On Sun, 10 Apr 2005 15:45:35 -0400, dxAce
wrote:



-=jd=- wrote:

On Sun 10 Apr 2005 01:58:30p, dxAce wrote in
message :



David wrote:

On Sun, 10 Apr 2005 13:04:13 -0400, dxAce
wrote:



Brian Hill wrote:

"dxAce" wrote in message
...


Brian Hill wrote:

"Don Forsling" wrote in message
...
Yes, I'm iold, tired, lazy and forgetful. That said, can
someone
remind
me
of the formula for calculating the length of a full-wave
antenna wire
if
the
frequency is known (think whip and a frequency of 160.890
mhz).

Your ant would be 2.9088196904717508856983031885139. So about 2
15/16 or
so
inches. I wouldn't recamend a dipole config. LOL!!!

Are you sure about that length? A dipole at 144 MHz is much, much
larger
than
that, so something at 160 MHz or so isn't going to be that much
smaller.

dxAce
Michigan
USA



I don't know what the logistics of VHF and above would be but the
math says it's so. I'll have to refer to my ARRL handbook. I'm a HF
guy and the math works for that spectrum.

A half wavelength dipole for 160.890 MHz would be be right about 3.06
feet long.

This is found by dividing 492 by the frequency in MHz.

dxAce
Michigan
USA


Meters times megaHertz equals 300.

300 what?

dxAce
Michigan
USA



I think he mis-typed and meant to say, "3 Meters times 100 megaHertz equals
300 meterHertz."

I have no idea what he was trying to say!

dxAce
Michigan
USA

Man, y'all are ****in' dense. Would you believe Arnie Coro?

''...for example, let's say you want to pick up Radio Havana Cuba's
ever popular 9820 kiloHertz frequency... First let's calculate 9820
kiloHertz 's wavelength... easy too... Wavelength in meters, equals
the constant 300, divided by the frequency in megaHerz... which is 300
divided by 9.820, and that equals... let's see 30.54 meters
wavelength...''