm which indeed gives 0.875 Amperes Again usinghttp://www.sengpielaudio.com/calculator-ohm.htm which indeed gives 17.5 Amperes Allowing for efficiencies and loss etc I would allow for 20 to 25 amperes Most inverters will specify a power rating Lamont- Hide quoted text - - Show quoted text -- Hide quoted text - - Show quoted text - JP, Message - "New Radio in South Africa" http://groups.google.com/group/rec.r...866d6ff18a951c I am getting another RX, an Icom IC-7700 see brochure at: http://www.ab4oj.com/icom/ic7700/IC-7700_pre.pdf ICOM IC-7700 - http://www.rigpix.com/icom/ic7700.htm Minute-Video - http://www.youtube.com/watch?v=eJS0z-Y5hKc You are talking about your new Icom IC-7700 Transceiver. IC7700 - http://www.ab4oj.com/icom/ic7700/main.html Icom IC-7700 Transceiver - Rated Power Consumption : Tx Max. power 800 VA {Transmit 'Power Output' Mode} Rx Stand-by 200 VA (typ.) {Receive Only Listening Mode} Max. Audio 210 VA (typ.) {Receive Only Maximum Audio Output} 12 VOLT DC POWER SOURCE / SUPPLY - = FOR RECEIVE ONLY USE = - [NO MIC CONNECTED / NO TRANSMITTING] 240 Volts divide by 12 Volts = 20 f# 0.875 Amperes @ 240 Volts 0.875 Amperes times 20 f# = 17.5 Amperes @ 12 Volts Add a 15% Power Supply Safety Factor : 17.5 Amperes times 15% (0.15) = 2.63 Amperes 17.5 Amperes plus 2.63 Amperes = 20.13 Amperes Requires as a Minimum a 12 Volt DC Power Supply that is Rated at 20+ Amperes. {25 Amps would be better.} FWIW - Going from 240 VAC to 120 VAC the 0.875 Amperes would become 1.75 Amperes {2 Amps} Again these Rough Numbers are for "Receive Only" Use -NOT- Transmit. ~RHF |
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